
Interpretation:
The energy released per gram from the combustion of a fixed mass of potato chips needs to be determined. The energy produced by the combustion reaction is used to heat up a fixed mass of water.
Concept introduction:
As per the principle of thermochemistry, the heat lost by a hot substance is equal to the heat gained by a cold substance when these two substances are brought in contact with each other. The amount of heat energy lost or gained by the substance depends on the mass of the substance taken as well as the rise in temperature of the substance.
In this problem, the combustion of the chips produces energy that is used to heat up the given mass of water. The heat gained by the fixed mass of water is given by the following formula:
Here, q is heat gained, m is mass of water, c is specific heat capacity of water and
The specific heat capacity of a substance is constant and is equal to the amount of heat required to raise the temperature of unit mass of the substance by unit degree.

Answer to Problem 11STP
The correct answer is the second option, option (B).
Explanation of Solution
Reason for correct option:
The heat released by the combustion of the chips is used to heat up 25.0 mL of water.
Assuming that the density of water is 1.00 g/mL at the temperature of the experiment, the mass of water heated up can be calculated as
(specific heat capacity of water is 1.00 cal/g.°C)
The heat gained by water must have been obtained from the combustion of the chips; thus, the heat released by the combustion of the chips is 150. cal.
Therefore,
Reason for incorrect options:
The mathematical calculation leads to the correct answer as option (B) and thus, all the other options are incorrect.
Chapter U5 Solutions
Living by Chemistry
Additional Science Textbook Solutions
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Biology: Life on Earth with Physiology (11th Edition)
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Campbell Biology (11th Edition)
Anatomy & Physiology (6th Edition)
Campbell Biology in Focus (2nd Edition)
- The following 'H NMR spectrum was taken with a 750 MHz spectrometer: 1.0 0.5 0.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 ' 2.0 1.0 0.0 (ppm) What is the difference Av in the frequency of RF ac Δν ac radiation absorbed by the a and c protons? (Note: it's not equal to the difference in chemical shifts.) Round your answer to 2 significant digits, and be sure it has an appropriate unit symbol. = O O a will shift left, c will shift right. O a will shift right, c will shift left. a and c will both shift left, with more space between them. Suppose a new spectrum is taken with a 500 MHz spectrometer. What will be true about this new spectrum? O a and c will both shift left, with less space between them. O a and c will both shift right, with more space between them. O a and c will both shift right, with less space between them. Which protons have the largest energy gap between spin up and spin down states? O None of the above. ○ a Ob Explanation Check C Ar B 2025 McGraw Hill LLC. All Rights Reserved.…arrow_forwardWhat mass of Na2CO3 must you add to 125g of water to prepare 0.200 m Na2CO3? Calculate mole fraction of Na2CO3, mass percent, and molarity of the resulting solution. MM (g/mol): Na2CO3 105.99; water 18.02. Final solution density is 1.04 g/mL.arrow_forward(ME EX2) Prblms Can you please explain problems to me in detail, step by step? Thank you so much! If needed color code them for me.arrow_forward
- Experiment #8 Electrical conductivity & Electrolytes. Conductivity of solutions FLINN Scientific Scale RED LED Green LED LED Conductivity 0 OFF OFF 1 Dim OFF 2 medium OFF 3 Bright Dim Low or Nowe Low Medium High 4 Very Bright Medium nd very high AA Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ SE=Strong Electrolyte, FE = Fair Electrolyte CWE = Weak Electrolyte, NE= Noni Electrolyte, #Solutions 1 0.1 M NaCl 2/1x 102 M NaCl, 3/1X103 M Nall Can Prediction M Observed Conductivity Very bright red Bright red Dim red you help me understand how I'm supposed to find the predictions of the following solutions? I know this is an Ionic compound and that the more ions in a solution means it is able to carry a charge, right? AAAA Darrow_forward(SE EX 2) Prblsm 4-7: Can you please explain problems 4-7 and color code if needed for me. (step by step) detail explanationsarrow_forward(SE EX 2) Problems 8-11, can you please explain them to me in detail and color-code anything if necessary?arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





