Consider the series solution, Equation 5.42, for the plane wall with convection. Calculate midplane
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Introduction to Heat Transfer
- answer (c) pleasearrow_forwardNonearrow_forwardThe one-dimensional heat equation ut + a²uxx = 0 is discretised using the forward Euler time scheme and a two node centred spatial scheme. This discretisation results in the following equation un n+1 u = a² u+12u?+ u-1 4x² At • Comment on the linearity, order and type of the partial differential equation. • Check the consistency of the discrete equation and state the order of the truncation error for At and Ax. Using the modified equation method, investigate the stability of the discrete equation. • Comment on any stability limitations in terms of choice of At. • Comment on the implications of this scheme with regards to numerical diffusion and dispersion, if any.arrow_forward
- This is a multiple-part question, I just need help with part C, Table 2.2 is provided and you can refer to above parts for equations and boundary equations.arrow_forwardThe initial temperature distribution of a 5 cm long stick is given by the following function. The circumference of the rod in question is completely insulated, but both ends are kept at a temperature of 0 °C. Obtain the heat conduction along the rod as a function of time and position ? (x = 1.752 cm²/s for the bar in question) 100 A) T(x1) = 1 Sin ().e(-1,752 (³¹)+(sin().e (-1,752 (²) ₁ + 1 3π TC3 .....) 100 t + ··· ....... 13) T(x,t) = 200 Sin ().e(-1,752 (²t) + (sin (3). e (-1,752 (7) ²) t B) 3/3 t + …............) C) T(x.t) = 200 Sin ().e(-1,752 (²t) (sin().e(-1,752 (7) ²) t – D) T(x,t) = 200 Sin ().e(-1,752 (²)-(sin().e (-1,752 (²7) ²) t E) T(x.t)=(Sin().e(-1,752 (²t)-(sin().e(-1,752 (²) t+ t + ··· .........) t +.... t + ··· .........) …..)arrow_forwardOne of the strengths of numerical methods is their ability to handle complex boundary conditions. In the sketch, the boundary condition changes from specified heat flux ′′ qs (into the domain) to convection, at the location of the node (m, n). Write the steady-state, two- dimensional finite difference equation at this node.arrow_forward
- (3) For the given boundary value problem, the exact solution is given as = 3x - 7y. (a) Based on the exact solution, find the values on all sides, (b) discretize the domain into 16 elements and 15 evenly spaced nodes. Run poisson.m and check if the finite element approximation and exact solution matches, (c) plot the D values from step (b) using topo.m. y Side 3 Side 1 8.0 (4) The temperature distribution in a flat slab needs to be studied under the conditions shown i the table. The ? in table indicates insulated boundary and Q is the distributed heat source. I all cases assume the upper and lower boundaries are insulated. Assume that the units of length energy, and temperature for the values shown are consistent with a unit value for the coefficier of thermal conductivity. Boundary Temperatures 6 Case A C D. D. 00 LEGION Side 4 z episarrow_forward2. One of the strengths of numerical methods is their ability to handle complex boundary conditions. In the sketch, the boundary condition changes from specified heat flux qs"(into the domain) to convection, at the location of the node (m, n). Write the steady-state, two-dimensional finite difference equation at this node. Δ.Χ m, n h, T∞ Ayarrow_forwardSolve the heat equation u, = 0.2u on a digital computer using XX the Crank-Nicolson scheme. for the initial condition and boundary conditions TABLE P4.1 Case 1 2 3 4 5 Number of Grid Points 11 11 16 11 11 (x,0) = 100 sin TX L 0.25 0.50 0.50 1.00 2.00 L = 1 u(0,t) = u(L,t) = 0 Compute to t = 0.5 using the parameters in Table P4.1 (if possible) and compare graphically with the exact solution.arrow_forward
- SOLVE IN DIGITAL FORMATarrow_forward1. A spring mass system serving as a shock absorber under a car's suspension, supports the M 1000 kg mass of the car. For this shock absorber, k = 1 × 10°N /m and c = 2 × 10° N s/m. The car drives over a corrugated road with force %3| F = 2× 10° sin(@t) N . Use your notes to model the second order differential equation suited to this application. Simplify the equation with the coefficient of x'" as one. Solve x (the general solution) in terms of w using the complimentary and particular solution method. In determining the coefficients of your particular solution, it will be required that you assume w – 1z w or 1 – o z -w. Do not use Matlab as its solution will not be identifiable in the solution entry. Do not determine the value of w. You must indicate in your solution: 1. The simplified differential equation in terms of the displacement x you will be solving 2. The m equation and complimentary solution xe 3. The choice for the particular solution and the actual particular solution x,…arrow_forwardQ1arrow_forward
- Principles of Heat Transfer (Activate Learning wi...Mechanical EngineeringISBN:9781305387102Author:Kreith, Frank; Manglik, Raj M.Publisher:Cengage Learning