![Living By Chemistry: First Edition Textbook](https://www.bartleby.com/isbn_cover_images/9781559539418/9781559539418_largeCoverImage.gif)
(a)
Interpretation:
The chemical formulas for sodium silicate, sodium chlorite and sodium bicarbonate are to be written.
Concept introduction:
In some ionic compound, the ions are composed of more than one atom. These are called polyatomic ions and the compound is known as polyatomic compound. The entire cluster of atoms shares the charge on a polyatomic ion.
To write the chemical formulas of such polyatomic compounds, one must apply the rule of zero charge which states that charges on metal cations and polyatomic anions must add up to zero.
![Check Mark](/static/check-mark.png)
Answer to Problem SIV6RQ
- Sodium silicate - Na2SiO3
- Sodium chlorite - NaClO2
- Sodium bicarbonate - NaHCO3
Explanation of Solution
When there is more than one of the same polyatomic ion in a formula, the ion is enclosed in parenthesis and a subscript number is written indicating the number of ions in the compound.
- Sodium silicate - Na2SiO3 - The polyatomic ion here is silicate (SiO32-). Sodium has + 1 charge so 2 sodium atoms will combine with 1 silicate ion. Hence, sum of charges becomes zero. The formula for this compound is Na2SiO3.
- Sodium chlorite - NaClO2 - The polyatomic ion here is chlorite (ClO2-) and sodium has + 1 charge so 1 sodium atom will combine with 1 chlorite ion. Hence, sum of charges becomes zero. The formula for this compound is NaClO2.
- Sodium bicarbonate - NaHCO3 - The polyatomic ion here is bicarbonate (HCO3-). Sodium has 2 + charge so 1 sodium atom will combine with 1bicarbonate ion. Hence, sum of charges becomes zero. The formula for this compound is NaHCO3.
(b)
Interpretation:
The chemical formulas for calcium silicate, calcium chlorite and calcium bicarbonate are to be written.
Concept introduction:
In some ionic compound, the ions are composed of more than one atom. These are called polyatomic ions and the compound is known as polyatomic compound. The entire cluster of atoms shares the charge on a polyatomic ion.
To write the chemical formulas of such polyatomic compounds, one must apply the rule of zero charge which states that charges on metal cations and polyatomic anions must add up to zero.
![Check Mark](/static/check-mark.png)
Answer to Problem SIV6RQ
- Calcium silicate - CaSiO3
- Calcium chlorite - Ca(ClO2)2
- Calcium bicarbonate - Ca(HCO3)2
Explanation of Solution
When there is more than one of the same polyatomic ion in a formula, the ion is enclosed in parenthesis and a subscript number is written indicating the number of ions in the compound.
- Calcium silicate - Ca2SiO3 - The polyatomic ion here is silicate (SiO32-). Calcium has + 2 charges so 1 calcium atom will combine with 1 silicate ion. Hence, sum of charges becomes zero. The formula for this compound is Ca2SiO3.
- Calcium chlorite - Ca(ClO2)2 - The polyatomic ion here is chlorite (ClO2-)Calcium has + 2 charge so 1 calcium atom will combine with 2chlorite ions. Hence, sum of charges becomes zero. The formula for this compound is Ca(ClO2)2.
- Calcium bicarbonate - Ca(HCO3)2 - The polyatomic ion here is bicarbonate (HCO3-). Calcium has + 2 charges so 1 calcium atom will combine with 2bicarbonate ion. Hence, sum of charges becomes zero. The formula for this compound is Ca(HCO3)2.
Chapter U1 Solutions
Living By Chemistry: First Edition Textbook
Additional Science Textbook Solutions
Microbiology: An Introduction
Anatomy & Physiology (6th Edition)
Applications and Investigations in Earth Science (9th Edition)
Chemistry: Structure and Properties (2nd Edition)
Biology: Life on Earth with Physiology (11th Edition)
Cosmic Perspective Fundamentals
- 1. Consider a pair of elements with 2p and 4p valence orbitals (e.g., N and Se). Draw their (2p and 4p AO's) radial probability plots, and sketch their angular profiles. Then, consider these orbitals from the two atoms forming a homonuclear л-bond. Which element would have a stronger bond, and why? (4 points)arrow_forwardWrite the reaction and show the mechanism of the reaction. Include the mechanism for formation of the NO2+ 2. Explain, using resonance structures, why the meta isomer is formed. Draw possible resonance structures for ortho, meta and para.arrow_forwardNonearrow_forward
- 3. A molecular form of "dicarbon", C2, can be generated in gas phase. Its bond dissociation energy has been determined at 599 kJ/mol. Use molecular orbital theory to explain why energy of dissociation for C₂+ is 513 kJ/mol, and that for C2² is 818 kJ/mol. (10 points)arrow_forward9.73 g of lead(IV) chloride contains enough Cl- ions to make ____ g of magnesium chloride.arrow_forward6. a) C2's. Phosphorus pentafluoride PF5 belongs to D3h symmetry group. Draw the structure of the molecule, identify principal axis of rotation and perpendicular (4 points) b) assume that the principal axis of rotation is aligned with z axis, assign symmetry labels (such as a1, b2, etc.) to the following atomic orbitals of the P atom. (character table for this group is included in the Supplemental material). 3s 3pz (6 points) 3dz²arrow_forward
- 2. Construct Lewis-dot structures, and draw VESPR models for the ions listed below. a) SiF5 (4 points) b) IOF4 (4 points)arrow_forward5. Complex anion [AuCl2]¯ belongs to Doh symmetry point group. What is the shape of this ion? (4 points)arrow_forward4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward
- 7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forwardcan someone answer the questions and draw out the complete mechanismarrow_forwardPlease help, draw and me the proper mechanisms.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)