![Living By Chemistry: First Edition Textbook](https://www.bartleby.com/isbn_cover_images/9781559539418/9781559539418_largeCoverImage.gif)
Concept explainers
(a)
Interpretation :
Shape of ammonia molecule must be predicted.
Concept Introduction :
Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.
Ammonia molecule has total 4 atoms in which N is the central atom.
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem SII2RE
Shape of ammonia molecule is trigonal pyramidal.
Explanation of Solution
The structure of ammonia molecule is represented as follows:
N has total 4 pairs of electrons in the valence shell.
There are three bond pairs and lone pairs of electrons. N atom is sp3 hybridized and thus NH3 has trigonal pyramidal shape due to presence of one lone pair electrons.
b)
Interpretation :
Shape of silicon tetrachloride must be predicted.
Concept Introduction :
Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.
Silicon tetrachloride molecule has total 5 atoms in which Si is the central atom.
b)
![Check Mark](/static/check-mark.png)
Answer to Problem SII2RE
Shape of silicon tetrachloride molecule is tetrahedral.
Explanation of Solution
The structure is represented as follows:
Si has total 4 pairs of electrons in the valence shell.
There are four bond pairs and no lone pairs of electrons. Si atom is sp3 hybridized and thus SiCl4 has tetrahedral shape.
c)
Interpretation :
Shape of hydrogen sulfide must be predicted.
Concept Introduction :
Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.
Hydrogen sulfide molecule has total 3 atoms in which S is the central atom.
c)
![Check Mark](/static/check-mark.png)
Answer to Problem SII2RE
Shape of hydrogen molecule is angular.
Explanation of Solution
The structure of H2S is represented as follows:
S has total 4 pairs of electrons in the valence shell.
There are two bond pairs and two lone pairs of electrons. S atom is sp3 hybridized and thus H2S has angular shape.
d)
Interpretation :
Shape of hydrogen cyanide must be predicted.
Concept Introduction :
Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.
Hydrogen cyanide molecule has total 3 atoms in which C is the central atom.
d)
![Check Mark](/static/check-mark.png)
Answer to Problem SII2RE
Shape of hydrogen cyanide is linear.
Explanation of Solution
The structure is represented as follows:
C has total 4 pairs of electrons in the valence shell.
There are four bond pairs and no lone pairs of electrons. C atom is triple bonded with N and carbon is sp hybridized and thus HCN has linear shape.
e)
Interpretation :
Shape of formaldehyde must be predicted.
Concept Introduction :
Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.
Formaldehyde molecule has total 4 atoms in which C is the central atom.
e)
![Check Mark](/static/check-mark.png)
Answer to Problem SII2RE
Shape of formaldehyde is trigonal planar.
Explanation of Solution
The structure of formaldehyde is represented as follows:
C has total 4 pairs of electrons in the valence shell.
There are four bond pairs and no lone pairs of electrons. C atom is double bonded with O and single bonded with two hydrogen atoms. Carbon is sp2 hybridized and thus CH2N has trigonal planar shape.
Chapter U2 Solutions
Living By Chemistry: First Edition Textbook
Additional Science Textbook Solutions
Campbell Biology (11th Edition)
Introductory Chemistry (6th Edition)
Applications and Investigations in Earth Science (9th Edition)
Campbell Biology in Focus (2nd Edition)
Microbiology with Diseases by Body System (5th Edition)
Organic Chemistry (8th Edition)
- c) 3. Provide a common name for each of the following alcohols. a) a) OH b) OH c) HO b) c) 4. Provide a common name for each of the following compounds. b) OH a) 5 a) Y OH c) OHarrow_forwardUsing the critical constants for water (refer to the table in the lecture slides), calculate the second virial coefficient. Assume that the compression factor (Z) is expressed as an expansion series in terms of pressure.arrow_forward+3413 pts /4800 Question 38 of 48 > Write the full electron configuration for a Kion. © Macmillan Learning electron configuration: ↓ Resources Solution Penalized → Al Tutor Write the full electron configuration for an Fion. electron configuration: T G 6 & 7 Y H כ Y 00 8 hp 9 J K no L 144 P 112 | t KC 47°F Clear ins prt sc delete ] backspace erarrow_forward
- How to solve these types of problems step by step? I'm so confused.arrow_forwardIdentify the expected product of the following Claisen rearrangement. || = IV OV 00000 5 ОН Он Он Он Он || III IV Varrow_forwardCan you please color-code and explain how to solve this and any molecular orbital diagram given? I'm so confused; could you provide baby steps regardless of which problem type they gave me?arrow_forward
- Consider the following structure. OH Esmolol The synthesis of this compound uses a building block derived from either ethylene oxide or epichlorohydrin. 1) Determine which building block was used: | 2) Draw the structure of the nucleophiles that were used along with this building block in the synthesis of the molecule. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. You do not have to consider stereochemistry. Θε {n [arrow_forward< 10:44 5GW 10 Question 7/8 Show Answer Convert 46.0 mm to inches (1 inch = 2.54 cm) 46.0 DAM STARTING AMOUNT 1 cm 1 in 46.0 mm x ☑ 10 mm 10 cm ADD FACTOR DELETE x() X × = 1.81 in = 1 10 Dam ANSWER RESET ១ 2.54 0.0460 mm 10 1000 in 0.001 11.7 m 4.60 18.1 cm 100 1.81 0.394 1 0.1 46.0 0.01 Tap here for additional resourcesarrow_forward< 10:44 Question 6/8 5GW (10 Submit A cake recipe calls for 230.0 mL of buttermilk. How 230.0 many cups is this? DAL STARTING AMOUNT × 1 cups 230.0 mL x = 0.9722 cups 230.0 mL ADD FACTOR DELETE (( ) = 1 cups 230.0 DAE ANSWER RESET ១ 9.722 × 105 0.8706 cups 8.706 × 104 1 L 8.706 × 105 0.9722 quart 10 100 mL 0.001 0.1 6.076 × 103 0.01 9.722 × 104 230.0 0.06076 4 1.0567 1000 6.076 × 104 Tap here for additional resourcesarrow_forward
- < 10:44 Question 6/8 5GW (10 Submit A cake recipe calls for 230.0 mL of buttermilk. How 230.0 many cups is this? DAL STARTING AMOUNT × 1 cups 230.0 mL x = 0.9722 cups 230.0 mL ADD FACTOR DELETE (( ) = 1 cups 230.0 DAE ANSWER RESET ១ 9.722 × 105 0.8706 cups 8.706 × 104 1 L 8.706 × 105 0.9722 quart 10 100 mL 0.001 0.1 6.076 × 103 0.01 9.722 × 104 230.0 0.06076 4 1.0567 1000 6.076 × 104 Tap here for additional resourcesarrow_forwardShow work in detailed of all the options. Don't give Ai generated solutionarrow_forwardPredict the Product. Predict the major organic product for the following reaction:arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)