Living By Chemistry: First Edition Textbook
Living By Chemistry: First Edition Textbook
1st Edition
ISBN: 9781559539418
Author: Angelica Stacy
Publisher: MAC HIGHER
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Concept explainers

Question
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Chapter U2.5, Problem 5E

(a)

Interpretation Introduction

Interpretation:

Lewis dot structure of CF4 must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

(a)

Expert Solution
Check Mark

Answer to Problem 5E

Lewis dot structure of CF4 is given below.

. Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  1

Explanation of Solution

C has 4 valence electrons. F has 7 valence electrons. Thus one carbon is covalently bonded with 4 F atoms. There are three lone pairs of electrons on each F atom. Accordingly Lewis structure is shown as follows:

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  2

(b)

Interpretation Introduction

Interpretation:

Lewis dot structure of CH3Cl must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

(b)

Expert Solution
Check Mark

Answer to Problem 5E

Lewis dot structure of CH3Cl is given below.

. Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  3

Explanation of Solution

C has 4 valence electrons. Cl has 7 valence electrons. H has one valence electron. Thus one carbon is covalently bonded with 3 H atoms and 1 Cl. There are three lone pairs of electrons on Cl atom. Accordingly Lewis structure is shown as follows:

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  4

(c)

Interpretation Introduction

Interpretation:

Lewis dot structure of SiCl2H2 must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

(c)

Expert Solution
Check Mark

Answer to Problem 5E

Lewis dot structure of SiCl2H2 is given below.

.

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  5

Explanation of Solution

Si has 4 valence electrons, Cl has 7 valence electrons and H has one valence electron. Thus one carbon is covalently bonded with 2 H atoms and 2 Cl atoms. There are three lone pairs of electrons on Cl atom. Accordingly Lewis structure is shown as follows:

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  6

(d)

Interpretation Introduction

Interpretation:

Lewis dot structure of CH3OH must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

(d)

Expert Solution
Check Mark

Answer to Problem 5E

Lewis dot structure of CH3OH is given below:

.

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  7

Explanation of Solution

C has 4 valence electrons. O has 6 valence electrons. H has one valence electron. Thus one carbon is covalently bonded with 3 H atoms and 1 O atom. The O atom is bonded with central carbon atom and one hydrogen atom. There are 2 lone pairs of electrons on O atom. Accordingly, Lewis structure is shown as follows:

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  8

(e)

Interpretation Introduction

Interpretation:

Lewis dot structure of HOCl must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

(e)

Expert Solution
Check Mark

Answer to Problem 5E

Lewis dot structure of HOCl is given below.

.

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  9

Explanation of Solution

O has 6 valence electrons, Cl has 7valence electrons and H has one valence electron. Thus one central O is covalently bonded with 1 H atoms and 1 Cl atom. There are 2 lone pairs of electrons on O atom and 3 lone pairs of electrons on Cl atom. Accordingly Lewis structure is shown as follows

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  10

(f)

Interpretation Introduction

Interpretation:

Lewis dot structure of CH3NH2 must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

(f)

Expert Solution
Check Mark

Answer to Problem 5E

Lewis dot structure of CH3NH2 is given below.

.

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  11

Explanation of Solution

C has 4 valence electrons, N has 5 valence electrons and H has one valence electron. Thus one central C is covalently bonded with 3 H atoms and 1 N atom. N atom is covalently bonded with central C atom and two hydrogen atoms. There are 2 lone pairs of electrons on N atom. Accordingly Lewis structure is shown as follows:

  Living By Chemistry: First Edition Textbook, Chapter U2.5, Problem 5E , additional homework tip  12

Chapter U2 Solutions

Living By Chemistry: First Edition Textbook

Ch. U2.2 - Prob. 3ECh. U2.2 - Prob. 4ECh. U2.2 - Prob. 5ECh. U2.2 - Prob. 6ECh. U2.2 - Prob. 7ECh. U2.3 - Prob. 1TAICh. U2.3 - Prob. 1ECh. U2.3 - Prob. 2ECh. U2.3 - Prob. 3ECh. U2.3 - Prob. 4ECh. U2.3 - Prob. 5ECh. U2.4 - Prob. 1TAICh. U2.4 - Prob. 1ECh. U2.4 - Prob. 2ECh. U2.4 - Prob. 3ECh. U2.4 - Prob. 4ECh. U2.4 - Prob. 5ECh. U2.4 - Prob. 6ECh. U2.4 - Prob. 7ECh. U2.4 - Prob. 8ECh. U2.5 - Prob. 1TAICh. U2.5 - Prob. 1ECh. U2.5 - Prob. 2ECh. U2.5 - Prob. 3ECh. U2.5 - Prob. 4ECh. U2.5 - Prob. 5ECh. U2.5 - Prob. 6ECh. U2.5 - Prob. 7ECh. U2.5 - Prob. 8ECh. U2.5 - Prob. 9ECh. U2.6 - Prob. 1TAICh. U2.6 - Prob. 1ECh. U2.6 - Prob. 2ECh. U2.6 - Prob. 3ECh. U2.6 - Prob. 4ECh. U2.6 - Prob. 5ECh. U2.6 - Prob. 6ECh. U2.6 - Prob. 7ECh. U2.6 - Prob. 8ECh. U2.6 - Prob. 9ECh. U2.6 - Prob. 10ECh. U2.6 - Prob. 11ECh. U2.7 - Prob. 1TAICh. U2.7 - Prob. 1ECh. U2.7 - Prob. 2ECh. U2.7 - Prob. 3ECh. U2.7 - Prob. 4ECh. U2.7 - Prob. 5ECh. U2.8 - Prob. 1TAICh. U2.8 - Prob. 1ECh. U2.8 - Prob. 2ECh. U2.8 - Prob. 3ECh. U2.8 - Prob. 4ECh. U2.8 - Prob. 5ECh. U2.8 - Prob. 6ECh. U2.9 - Prob. 1TAICh. U2.9 - Prob. 1ECh. U2.9 - Prob. 2ECh. U2.9 - Prob. 3ECh. U2.9 - Prob. 4ECh. U2.9 - Prob. 5ECh. U2.9 - Prob. 6ECh. U2.9 - Prob. 7ECh. U2.10 - Prob. 1TAICh. U2.10 - Prob. 1ECh. U2.10 - Prob. 2ECh. U2.10 - Prob. 3ECh. U2.10 - Prob. 4ECh. U2.10 - Prob. 5ECh. U2.10 - Prob. 6ECh. U2.10 - Prob. 7ECh. U2.10 - Prob. 8ECh. U2.10 - Prob. 9ECh. U2.11 - Prob. 1TAICh. U2.11 - Prob. 1ECh. U2.11 - Prob. 2ECh. U2.11 - Prob. 3ECh. U2.11 - Prob. 4ECh. U2.11 - Prob. 5ECh. U2.11 - Prob. 6ECh. U2.11 - Prob. 7ECh. U2.12 - Prob. 1TAICh. U2.12 - Prob. 1ECh. U2.12 - Prob. 2ECh. U2.12 - Prob. 3ECh. U2.12 - Prob. 4ECh. U2.12 - Prob. 5ECh. U2.12 - Prob. 6ECh. U2.12 - Prob. 7ECh. U2.13 - Prob. 1TAICh. U2.13 - Prob. 1ECh. U2.13 - Prob. 2ECh. U2.13 - Prob. 3ECh. U2.13 - Prob. 4ECh. U2.13 - Prob. 5ECh. U2.14 - Prob. 1TAICh. U2.14 - Prob. 1ECh. U2.14 - Prob. 2ECh. U2.14 - Prob. 3ECh. U2.14 - Prob. 4ECh. U2.14 - Prob. 5ECh. U2.14 - Prob. 6ECh. U2.14 - Prob. 7ECh. U2.14 - Prob. 8ECh. U2.15 - Prob. 1TAICh. U2.15 - Prob. 1ECh. U2.15 - Prob. 2ECh. U2.15 - Prob. 4ECh. U2.15 - Prob. 5ECh. U2.15 - Prob. 6ECh. U2.16 - Prob. 1TAICh. U2.16 - Prob. 1ECh. U2.16 - Prob. 2ECh. U2.16 - Prob. 3ECh. U2.16 - Prob. 4ECh. U2.16 - Prob. 6ECh. U2.16 - Prob. 7ECh. U2.17 - Prob. 1TAICh. U2.17 - Prob. 1ECh. U2.17 - Prob. 2ECh. U2.17 - Prob. 3ECh. U2.17 - Prob. 4ECh. U2.17 - Prob. 5ECh. U2.17 - Prob. 6ECh. U2.17 - Prob. 7ECh. U2.17 - Prob. 8ECh. U2.17 - Prob. 9ECh. U2.18 - Prob. 1TAICh. U2.18 - Prob. 1ECh. U2.18 - Prob. 2ECh. U2.18 - Prob. 3ECh. U2.18 - Prob. 4ECh. U2.18 - Prob. 5ECh. U2.18 - Prob. 6ECh. U2.18 - Prob. 7ECh. U2.19 - Prob. 1TAICh. U2.19 - Prob. 1ECh. U2.19 - Prob. 2ECh. U2.19 - Prob. 3ECh. U2.19 - Prob. 4ECh. U2.19 - Prob. 5ECh. U2.19 - Prob. 6ECh. U2.19 - Prob. 7ECh. U2.19 - Prob. 8ECh. U2.19 - Prob. 9ECh. U2.20 - Prob. 1TAICh. U2.20 - Prob. 1ECh. U2.20 - Prob. 2ECh. U2.20 - Prob. 3ECh. U2.20 - Prob. 4ECh. U2.20 - Prob. 5ECh. U2.20 - Prob. 6ECh. U2.20 - Prob. 7ECh. U2.20 - Prob. 8ECh. U2.20 - Prob. 9ECh. U2.21 - Prob. 1TAICh. U2.21 - Prob. 1ECh. U2.21 - Prob. 2ECh. U2.21 - Prob. 3ECh. U2.21 - Prob. 4ECh. U2.21 - Prob. 6ECh. U2 - Prob. SI1RECh. U2 - Prob. SI2RECh. U2 - Prob. SI3RECh. U2 - Prob. SI4RECh. U2 - Prob. SI5RECh. U2 - Prob. SII1RECh. U2 - Prob. SII2RECh. U2 - Prob. SII3RECh. U2 - Prob. SII4RECh. U2 - Prob. SII5RECh. U2 - Prob. SIII1RECh. U2 - Prob. SIII2RECh. U2 - Prob. SIII3RECh. U2 - Prob. SIII4RECh. U2 - Prob. SIII5RECh. U2 - Prob. SIII6RECh. U2 - Prob. SIV1ECh. U2 - Prob. SIV2ECh. U2 - Prob. SIV3ECh. U2 - Prob. SIV4ECh. U2 - Prob. SIV5ECh. U2 - Prob. 1RECh. U2 - Prob. 2RECh. U2 - Prob. 3RECh. U2 - Prob. 4RECh. U2 - Prob. 5RECh. U2 - Prob. 6RECh. U2 - Prob. 7RECh. U2 - Prob. 8RE
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