(a)
Interpretation:
The electronic configuration of the element with
Concept introduction:
The electronic configuration of an element is the distribution of the electrons in an atom of the element into atomic orbitals. It is known that the atomic orbitals are designated as 1s, 2s, 2p, 3s, etc depending on their energy and distance from the nucleus. These atomic orbitals accommodate the electrons orbiting around the nucleus.
Answer to Problem 9E
The electronic configuration of the element with atomic number 13 is 1s22s22p63s23p1
Explanation of Solution
The atomic orbital closest to the nucleus is the 1s orbital followed by the 2s orbital, then 2p and so on. Each electronic orbital can hold maximum 2 electrons. Thus, both the 1s and 2s orbitals can hold 2 electrons each. There are 3 p orbitals depending on their orientations with respect to the nucleus and each p orbital can hold 2 electrons at maximum. Thus, the 2p and 3p orbitals can accommodate 6 electrons in total.
The energy of the orbitals is guided by the principal quantum number, n of the orbital. The orbital having n = 1 has the lowest energy (closest to the nucleus) and the energy of the orbitals increases with increasing n values.
Further, while filling up the atomic orbitals, it must be noted that unless a lower energy atomic orbital is completely filled with electrons, the next higher energy orbital will not be filled up with an electron.
The element with atomic number 13 has 13 electrons in total (the atomic number is equal to the number of electrons contained in the neutral atom). The first two electrons must go in the 1s orbital followed by 2 electrons in the 2s orbital. The next available orbital is the 2p orbital which can hold 6 electrons. The remaining 3 electrons go into the 3s and 3p orbitals. This will give the electronic configuration stated above (the superscripts denote the number of electrons in the atomic orbitals).
(b)
Interpretation:
The number of valence electrons in the element with atomic number 13 needs to be determined.
Concept introduction:
The valence electrons are defined as the electron occurring in the outermost, highest energy orbitals of the element. Since a principal shell (defined by quantum number n) can have more than 1 sub-shell or atomic orbital, hence, all the electrons occurring in the highest shell are considered as valence electrons.
Answer to Problem 9E
The number of valence electrons in the element with atomic number 13 is 3.
Explanation of Solution
It has already been stated above that the highest energy shell in the element with atomic number 13 is the third shell (n = 3). Since the third shell has three available atomic orbitals (s, p and d) out of which the s and the p orbitals are occupied here, hence, the sum total of the electrons in the third shell is the number of valence electrons in the element.
(c)
Interpretation:
The number of core electrons in the element with atomic number 13 needs to be determined.
Concept introduction:
The core electrons are defined as the electrons occurring in the inner, lower energy orbitals of the element. Since a principal shell (defined by quantum number n) can have more than 1 sub-shell or atomic orbital, hence, all the electrons occurring in the inner shells are considered as core electrons.
Answer to Problem 9E
The number of core electrons in the element with atomic number 13 is 10.
Explanation of Solution
The valence electrons of the element having atomic number 13 occur in the third shell and there are 3 valence electrons. Thus, the remaining electrons must be the core electrons and a simple subtraction determines the number of core electrons as 10.
Chapter U1 Solutions
Living By Chemistry: First Edition Textbook
Additional Science Textbook Solutions
Human Biology: Concepts and Current Issues (8th Edition)
Concepts of Genetics (12th Edition)
Applications and Investigations in Earth Science (9th Edition)
College Physics: A Strategic Approach (3rd Edition)
Human Physiology: An Integrated Approach (8th Edition)
Campbell Biology: Concepts & Connections (9th Edition)
- Draw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl C O Substitution will not occur at a significant rate. Explanation Check + O-CH3 Х Click and drag to start drawing a structure.arrow_forward✓ aw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. C Cl HO–CH O Substitution will not occur at a significant rate. Explanation Check -3 ☐ : + D Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Cearrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Don't used hand raiting and don't used Ai solutionarrow_forwardDetermine whether the following reaction is an example of a nucleophilic substitution reaction: Br OH HO 2 -- Molecule A Molecule B + Br 义 ollo 18 Is this a nucleophilic substitution reaction? If this is a nucleophilic substitution reaction, answer the remaining questions in this table. Which of the reactants is referred to as the nucleophile in this reaction? Which of the reactants is referred to as the organic substrate in this reaction? Use a ŏ + symbol to label the electrophilic carbon that is attacked during the substitution. Highlight the leaving group on the appropriate reactant. ◇ Yes O No O Molecule A Molecule B Molecule A Molecule B टेarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Show work..don't give Ai generated solutionarrow_forwardPheromone G of the maize stalk borer, chilo partelus, can be synthesized based on the partial scheme shown below. Complete the scheme by identifying the structures of the intermediate compounds A, B, C, D, E, F and pheromone G. Indicate stereochemistry where relevantarrow_forwardQ8: Draw the resonance structures for the following molecule. Show the curved arrows (how you derive each resonance structure). Circle the major resonance contributor. одarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY