Living by Chemistry
Living by Chemistry
2nd Edition
ISBN: 9781464142314
Author: Angelica M. Stacy
Publisher: W. H. Freeman
bartleby

Videos

Question
Book Icon
Chapter U5, Problem 11STP
Interpretation Introduction

Interpretation:

The energy released per gram from the combustion of a fixed mass of potato chips needs to be determined. The energy produced by the combustion reaction is used to heat up a fixed mass of water.

Concept introduction:

As per the principle of thermochemistry, the heat lost by a hot substance is equal to the heat gained by a cold substance when these two substances are brought in contact with each other. The amount of heat energy lost or gained by the substance depends on the mass of the substance taken as well as the rise in temperature of the substance.

In this problem, the combustion of the chips produces energy that is used to heat up the given mass of water. The heat gained by the fixed mass of water is given by the following formula:

q=mcΔT

Here, q is heat gained, m is mass of water, c is specific heat capacity of water and ΔT is change in temperature of water.

The specific heat capacity of a substance is constant and is equal to the amount of heat required to raise the temperature of unit mass of the substance by unit degree.

Expert Solution & Answer
Check Mark

Answer to Problem 11STP

The correct answer is the second option, option (B).

Explanation of Solution

Reason for correct option:

The heat released by the combustion of the chips is used to heat up 25.0 mL of water.

Assuming that the density of water is 1.00 g/mL at the temperature of the experiment, the mass of water heated up can be calculated as

Mass of water = (volume of water)×(density of water)=(25.0 mL)×(1.00 g/mL)=25.0 g

Heat gained by water =(mass of water)×(specific heat capacity of water)×(change in temperature of water)=(25.0 g)×(1.00 cal/g.°C)×(6.00°C)=150. cal

(specific heat capacity of water is 1.00 cal/g.°C)

The heat gained by water must have been obtained from the combustion of the chips; thus, the heat released by the combustion of the chips is 150. cal.

Heat released by the combustion of the chips =(mass of the chips)×(energy per gram of chips)

Therefore,

(13.0 g)×(energy per gram of chips)=150. calenergy per gram of chips =(150. cal)(13.0 g)energy per gram of chips =11.53 cal/g11.5 cal/g

Conclusion

Reason for incorrect options:

The mathematical calculation leads to the correct answer as option (B) and thus, all the other options are incorrect.

Chapter U5 Solutions

Living by Chemistry

Ch. U5.95 - Prob. 3ECh. U5.95 - Prob. 4ECh. U5.95 - Prob. 5ECh. U5.96 - Prob. 1TAICh. U5.96 - Prob. 1ECh. U5.96 - Prob. 2ECh. U5.96 - Prob. 3ECh. U5.96 - Prob. 4ECh. U5.96 - Prob. 5ECh. U5.96 - Prob. 6ECh. U5.96 - Prob. 7ECh. U5.96 - Prob. 8ECh. U5.96 - Prob. 9ECh. U5.96 - Prob. 10ECh. U5.96 - Prob. 11ECh. U5.97 - Prob. 1TAICh. U5.97 - Prob. 1ECh. U5.97 - Prob. 2ECh. U5.97 - Prob. 3ECh. U5.97 - Prob. 4ECh. U5.97 - Prob. 5ECh. U5.97 - Prob. 6ECh. U5.97 - Prob. 7ECh. U5.98 - Prob. 1TAICh. U5.98 - Prob. 1ECh. U5.98 - Prob. 2ECh. U5.98 - Prob. 3ECh. U5.98 - Prob. 4ECh. U5.98 - Prob. 5ECh. U5.98 - Prob. 6ECh. U5.98 - Prob. 7ECh. U5.98 - Prob. 8ECh. U5.98 - Prob. 9ECh. U5.98 - Prob. 10ECh. U5.99 - Prob. 1TAICh. U5.99 - Prob. 1ECh. U5.99 - Prob. 2ECh. U5.99 - Prob. 3ECh. U5.99 - Prob. 4ECh. U5.99 - Prob. 5ECh. U5.99 - Prob. 6ECh. U5.99 - Prob. 7ECh. U5.99 - Prob. 8ECh. U5.99 - Prob. 9ECh. U5.100 - Prob. 1TAICh. U5.100 - Prob. 1ECh. U5.100 - Prob. 2ECh. U5.100 - Prob. 3ECh. U5.100 - Prob. 4ECh. U5.100 - Prob. 5ECh. U5.101 - Prob. 1TAICh. U5.101 - Prob. 1ECh. U5.101 - Prob. 2ECh. U5.101 - Prob. 3ECh. U5.101 - Prob. 4ECh. U5.101 - Prob. 6ECh. U5.102 - Prob. 1TAICh. U5.102 - Prob. 1ECh. U5.102 - Prob. 2ECh. U5.102 - Prob. 3ECh. U5.102 - Prob. 4ECh. U5.102 - Prob. 5ECh. U5.102 - Prob. 6ECh. U5.102 - Prob. 8ECh. U5.103 - Prob. 1TAICh. U5.103 - Prob. 1ECh. U5.103 - Prob. 2ECh. U5.103 - Prob. 3ECh. U5.103 - Prob. 4ECh. U5.103 - Prob. 5ECh. U5.103 - Prob. 6ECh. U5.104 - Prob. 1TAICh. U5.104 - Prob. 1ECh. U5.104 - Prob. 2ECh. U5.104 - Prob. 3ECh. U5.104 - Prob. 4ECh. U5.104 - Prob. 5ECh. U5.104 - Prob. 6ECh. U5.104 - Prob. 7ECh. U5.104 - Prob. 8ECh. U5.104 - Prob. 9ECh. U5.105 - Prob. 1TAICh. U5.105 - Prob. 1ECh. U5.105 - Prob. 2ECh. U5.105 - Prob. 3ECh. U5.105 - Prob. 4ECh. U5.105 - Prob. 5ECh. U5.106 - Prob. 1TAICh. U5.106 - Prob. 1ECh. U5.106 - Prob. 2ECh. U5.106 - Prob. 3ECh. U5.106 - Prob. 4ECh. U5.106 - Prob. 5ECh. U5.106 - Prob. 6ECh. U5.106 - Prob. 7ECh. U5.106 - Prob. 8ECh. U5.106 - Prob. 9ECh. U5.106 - Prob. 11ECh. U5.107 - Prob. 1TAICh. U5.107 - Prob. 1ECh. U5.107 - Prob. 2ECh. U5.107 - Prob. 3ECh. U5.107 - Prob. 4ECh. U5.108 - Prob. 1TAICh. U5.108 - Prob. 1ECh. U5.108 - Prob. 2ECh. U5.108 - Prob. 3ECh. U5.108 - Prob. 4ECh. U5.108 - Prob. 5ECh. U5.109 - Prob. 1TAICh. U5.109 - Prob. 1ECh. U5.109 - Prob. 2ECh. U5.109 - Prob. 3ECh. U5.109 - Prob. 4ECh. U5.109 - Prob. 5ECh. U5.109 - Prob. 6ECh. U5.109 - Prob. 7ECh. U5.109 - Prob. 8ECh. U5.110 - Prob. 1TAICh. U5.110 - Prob. 1ECh. U5.110 - Prob. 2ECh. U5.110 - Prob. 3ECh. U5.110 - Prob. 4ECh. U5.110 - Prob. 5ECh. U5.110 - Prob. 6ECh. U5.110 - Prob. 7ECh. U5.111 - Prob. 1TAICh. U5.111 - Prob. 1ECh. U5.111 - Prob. 2ECh. U5.111 - Prob. 3ECh. U5.111 - Prob. 4ECh. U5.111 - Prob. 5ECh. U5.111 - Prob. 6ECh. U5.111 - Prob. 7ECh. U5.111 - Prob. 8ECh. U5.111 - Prob. 9ECh. U5.112 - Prob. 1TAICh. U5.112 - Prob. 1ECh. U5.112 - Prob. 2ECh. U5.112 - Prob. 3ECh. U5.112 - Prob. 4ECh. U5.112 - Prob. 5ECh. U5.112 - Prob. 6ECh. U5.112 - Prob. 7ECh. U5.113 - Prob. 1TAICh. U5.113 - Prob. 1ECh. U5.113 - Prob. 2ECh. U5.113 - Prob. 3ECh. U5.113 - Prob. 4ECh. U5.113 - Prob. 5ECh. U5.113 - Prob. 6ECh. U5.113 - Prob. 7ECh. U5.113 - Prob. 8ECh. U5.114 - Prob. 1TAICh. U5.114 - Prob. 1ECh. U5.114 - Prob. 2ECh. U5.114 - Prob. 3ECh. U5.114 - Prob. 4ECh. U5.114 - Prob. 5ECh. U5.114 - Prob. 6ECh. U5.115 - Prob. 1TAICh. U5.115 - Prob. 1ECh. U5.115 - Prob. 2ECh. U5.115 - Prob. 3ECh. U5.115 - Prob. 4ECh. U5.115 - Prob. 5ECh. U5.115 - Prob. 6ECh. U5.115 - Prob. 7ECh. U5.116 - Prob. 1TAICh. U5.116 - Prob. 1ECh. U5.116 - Prob. 2ECh. U5.116 - Prob. 3ECh. U5.116 - Prob. 4ECh. U5.116 - Prob. 5ECh. U5.116 - Prob. 6ECh. U5.116 - Prob. 7ECh. U5.116 - Prob. 8ECh. U5 - Prob. C18.1RECh. U5 - Prob. C18.2RECh. U5 - Prob. C18.3RECh. U5 - Prob. C18.4RECh. U5 - Prob. C18.5RECh. U5 - Prob. C18.6RECh. U5 - Prob. C18.7RECh. U5 - Prob. C18.8RECh. U5 - Prob. C19.1RECh. U5 - Prob. C19.2RECh. U5 - Prob. C19.3RECh. U5 - Prob. C19.4RECh. U5 - Prob. C20.1RECh. U5 - Prob. C20.2RECh. U5 - Prob. C20.3RECh. U5 - Prob. C20.4RECh. U5 - Prob. C20.6RECh. U5 - Prob. C21.1RECh. U5 - Prob. C21.2RECh. U5 - Prob. C21.3RECh. U5 - Prob. C21.4RECh. U5 - Prob. C21.5RECh. U5 - Prob. 1RECh. U5 - Prob. 2RECh. U5 - Prob. 3RECh. U5 - Prob. 4RECh. U5 - Prob. 5RECh. U5 - Prob. 6RECh. U5 - Prob. 7RECh. U5 - Prob. 8RECh. U5 - Prob. 9RECh. U5 - Prob. 10RECh. U5 - Prob. 11RECh. U5 - Prob. 12RECh. U5 - Prob. 13RECh. U5 - Prob. 14RECh. U5 - Prob. 15RECh. U5 - Prob. 16RECh. U5 - Prob. 17RECh. U5 - Prob. 1STPCh. U5 - Prob. 2STPCh. U5 - Prob. 3STPCh. U5 - Prob. 4STPCh. U5 - Prob. 5STPCh. U5 - Prob. 6STPCh. U5 - Prob. 7STPCh. U5 - Prob. 8STPCh. U5 - Prob. 9STPCh. U5 - Prob. 10STPCh. U5 - Prob. 11STPCh. U5 - Prob. 12STPCh. U5 - Prob. 13STPCh. U5 - Prob. 14STPCh. U5 - Prob. 15STPCh. U5 - Prob. 16STPCh. U5 - Prob. 17STPCh. U5 - Prob. 18STPCh. U5 - Prob. 19STPCh. U5 - Prob. 20STPCh. U5 - Prob. 21STPCh. U5 - Prob. 22STP

Additional Science Textbook Solutions

Find more solutions based on key concepts
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY