Chapter U2.32, Problem 5E

(a)

Interpretation Introduction

Interpretation:

Lewis dot structure of CF₄ must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

Answer to Problem 5E

Lewis dot structure of CF₄ is given below.

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Explanation of Solution

C has 4 valence electrons. F has 7 valence electrons. Thus one carbon is covalently bonded with 4 F atoms. There are three lone pairs of electrons on each F atom. Accordingly Lewis structure is shown as follows:

  

(b)

Interpretation Introduction

Interpretation:

Lewis dot structure of CH₃Cl must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

Answer to Problem 5E

Lewis dot structure of CH₃Cl is given below.

.

Explanation of Solution

C has 4 valence electrons. Cl has 7 valence electrons. H has one valence electron. Thus one carbon is covalently bonded with 3 H atoms and 1 Cl. There are three lone pairs of electrons on Cl atom. Accordingly Lewis structure is shown as follows:

  

(c)

Interpretation Introduction

Interpretation:

Lewis dot structure of SiCl₂H₂ must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

Answer to Problem 5E

Lewis dot structure of SiCl₂H₂ is given below.

.

  

Explanation of Solution

Si has 4 valence electrons, Cl has 7 valence electrons and H has one valence electron. Thus one carbon is covalently bonded with 2 H atoms and 2 Cl atoms. There are three lone pairs of electrons on Cl atom. Accordingly Lewis structure is shown as follows:

  

(d)

Interpretation Introduction

Interpretation:

Lewis dot structure of CH₃OH must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

Answer to Problem 5E

Lewis dot structure of CH₃OH is given below:

.

  

Explanation of Solution

C has 4 valence electrons. O has 6 valence electrons. H has one valence electron. Thus one carbon is covalently bonded with 3 H atoms and 1 O atom. The O atom is bonded with central carbon atom and one hydrogen atom. There are 2 lone pairs of electrons on O atom. Accordingly, Lewis structure is shown as follows:

  

(e)

Interpretation Introduction

Interpretation:

Lewis dot structure of HOCl must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

Answer to Problem 5E

Lewis dot structure of HOCl is given below.

.

  

Explanation of Solution

O has 6 valence electrons, Cl has 7valence electrons and H has one valence electron. Thus one central O is covalently bonded with 1 H atoms and 1 Cl atom. There are 2 lone pairs of electrons on O atom and 3 lone pairs of electrons on Cl atom. Accordingly Lewis structure is shown as follows

  

(f)

Interpretation Introduction

Interpretation:

Lewis dot structure of CH₃NH₂ must be drawn.

Concept Introduction :

Lewis dot structure is the representation of a molecule with the valence electrons shown as dots.

Answer to Problem 5E

Lewis dot structure of CH₃NH₂ is given below.

.

  

Explanation of Solution

C has 4 valence electrons, N has 5 valence electrons and H has one valence electron. Thus one central C is covalently bonded with 3 H atoms and 1 N atom. N atom is covalently bonded with central C atom and two hydrogen atoms. There are 2 lone pairs of electrons on N atom. Accordingly Lewis structure is shown as follows: