
Concept explainers
(a)
Interpretation:
Lewis dot symbol of Ge, Sb, Se and Br must be drawn.
Concept Introduction :
Lewis dot symbol is the
(a)

Answer to Problem 4E
Lewis dot symbols for all the given elements are drawn below.
.
Explanation of Solution
Ge, Sb, Se and Br have 4, 5, 4, 6 and 7 valence electrons respectively. Accordingly Lewis dot structures are shown as follows:
(b)
Interpretation:
Lewis structures for GeH4, SbH3, H2Se and HBr must be drawn.
Concept Introduction :
Ge, Sb, Se and Br bond with 4, 3, 2 and 1 hydrogen respectively to form the corresponding covalent hydrides.
(b)

Answer to Problem 4E
Lewis structures for all the hydrides are shown below.
Explanation of Solution
Ge has 4 valence electrons and bonded with 4 hydrogens. There is no lone pair of electrons.
Sb has 5 valence electrons and formed 3 covalent bonds with 3 hydrogens. There are one lone pair electrons on Sb atom.
Se has 6 valence electrons and bonds with 2 hydrogens. There are 2 lone pairs of electrons on Se atom.
Br has 7 valence electrons and bonds with 1 hydrogen. There is 3 lone pair of electrons on Br atom.
Thus, the Lewis structures are represented as follows:
(c)
Interpretation:
Pattern for number of hydrogen atoms in GeH4, SbH3, H2Se and HBr must be explained.
Concept Introduction :
Ge, Sb, Se and Br have valence electrons as 4, 5, 6 and 7 respectively. Thus, the vacancies are 4, 3, 2 and 1 respectively.
(c)

Answer to Problem 4E
Number of hydrogens gradually decreases from Ge to Br.
Explanation of Solution
Ge has 4 valence electrons and bonded with 4 hydrogens. Sb has 5 valence electrons and valency 3 and formed 3 covalent bonds with 3 hydrogen atoms.
Se has 6 valence electrons and valency 2 and bonds with 2 hydrogens.
Br has 7 valence electrons and valency 1 and bonds with 1 hydrogen.
Thus, the number of hydrogen atoms decreases from Ge to Br.
Chapter U2 Solutions
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