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In a manufacturing process, stainless steel cylinders (AISI 304) initially at 600 K are quenched by submersion in an oil bath maintained at 300 K with
(a) Calculate the temperatures,
(b) Plot the temperature history at the center,
(c) Having solved the model for a total integration time of 10 min in part (b), now use the View/Temperature Contours command with the shaded band option for the isotherm contours. Select the From Start to Stop time option, and view the temperature contours as the cylinder cools during the quench process. Describe the major features of the cooling process revealed by this display. Use other options of this command to create a 10-isotherm temperature distribution for
(d) For the location of part (a), calculate the temperatures after 3 min if the convection coefficient is doubled
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Chapter 3 Solutions
Introduction to Heat Transfer
- T1=68 T2=43 Q3:arrow_forwardI need answer within 20 minutes please please with my best wishesarrow_forwardA piece of metal is initially heated to 850°C and is quenched in water which temperature is kept at 50°C. The temperature decay constant of the system is 0.30/min. a.) Determine the temperature of the metal at any time, T(t), using Laplace Transforms. b.) Determine the time needed for the metal to be at 80°C.arrow_forward
- Specific Heat, Cp Water Thermal Thermal Content, Temperature, T Density, p Conductivity, k Ibm/ft3 Diffusivity, a ft2/s Food %(mass) °F Btu/h-ft.°F Btu/lbm-R Fruits/Vegetables Apple juice Apples Apples, dried Apricots, dried Bananas, fresh 1.51 x 10-6 1.47 x 10-6 87 68 62.4 0.323 0.922 85 32-86 52.4 0.242 0.910 41.6 73 53.4 0.127 1.03 x 10-6 0.650 1.22 x 10-6 1.51 × 10-6 43.6 73 82.4 0.217 0.662 76 41 61.2 0.278 0.856 Broccoli 21 35.0 0.223 | 1.42 x 10-6 Cherries, fresh Figs Grape juice 92 32-86 65.5 0.315 0.952 40.4 73 77.5 0.179 1.03 x 10-6 0.642 1.51 × 10-6 1.51 × 10-6 89 68 62.4 0.328 0.934 Peaches 36-90 2-32 59.9 0.304 0.934 Plums 3 38.1 0.143 | Potatoes 32-158 0-70 65.7 0.288 1.40 x 10-6 0.868 Raisins 32 73 86.2 0.217 1.18 x 10-6 0.592 Meats Beef, ground Beef, lean 67 43 59.3 0.235 1.40 x 10-6 0.802 74 37 68.0 0.272 1.40 x 10-6 0.844 Beef fat 95 50.5 0.110 72 95 73 Beef liver 0.259 0.832 1.18 x 10-6 1.40 x 10-6 Cat food 39.7 71.2 0.188 0.638 Chicken breast 75 32 65.5 0.275 0.850arrow_forwardQuestion: USE CRANCK NICKLISON METHOD TO Find the steady state temperature distribution at all points of a heated steel plate .The plate has 30 cm width and 30 cm in length . The edges of the sheet are kept at constant temperature: 100 , 80 , 60 ,40 degrees. Assume the sheet is divided into 3x3 grids.arrow_forwardPlease show all work for this mechnical measure problem. Not Ai generated the answers have been wrong I need to understand.arrow_forward
- Thxarrow_forwardFind the two-dimensional temperature distribution T(x,y) and midplane temperature T(B/2,W/2) under steady state condition. The density, conductivity and specific heat of the material are p=(1200*32)kg/mº, k=400 W/m.K, and cp=2500 J/kg.K, respectively. A uniform heat flux 9" =1000 W/m² is applied to the upper surface. The right and left surfaces are also kept at 0°C. Bottom surface is insulated. 9" (W/m) T=0°C T=0°C W=(10*32)cm B=(30*32)cmarrow_forwardI.C 02/A/ Use the Crank-Nicolson method to solve for the temperature distribution of a long thin rod with a length of 10 cm and the following values: k = 0.49 cal/(s cm °C), Ax = 2 cm, and At = st 0.1 s. Initially the temperature of the rod is 0°C and the boundary conditions are fixed for all times at 7(0, t) = 100°C and 7(10, t) = 50°C. Note that the rod is aluminum with C = 0.2174 cal/g °C) and p = 2.7 g/cm³. List the tridiagonal system of equations and determined the temperature up to 0.1 s.arrow_forward
- I need step by step and detailed explanations please help for understand, thank u :)arrow_forwardplz solve all the question with explaination. I will give you upvotesarrow_forwardAfter a thorough derivation by Doraemon to establish an equation for cylindrical fuel rod of a nuclear reactor. Here he was able to come up an equation of heat generated internally as shown below. 96 = 9. where qG is the local rate of heat generation per unit volume at radius r, ro is the outside radius, and qo is the rate of heat generation per unit volume at the centre line. Calculate the temperature drop from the centre line to the surface for a 2.5 cm outer diameter rod having k = 25 W/m K, if the rate of heat removal from the surface is 1650 kW/m2 A 619 °C 719 °C C) 819 °C 919 °C E 1019 °C F None of thesearrow_forward
- Principles of Heat Transfer (Activate Learning wi...Mechanical EngineeringISBN:9781305387102Author:Kreith, Frank; Manglik, Raj M.Publisher:Cengage Learning
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