(a) Explanation Given: The inner diameter of spherical tank is d 1 = 3 m . The temperature of liquefied petroleum gas is T 1 = − 60 ° C . The thermal conductivity of insulation is k = 0.06 W / m ⋅ K . The thickness of tank is t = 250 mm . The temperature of insulation layer is T 2 = 0 °C . The temperature of outer surface of tank is T 3 = 20 °C . The convection heat transfer coefficient is, h = 6 W / m 2 ⋅ K . Formula used: The heat transfer relation is given as, T 3 − T 1 R T = 4 π k ( T 2 − T 1 ) [ 1 r 1 − 1 r s ] Here, R T is the total thermal resistance and r s is the radial position of insulation layer. The total thermal resistance is given as, R T = 1 4 π [ 1 k ( 1 r 1 − 1 r 2 ) + 1 h × r 2 2 ] Here, r 2 is the outer radius. The outer radius is given as, r 2 = d 1 2 + t Calculation: The outer radius is can be calculated as, r 2 = d 1 2 + t r 2 = 3 m 2 + 250 mm × ( 1 m 1000 mm ) r 2 = 1.75 m The total thermal resistance is given as, R T = 1 4 π [ 1 k ( 1 r 1 − 1 r 2 ) + 1 h × r 2 2 ] R T = 1 4 π [ 1 k ( 1 d 1 2 − 1 r 2 ) + 1 h × r 2 2 ] R T = 1 4 π [ 1 0 (b) To determine The effect on ice formation on heat gain to low temperature gas. The prevention of situation.

6th Edition

ISBN: 9780470501962

Author: Frank P. Incropera, David P. DeWitt, Theodore L. Bergman, Adrienne S. Lavine

Publisher: Wiley, John & Sons, Incorporated

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Chapter 3, Problem 3.76P

(a)

To determine

The radial position of the insulation layer.

(b)

To determine

The effect on ice formation on heat gain to low temperature gas.

The prevention of situation.

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Chapter 3, Problem 3.75P

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The radial position of the insulation layer.

Solution Summary: The author explains the radial position of the insulation layer, the temperature of liquefied petroleum gas, and the convection heat transfer coefficient.

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The effect on ice formation on heat gain to low temperature gas. The prevention of situation.

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Chapter 3 Solutions

The effect on ice formation on heat gain to low temperature gas.

The prevention of situation.