
Concept explainers
(a)
Interpretation: Comprehend the orientation of methanol molecule towards a negatively charged wand.
Concept Introduction: The polarity of molecule depends on the presence of electropositive and electronegative atoms present in the molecule.
Due to electronegativity difference between bonded atoms, partial charges induce on the bonded atoms. The partial charges effect the physical properties of the polar molecules.
(a)

Answer to Problem 4E
Explanation of Solution
Methanol is a polar molecule as it contains one −OH group. Here O is more electronegative than H atom. Therefore the −OH group is polar with partial negative charge on O and partial positive charge on H atom.
The molecule of methanol will orient towards a negative charge wand in such a way that the electropositive H atom will orient toward wand and the O atom will orient away from wand as it carries partial negative charge as given below:
(b)
Interpretation: Comprehend the position of methanol molecules on waxed paper; either bead up or spread out.
Concept Introduction: The polarity of molecule depends on the presence of electropositive and electronegative atoms present in the molecule.
Due to electronegativity difference between bonded atoms, partial charges induce on the bonded atoms. The partial charges effect the physical properties of the polar molecules.
(b)

Answer to Problem 4E
Methanol molecules bead up over waxed paper.
Explanation of Solution
Methanol is a polar molecule as it contains one −OH group. Here O is more electronegative than H atom. Therefore the −OH group is polar with partial negative charge on O and partial positive charge on H atom. A polar molecule is always soluble in polar solvent. Wax is a non-polar compound as it is composed of long fatty acid chain.
Therefore methanol is not soluble in wax and methanol molecules will bead up over waxed paper.
(c)
Interpretation: Comprehend the solubility of methanol in water.
Concept Introduction: The polarity of molecule depends on the presence of electropositive and electronegative atoms present in the molecule.
Due to electronegativity difference between bonded atoms, partial charges induce on the bonded atoms. The partial charges effect the physical properties of the polar molecules.
(c)

Answer to Problem 4E
Methanol is soluble in water.
Explanation of Solution
Methanol is a polar molecule as it contains one −OH group. Here O is more electronegative than H atom. Therefore the −OH group is polar with partial negative charge on O and partial positive charge on H atom. A polar molecule is always soluble in polar solvent. Water is a polar molecule as it has partially negative O atom that is bonded with partially positive H atom.
Therefore methanol will be soluble in polar water as solvent.
Chapter U2 Solutions
Living by Chemistry
Additional Science Textbook Solutions
The Cosmic Perspective (8th Edition)
Microbiology: An Introduction
Chemistry: A Molecular Approach (4th Edition)
Microbiology with Diseases by Body System (5th Edition)
Microbiology: An Introduction
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
- Using reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NOCI (g) 2NO (g) + Cl2 (g) AGº =41. kJ Now suppose a reaction vessel is filled with 4.50 atm of nitrosyl chloride (NOCI) and 6.38 atm of chlorine (C12) at 212. °C. Answer the following questions about this system: ? rise Under these conditions, will the pressure of NOCI tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO? In other words, if you said the pressure of NOCI will tend to rise, can that be changed to a tendency to fall by adding NO? Similarly, if you said the pressure of NOCI will tend to fall, can that be changed to a tendency to rise by adding NO? yes no If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO needed to reverse it. Round your answer to 2 significant digits. 0.035 atm ✓ G 00. 18 Ararrow_forwardHighlight each glycosidic bond in the molecule below. Then answer the questions in the table under the drawing area. HO- HO- -0 OH OH HO NG HO- HO- OH OH OH OH NG OHarrow_forward€ + Suppose the molecule in the drawing area below were reacted with H₂ over a platinum catalyst. Edit the molecule to show what would happen to it. That is, turn it into the product of the reaction. Also, write the name of the product molecule under the drawing area. Name: ☐ H C=0 X H- OH HO- H HO- -H CH₂OH ×arrow_forward
- Draw the Haworth projection of the disaccharide made by joining D-glucose and D-mannose with a ẞ(1-4) glycosidic bond. If the disaccharide has more than one anomer, you can draw any of them. Click and drag to start drawing a structure. Xarrow_forwardEpoxides can be opened in aqueous acid or aqueous base to produce diols (molecules with two OH groups). In this question, you'll explore the mechanism of epoxide opening in aqueous acid. 2nd attempt Be sure to show all four bonds at stereocenters using hash and wedge lines. 0 0 Draw curved arrows to show how the epoxide reacts with hydronium ion. 100 +1: 1st attempt Feedback Be sure to show all four bonds at stereocenters using hash and wedge lines. See Periodic Table See Hint H A 5 F F Hr See Periodic Table See Hintarrow_forward03 Question (1 point) For the reaction below, draw both of the major organic products. Be sure to consider stereochemistry. > 1. CH₂CH₂MgBr 2. H₂O 3rd attempt Draw all four bonds at chiral centers. Draw all stereoisomers formed. Draw the structures here. e 130 AN H See Periodic Table See Hint P C Brarrow_forward
- You may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forward
- Alcohols can be synthesized using an acid-catalyzed hydration of an alkene. An alkene is combined with aqueous acid (e.. sulfuric acid in water). The reaction mechanism typically involves a carbocation intermediate. > 3rd attempt 3343 10 8 Draw arrows to show the reaction between the alkene and hydronium ion. that 2nd attempt Feedback 1st attempt تعمال Ju See Periodic Table See Hint F D Ju See Periodic Table See Hintarrow_forwardDraw the simplified curved arrow mechanism for the reaction of acetone and CHgLi to give the major product. 4th attempt Π Draw the simplified curved arrow mechanism T 3rd attempt Feedback Ju See Periodic Table See Hint H -H H -I H F See Periodic Table See Hintarrow_forwardSelect the correct reagent to accomplish the first step of this reaction. Then draw a mechanism on the Grignard reagent using curved arrow notation to show how it is converted to the final product. 4th attempt Part 1 (0.5 point) Select the correct reagent to accomplish the first step of this reaction. Choose one: OA Mg in ethanol (EtOH) OB. 2 Li in THF O C. Li in THF D. Mg in THF O E Mg in H2O Part 2 (0.5 point) Br Part 1 Bri Mg CH B CH, 1 Draw intermediate here, but no arrows. © TE See Periodic Table See Hint See Hint ין Harrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





