Concept explainers
(a)
Interpretation:
Lewis dot structure of CF4 must be drawn.
Concept Introduction :
Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.
(a)
Answer to Problem 5E
Lewis dot structure of CF4 is given below.
.
Explanation of Solution
C has 4 valence electrons. F has 7 valence electrons. Thus one carbon is covalently bonded with 4 F atoms. There are three lone pairs of electrons on each F atom. Accordingly Lewis structure is shown as follows:
(b)
Interpretation:
Lewis dot structure of CH3Cl must be drawn.
Concept Introduction :
Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.
(b)
Answer to Problem 5E
Lewis dot structure of CH3Cl is given below.
.
Explanation of Solution
C has 4 valence electrons. Cl has 7 valence electrons. H has one valence electron. Thus one carbon is covalently bonded with 3 H atoms and 1 Cl. There are three lone pairs of electrons on Cl atom. Accordingly Lewis structure is shown as follows:
(c)
Interpretation:
Lewis dot structure of SiCl2H2 must be drawn.
Concept Introduction :
Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.
(c)
Answer to Problem 5E
Lewis dot structure of SiCl2H2 is given below.
.
Explanation of Solution
Si has 4 valence electrons, Cl has 7 valence electrons and H has one valence electron. Thus one carbon is covalently bonded with 2 H atoms and 2 Cl atoms. There are three lone pairs of electrons on Cl atom. Accordingly Lewis structure is shown as follows:
(d)
Interpretation:
Lewis dot structure of CH3OH must be drawn.
Concept Introduction :
Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.
(d)
Answer to Problem 5E
Lewis dot structure of CH3OH is given below:
.
Explanation of Solution
C has 4 valence electrons. O has 6 valence electrons. H has one valence electron. Thus one carbon is covalently bonded with 3 H atoms and 1 O atom. The O atom is bonded with central carbon atom and one hydrogen atom. There are 2 lone pairs of electrons on O atom. Accordingly, Lewis structure is shown as follows:
(e)
Interpretation:
Lewis dot structure of HOCl must be drawn.
Concept Introduction :
Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.
(e)
Answer to Problem 5E
Lewis dot structure of HOCl is given below.
.
Explanation of Solution
O has 6 valence electrons, Cl has 7valence electrons and H has one valence electron. Thus one central O is covalently bonded with 1 H atoms and 1 Cl atom. There are 2 lone pairs of electrons on O atom and 3 lone pairs of electrons on Cl atom. Accordingly Lewis structure is shown as follows
(f)
Interpretation:
Lewis dot structure of CH3NH2 must be drawn.
Concept Introduction :
Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.
(f)
Answer to Problem 5E
Lewis dot structure of CH3NH2 is given below.
.
Explanation of Solution
C has 4 valence electrons, N has 5 valence electrons and H has one valence electron. Thus one central C is covalently bonded with 3 H atoms and 1 N atom. N atom is covalently bonded with central C atom and two hydrogen atoms. There are 2 lone pairs of electrons on N atom. Accordingly Lewis structure is shown as follows:
Chapter U2 Solutions
Living By Chemistry: First Edition Textbook
Additional Science Textbook Solutions
Cosmic Perspective Fundamentals
Applications and Investigations in Earth Science (9th Edition)
Introductory Chemistry (6th Edition)
Biology: Life on Earth with Physiology (11th Edition)
Biology: Life on Earth (11th Edition)
Microbiology: An Introduction
- Please provide steps to work for complete understanding.arrow_forwardPlease provide steps to work for complete understanding.arrow_forwardIdentify the Functional Groups (FG) in the following molecules. Classify C atoms as tertiary, 30, or quaternary 40. Identify secondary 20 and tertiary, 30 hydrogen atoms. Please provide steps to undertand each labeling.arrow_forward
- Identify the Functional Groups (FG) in the following molecules. Classify C atoms as tertiary, 30, or quaternary 40. Identify secondary 20 and tertiary, 30 hydrogen atoms. Please provide steps to undertand each labeling.arrow_forwardIdentify the Functional Groups (FG) in the following molecules. Classify C atoms as tertiary, 30, or quaternary 40. Identify secondary 20 and tertiary, 30 hydrogen atoms. Please provide steps to undertand each labeling.arrow_forwardIdentify the Functional Groups (FG) in the following molecules. Classify C atoms as tertiary, 30, or quaternary 40. Identify secondary 20 and tertiary, 30 hydrogen atoms. Please provide steps to undertand each labeling.arrow_forward
- A certain chemical reaction releases 24.7 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of reactant will produce 1460. J of heat? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols. mass M 0.0 x μ 00 1 Garrow_forwardPlease don't used hand raiting and don't used Ai solutionarrow_forwardDon't used Ai solutionarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY