Living By Chemistry: First Edition Textbook
Living By Chemistry: First Edition Textbook
1st Edition
ISBN: 9781559539418
Author: Angelica Stacy
Publisher: MAC HIGHER
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Chapter U2, Problem SI2RE

(a)

Interpretation Introduction

Interpretation: The Lewis dot structure and structural formula of SiF4 needs to be drawn.

Concept Introduction: Valence electrons are involved in covalent bonding where sharing of electrons takes place.

(a)

Expert Solution
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Explanation of Solution

Lewis dot structure can be drawn with the help of valence electrons. Silicon has 4 valence electrons, Fluorine has 7 valence electrons. To complete the octet, Si will share 4 electrons, one electron each with fluorine.

Thus, the Lewis dot structure and structural formula of SiF4is represented as follows:

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  1

(b)

Interpretation Introduction

Interpretation: The Lewis dot structure and structural formula of CO2 needs to be drawn.

Concept Introduction: Valence electrons are involved in covalent bonding where sharing of electrons takes place.

(b)

Expert Solution
Check Mark

Explanation of Solution

Lewis dot structure can be drawn with the help of valence electrons. Carbon has 4 valence electrons, oxygen has 6 valence electrons. To complete the octet, carbon will share 4 electrons, two electrons each with oxygen and form double covalent bond.

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  2Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  3

(c)

Interpretation Introduction

Interpretation: The Lewis dot structure and structural formula of CH4 needs to be drawn.

Concept Introduction: Valence electrons are involved in covalent bonding where sharing of electrons takes place.

(c)

Expert Solution
Check Mark

Explanation of Solution

Lewis dot structure can be drawn with the help of valence electrons. Carbon has 4 valence electrons, hydrogen has one valence electrons. To complete the octet, carbon will share 4 electrons, one electron each with hydrogen and form single covalent bond.

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  4Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  5

(d)

Interpretation Introduction

Interpretation: The Lewis dot structure and structural formula of SF2 needs to be drawn.

Concept Introduction: Valence electrons are involved in covalent bonding where sharing of electrons takes place.

(d)

Expert Solution
Check Mark

Explanation of Solution

Lewis dot structure can be drawn with the help of valence electrons. Sulphur has 6 valence electrons, Fluorine has 7 valence electrons. To complete the octet, sulphur will share 2 electrons, one electron each with fluorine and form single covalent bond.

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  6

(e)

Interpretation Introduction

Interpretation: The Lewis dot structure and structural formula of C2H4needs to be drawn.

Concept Introduction: Valence electrons are involved in covalent bonding where sharing of electrons takes place.

(e)

Expert Solution
Check Mark

Explanation of Solution

Carbon has 4 valence electrons, hydrogen has one valence electrons. To complete the octet, carbon will share 4 electrons, one electron each with hydrogen and form single covalent bond.

When carbon shares two electrons with other carbon atom, it forms double bond.

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  7Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  8

(f)

Interpretation Introduction

Interpretation: The Lewis dot structure and structural formula of C2H2 needs to be drawn.

Concept Introduction: Valence electrons are involved in covalent bonding where sharing of electrons takes place.

(f)

Expert Solution
Check Mark

Explanation of Solution

Carbon has 4 valence electrons, hydrogen has one valence electrons. To complete the octet, carbon will share 4 electrons, one electron each with hydrogen and form single covalent bond.

When carbon share three electrons with other carbon atom, it forms triple bond.

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  9Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  10

(g)

Interpretation Introduction

Interpretation: The Lewis dot structure and structural formula of C2H6needs to be drawn.

Concept Introduction: Valence electrons are involved in covalent bonding where sharing of electrons takes place.

(g)

Expert Solution
Check Mark

Explanation of Solution

Carbon has 4 valence electrons, hydrogen has one valence electrons. To complete the octet, carbon will share 4 electrons, one electron each with hydrogen and form single covalent bond.

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  11Living By Chemistry: First Edition Textbook, Chapter U2, Problem SI2RE , additional homework tip  12

Chapter U2 Solutions

Living By Chemistry: First Edition Textbook

Ch. U2.2 - Prob. 3ECh. U2.2 - Prob. 4ECh. U2.2 - Prob. 5ECh. U2.2 - Prob. 6ECh. U2.2 - Prob. 7ECh. U2.3 - Prob. 1TAICh. U2.3 - Prob. 1ECh. U2.3 - Prob. 2ECh. U2.3 - Prob. 3ECh. U2.3 - Prob. 4ECh. U2.3 - Prob. 5ECh. U2.4 - Prob. 1TAICh. U2.4 - Prob. 1ECh. U2.4 - Prob. 2ECh. U2.4 - Prob. 3ECh. U2.4 - Prob. 4ECh. U2.4 - Prob. 5ECh. U2.4 - Prob. 6ECh. U2.4 - Prob. 7ECh. U2.4 - Prob. 8ECh. U2.5 - Prob. 1TAICh. U2.5 - Prob. 1ECh. U2.5 - Prob. 2ECh. U2.5 - Prob. 3ECh. U2.5 - Prob. 4ECh. U2.5 - Prob. 5ECh. U2.5 - Prob. 6ECh. U2.5 - Prob. 7ECh. U2.5 - Prob. 8ECh. U2.5 - Prob. 9ECh. U2.6 - Prob. 1TAICh. U2.6 - Prob. 1ECh. U2.6 - Prob. 2ECh. U2.6 - Prob. 3ECh. U2.6 - Prob. 4ECh. U2.6 - Prob. 5ECh. U2.6 - Prob. 6ECh. U2.6 - Prob. 7ECh. U2.6 - Prob. 8ECh. U2.6 - Prob. 9ECh. U2.6 - Prob. 10ECh. U2.6 - Prob. 11ECh. U2.7 - Prob. 1TAICh. U2.7 - Prob. 1ECh. U2.7 - Prob. 2ECh. U2.7 - Prob. 3ECh. U2.7 - Prob. 4ECh. U2.7 - Prob. 5ECh. U2.8 - Prob. 1TAICh. U2.8 - Prob. 1ECh. U2.8 - Prob. 2ECh. U2.8 - Prob. 3ECh. U2.8 - Prob. 4ECh. U2.8 - Prob. 5ECh. U2.8 - Prob. 6ECh. U2.9 - Prob. 1TAICh. U2.9 - Prob. 1ECh. U2.9 - Prob. 2ECh. U2.9 - Prob. 3ECh. U2.9 - Prob. 4ECh. U2.9 - Prob. 5ECh. U2.9 - Prob. 6ECh. U2.9 - Prob. 7ECh. U2.10 - Prob. 1TAICh. U2.10 - Prob. 1ECh. U2.10 - Prob. 2ECh. U2.10 - Prob. 3ECh. U2.10 - Prob. 4ECh. U2.10 - Prob. 5ECh. U2.10 - Prob. 6ECh. U2.10 - Prob. 7ECh. U2.10 - Prob. 8ECh. U2.10 - Prob. 9ECh. U2.11 - Prob. 1TAICh. U2.11 - Prob. 1ECh. U2.11 - Prob. 2ECh. U2.11 - Prob. 3ECh. U2.11 - Prob. 4ECh. U2.11 - Prob. 5ECh. U2.11 - Prob. 6ECh. U2.11 - Prob. 7ECh. U2.12 - Prob. 1TAICh. U2.12 - Prob. 1ECh. U2.12 - Prob. 2ECh. U2.12 - Prob. 3ECh. U2.12 - Prob. 4ECh. U2.12 - Prob. 5ECh. U2.12 - Prob. 6ECh. U2.12 - Prob. 7ECh. U2.13 - Prob. 1TAICh. U2.13 - Prob. 1ECh. U2.13 - Prob. 2ECh. U2.13 - Prob. 3ECh. U2.13 - Prob. 4ECh. U2.13 - Prob. 5ECh. U2.14 - Prob. 1TAICh. U2.14 - Prob. 1ECh. U2.14 - Prob. 2ECh. U2.14 - Prob. 3ECh. U2.14 - Prob. 4ECh. U2.14 - Prob. 5ECh. U2.14 - Prob. 6ECh. U2.14 - Prob. 7ECh. U2.14 - Prob. 8ECh. U2.15 - Prob. 1TAICh. U2.15 - Prob. 1ECh. U2.15 - Prob. 2ECh. U2.15 - Prob. 4ECh. U2.15 - Prob. 5ECh. U2.15 - Prob. 6ECh. U2.16 - Prob. 1TAICh. U2.16 - Prob. 1ECh. U2.16 - Prob. 2ECh. U2.16 - Prob. 3ECh. U2.16 - Prob. 4ECh. U2.16 - Prob. 6ECh. U2.16 - Prob. 7ECh. U2.17 - Prob. 1TAICh. U2.17 - Prob. 1ECh. U2.17 - Prob. 2ECh. U2.17 - Prob. 3ECh. U2.17 - Prob. 4ECh. U2.17 - Prob. 5ECh. U2.17 - Prob. 6ECh. U2.17 - Prob. 7ECh. U2.17 - Prob. 8ECh. U2.17 - Prob. 9ECh. U2.18 - Prob. 1TAICh. U2.18 - Prob. 1ECh. U2.18 - Prob. 2ECh. U2.18 - Prob. 3ECh. U2.18 - Prob. 4ECh. U2.18 - Prob. 5ECh. U2.18 - Prob. 6ECh. U2.18 - Prob. 7ECh. U2.19 - Prob. 1TAICh. U2.19 - Prob. 1ECh. U2.19 - Prob. 2ECh. U2.19 - Prob. 3ECh. U2.19 - Prob. 4ECh. U2.19 - Prob. 5ECh. U2.19 - Prob. 6ECh. U2.19 - Prob. 7ECh. U2.19 - Prob. 8ECh. U2.19 - Prob. 9ECh. U2.20 - Prob. 1TAICh. U2.20 - Prob. 1ECh. U2.20 - Prob. 2ECh. U2.20 - Prob. 3ECh. U2.20 - Prob. 4ECh. U2.20 - Prob. 5ECh. U2.20 - Prob. 6ECh. U2.20 - Prob. 7ECh. U2.20 - Prob. 8ECh. U2.20 - Prob. 9ECh. U2.21 - Prob. 1TAICh. U2.21 - Prob. 1ECh. U2.21 - Prob. 2ECh. U2.21 - Prob. 3ECh. U2.21 - Prob. 4ECh. U2.21 - Prob. 6ECh. U2 - Prob. SI1RECh. U2 - Prob. SI2RECh. U2 - Prob. SI3RECh. U2 - Prob. SI4RECh. U2 - Prob. SI5RECh. U2 - Prob. SII1RECh. U2 - Prob. SII2RECh. U2 - Prob. SII3RECh. U2 - Prob. SII4RECh. U2 - Prob. SII5RECh. U2 - Prob. SIII1RECh. U2 - Prob. SIII2RECh. U2 - Prob. SIII3RECh. U2 - Prob. SIII4RECh. U2 - Prob. SIII5RECh. U2 - Prob. SIII6RECh. U2 - Prob. SIV1ECh. U2 - Prob. SIV2ECh. U2 - Prob. SIV3ECh. U2 - Prob. SIV4ECh. U2 - Prob. SIV5ECh. U2 - Prob. 1RECh. U2 - Prob. 2RECh. U2 - Prob. 3RECh. U2 - Prob. 4RECh. U2 - Prob. 5RECh. U2 - Prob. 6RECh. U2 - Prob. 7RECh. U2 - Prob. 8RE
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