EBK FOUNDATIONS OF COLLEGE CHEMISTRY15th EditionWillard Publisher: JOHN WILEY+SONS INC.ISBN: 9781118930144
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
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Chapter 1 - An Introduction To ChemistryChapter 1.1 - The Nature Of ChemistryChapter 1.4 - Classifying MatterChapter 2 - Standards For MeasurementChapter 2.1 - Scientific NotationChapter 2.2 - Measurement And UncertaintyChapter 2.3 - Significant FiguresChapter 2.4 - Significant Figures In CalculationsChapter 2.5 - The Metric SystemChapter 2.6 - Dimensional Analysis: A Problem-solving Method
Chapter 2.7 - PercentChapter 2.8 - Measurement Of TemperatureChapter 2.9 - DensityChapter 3 - Elements And CompoundsChapter 3.1 - ElementsChapter 3.2 - Introduction To The Periodic TableChapter 3.3 - Compounds And FormulasChapter 4 - Properties Of MatterChapter 4.1 - Properties Of SubstancesChapter 4.2 - Physical And Chemical ChangesChapter 4.5 - Heat: Quantitative MeasurementChapter 5 - Early Atomic Theory And StructureChapter 5.1 - Dalton’s Model Of The AtomChapter 5.2 - Electric ChargeChapter 5.3 - Subatomic Parts Of The AtomChapter 5.4 - The Nuclear AtomChapter 5.5 - Isotopes Of The ElementsChapter 5.6 - Atomic MassChapter 6 - Nomenclature Of Inorganic CompoundsChapter 6.2 - Elements And IonsChapter 6.3 - Writing Formulas From Names Of Ionic CompoundsChapter 6.4 - Naming Binary CompoundsChapter 6.5 - Naming Compounds Containing Polyatomic IonsChapter 6.6 - AcidsChapter 7 - Quantitative Composition Of CompoundsChapter 7.1 - The MoleChapter 7.2 - Molar Mass Of CompoundsChapter 7.3 - Percent Composition Of CompoundsChapter 7.4 - Calculating Empirical FormulasChapter 7.5 - Calculating The Molecular Formula From The Empirical FormulaChapter 8 - Chemical EquationsChapter 8.1 - The Chemical EquationChapter 8.2 - Writing And Balancing Chemical EquationsChapter 8.4 - Types Of Chemical EquationsChapter 8.5 - Heat In Chemical ReactionsChapter 9 - Calculations From Chemical EquationsChapter 9.1 - Introduction To StoichiometryChapter 9.2 - Mole–mole CalculationsChapter 9.3 - Mole–mass CalculationsChapter 9.4 - Mass–mass CalculationsChapter 9.5 - Limiting Reactant And Yield CalculationsChapter 10 - Modern Atomic Theory And The Periodic TableChapter 10.1 - Electromagnetic RadiationChapter 10.2 - The Bohr AtomChapter 10.3 - Energy Levels Of ElectronsChapter 10.4 - Atomic Structures Of The First 18 ElementsChapter 10.5 - Electron Structures And The Periodic TableChapter 11 - Chemical Bonds: The Formation Of Compounds From AtomsChapter 11.1 - Periodic Trends In Atomic PropertiesChapter 11.2 - Lewis Structures Of AtomsChapter 11.3 - The Ionic Bond: Transfer Of Electrons From One Atom To AnotherChapter 11.4 - Predicting Formulas Of Ionic CompoundsChapter 11.5 - The Covalent Bond: Sharing ElectronsChapter 11.6 - ElectronegativityChapter 11.7 - Lewis Structures Of CompoundsChapter 11.8 - Complex Lewis StructuresChapter 11.9 - Compounds Containing Polyatomic IonsChapter 11.10 - Molecular ShapeChapter 12 - The Gaseous State Of MatterChapter 12.1 - Properties Of GasesChapter 12.2 - Boyle’s LawChapter 12.3 - Charles’ LawChapter 12.5 - Combined Gas LawsChapter 12.6 - Ideal Gas LawChapter 12.7 - Dalton’s Law Of Partial PressuresChapter 12.8 - Density Of GasesChapter 12.9 - Gas StoichiometryChapter 13 - LiquidsChapter 13.2 - Properties Of LiquidsChapter 13.3 - Boiling Point And Melting PointChapter 13.4 - Changes Of StateChapter 13.5 - Intermolecular ForcesChapter 13.6 - HydratesChapter 14 - SolutionsChapter 14.1 - General Properties Of SolutionsChapter 14.2 - SolubilityChapter 14.3 - Rate Of Dissolving SolidsChapter 14.4 - Concentration Of SolutionsChapter 14.5 - Colligative Properties Of SolutionsChapter 15 - Acids, Bases, And SaltsChapter 15.1 - Acids And BasesChapter 15.2 - SaltsChapter 15.3 - Electrolytes And NonelectrolytesChapter 15.4 - Introduction To PhChapter 15.5 - NeutralizationChapter 15.6 - Writing Net Ionic EquationsChapter 16 - Chemical EquilibriumChapter 16.1 - Rates Of ReactionChapter 16.2 - Chemical EquilibriumChapter 16.3 - Le Châtelier’s PrincipleChapter 16.4 - Equilibrium ConstantsChapter 16.5 - Ion Product Constant For WaterChapter 16.6 - Ionization ConstantsChapter 16.7 - Solubility Product ConstantChapter 16.8 - Buffer Solutions: The Control Of PhChapter 17 - Oxidation–reductionChapter 17.1 - Oxidation NumberChapter 17.2 - Balancing Oxidation–reduction EquationsChapter 17.3 - Balancing Ionic Redox EquationsChapter 17.4 - Activity Series Of MetalsChapter 17.5 - Electrolytic And Voltaic CellsChapter 18 - Nuclear ChemistryChapter 18.1 - Discovery Of RadioactivityChapter 18.2 - Alpha Particles, Beta Particles, And Gamma RaysChapter 18.3 - Radioactive Disintegration SeriesChapter 18.4 - Measurement Of RadioactivityChapter 18.5 - Nuclear EnergyChapter 18.6 - Mass–energy Relationship In Nuclear ReactionsChapter 19 - Introduction To Organic Chemistry (online Only)Chapter 19.2 - Why Carbon?Chapter 19.3 - AlkanesChapter 19.4 - Alkenes And AlkynesChapter 19.5 - Aromatic HydrocarbonsChapter 19.6 - Hydrocarbon DerivativesChapter 19.7 - AlcoholsChapter 19.8 - EthersChapter 19.9 - Aldehydes And KetonesChapter 19.10 - Carboxylic AcidsChapter 19.11 - EstersChapter 19.12 - Polymers—macromoleculesChapter 20 - Introduction To Biochemistry (online Only)Chapter 20.2 - CarbohydratesChapter 20.3 - LipidsChapter 20.4 - Amino Acids And ProteinsChapter 20.5 - EnzymesChapter 20.6 - Nucleic Acids, Dna, And Genetics
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Used by over 750,000 students, Foundations of College Chemistry is praised for its accuracy, clear no-nonsense approach, and direct writing style. Foundations’ direct and straightforward explanations focus on problem solving making
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Hypothesis: A hypothesis is a reasonable guess based on the limited data which acts as a foundation...Incase if a larger number is written in scientific notation the exponent will have a positive number...The calculation for 12.62+1.5+0.25 is, 12.62 1.5 0.25_14.37 The number with the least precision is...The calculation for 15.2-2.75+15.67 is, 15.2-2.7515.67_28.12 The number with the least precision is...The given quantity is 28.0 cm. Centimeters is converted into meters using the conversion factor, (1...The given quantity is 4.5 cm. Centimeters is converted into Ao using the conversion factor, (1 m100...The given quantity is 42.2 in.. Inches is converted into centimeters using the conversion factor,...The given quantity is 35.6 m. Meters is converted into foot using the conversion factor, (100 cm1...Given, The temperature is 162oF. The temperature in Celsius is calculated as,...
Given, The temperature is 32oC. The temperature in Fahrenheit is calculated as,...Given, Liquid in a graduated cylinder is 25.0 mL. Empty mass is 85.450 g. Mass of metal slug is...The mass percent of silicon including earth’s crust, seawater and atmosphere is 25.2%. The mass...The name of the compound Fe2O3 is iron (III) oxide. The number of iron atoms in Fe2O3 is 2. The...The name of the compound HC2H3O2 is acetic acid. The number of carbon atoms in HC2H3O2 is 2. The...The name of the compound Co(ClO3)2 is cobalt (II) chlorate. The number of cobalt atoms in Co(ClO3)2...The name of the compound CH3CH2OH is ethanol. The number of carbon atoms in CH3CH2OH is 2. The...The name of the compound CO is carbon monoxide. The number of carbon atoms in CO is 1. The number of...The table is, Figure 1 The boiling point of acetic acid is 118 oC. The boiling point is the...Features of Dalton’s Model of Atom: 1) Elements are made up of minute, indivisible particles known...The atomic number of 63Cu is 29. The mass number of 63Cu is 63. Atomic number of an element tells...The atomic number of 54Fe is 26. The mass number of 54Fe is 54. Atomic number of an element tells...Given, The mass of one aluminum atom is 4.480×10-23 g. The mass of an electron is 9.1093897×10-27 g....Given, The mass of one selenium atom is 1.311×10-22 g. The mass of a proton is 1.6726219×10-24 g....Two compounds that are often referred by their common names are, 1) Baking soda 2) Wood alcohol...Nickel (II) ion reacts with sulfate ion to form nickel sulfate. In nickel sulfate, the charge on...Barium forms Ba2+ and sulfur forms sulfide S2-.. The formula of the ions are Ba2+ and S2-. The...Aluminum forms Al3+ and sulfur forms sulfide S2-.. The formula of the ions are Al3+ and S2-. The...In silver sulfite, the cation is silver (I) (Ag+) and the anion is sulfite (SO32-). The chemical...In sodium chromate, the cation is sodium (Na+) and the anion is chromate (CrO42-). The chemical...A mole corresponds to the mass of a substance that contains 6.022×1023 particles of the substance....The molecular formula has one potassium atom, and one bromine atoms. The molecular mass of KBr can...Given, The atomic mass of sodium atom =23 g The atomic mass of oxygen atom =16 g The atomic mass of...Given, The number of molecules of P2O5 is 25. There are seven atoms in P2O5 (two phosphorus and five...Given, The number of molecules of CH3COOH is 2. There are eight atoms in CH3COOH (two carbon atoms,...Given, The atomic mass of sodium atom =23 g The atomic mass of bromine atom =80 g The molecular...Given, The atomic mass of Zinc atom =65.39 g The atomic mass of chlorine atom =35.45 g The molecular...Given, The percentage composition of nitrogen is 63.6%. The percentage composition of oxygen is...Given, The percentage composition of copper is 64.1%. The percentage composition of chlorine is...Given, The grams of zinc is 26.08 g. The grams of carbon is 4.79 g. The grams of oxygen is 19.14 g....Given, The molar mass of the compound is 153.8 g. The percentage of carbon is 7.79%. The percentage...Coefficients (or) numbers, which is placed in front of the formulas in a balanced equation,...Hydrogen reacts with oxygen to form water. This reaction is an example of synthesis (or) combination...The given equation is, MnO2+CO→Mn2CO3+CO2 Carbon is balanced. Manganese and oxygen are not balanced....The given equation is, SO2+O2→SO3 Place the coefficient 2 in front of SO2 to balance both sulfur and...The reactants that will react to form the products nickel (II) chloride and lead are nickel and lead...The reaction of ammonium nitrate with barium phosphate results in the formation of barium phosphate...The reaction of barium acetate with potassium sulfate results in the formation of barium sulfate and...Mole ratio: A mole ratio is a ratio between the numbers of moles of any two species involved in a...The given balanced equation is, Ca3P2+6H2O→3Ca(OH)2+2PH3 In the mole ratio, the coefficients of the...The balanced reaction is, MnO2(s)+4 HCl(aq)→Cl2(g)+MnCl2(aq)+2H2O In the mole ratio, the...Given, The mass of Al4C3 is 100 g. The molecular weight of Al4C3 is 144 g. The balanced reaction is,...Given, The number of moles of oxygen is 10 mol. The balanced reaction is, 2C12H4Cl6+23 O2+2H2O→24...Given, The mass of Al (OH)3 is 35 g. The mass of H2SO4 is 35 g. The molecular weight of Al (OH)3 is...Given, The mass of copper is 27.5 g. The mass of HNO3 is 125 g. The molecular weight of copper is...Wavelength: A wavelength is the distance between the consecutive peaks or troughs of a wave. The...The given orbital diagram is, Li ↑↓↑ Lithium is a chemical element with chemical symbol Li and the...The orbital diagram is, ↑↓ ↑↓ ↑↓↑↓↑ ↑ The correct orbital diagrams of (a) is, The total number of...Given elements, Sodium (Na), Magnesium (Mg), Chlorine (Cl), Potassium (K) and Rubidium (Rb). In the...Given molecules, NaO, CO, NO The electronegativity value of Na is 0.9 The electronegativity value of...Given, The mass of sulfur is 1.40 g. The mass of oxygen is 2.10 g. The empirical formula can be...Given, The molar mass of the compound is 166 g/mol. The percentage composition of carbon is 14.5 %....Given compound, H2SO4 The total number of valence electrons in H2SO4 is 32. 1 electron each from two...Pressure represents force produced by substances per unit area on other substances. Therefore...Conversion factor to convert mm Hg to torr is as follows: (1 torr1 mm Hg) Pressure 30.2 in. Hg can...Conversion factor to convert torr to kPa is as follows: (101.325 kPa760 torr) Pressure 953 torr can...Conversion factor to convert torr to kPa is as follows: (101.325 kPa760 torr) Pressure 649 torr can...Expression to calculate final volume of gas is as follows: V2=V1T2T1 (1) Conversion factor to...Expression to calculate final volume of gas is as follows: V2=V1T2T1 (1) Conversion factor to...Chemical equation for reaction between C3H8 and oxygen is as follows: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)...Expression to calculate final pressure of gas is as follows: P2=P1V1V2 (1) Substitute 10 L for V1,...Rearrange expression (1) to calculate volume of gas as follows: V=nRTP (2) Conversion of temperature...Compound contains 80.0 % C and 20.0 % H. Therefore the empirical formula is calculated as follows:...Rearrange expression (1) to calculate value of n as follows: n=PVRT (2) Conversion factor to convert...Rearrange expression (1) to calculate value of n as follows: n=PVRT (2) Conversion factor to convert...Rearrange expression (1) to calculate volume of gas as follows: V=nRTP (2) Conversion of 47 °C to...Water being the first member of the group shows anomalous behavior and is liquid in nature at 0 °C....Molecular mass of MgSO4 is 120.366 g/mol and H2O is 18.02 g/mol. Expression to calculate total mass...Molecular mass of AlCl3 is 133.34 g/mol and H2O is 18.02 g/mol. Expression to calculate total mass...The hydrated iron chloride contains 20.66 g Fe, 39.35 g Cl and 39.99 g H2O. Therefore the empirical...The hydrated nickel chloride contain 24.69 % Ni, 29.83 % Cl and 45.48 % H2O. Therefore the empirical...The formula for calculation of energy absorbed by 75 g of ice is as follows: E=m⋅c⋅(T2−T1) (1) Here,...The formula to calculate mass of water is as follows: moles of H2O=mass of H2Omolar mass of H2O (1)...The formula to calculate energy of ice is as follows: E=m⋅c⋅(T2−T1) (1) Here, E is energy of ice m...True solution is type of solution that contains molecular or ionic-sized constituent particles. Such...Formula for moles of C12H22O11 is as follows: Moles of C12H22O11=Mass of C12H22O11Molar mass of...Expression for mass percent of KCl is as follows: Mass percent of KCl=(Mass of KClMass of...Expression for mass percent of NaNO3 is as follows: Mass percent of NaNO3=(Mass of NaNO3Mass of...Substitute 0.25 mol for moles of solute and 75.0 mL for volume of solution in equation (1). Molarity...Substitute 0.50 mol for moles of solute and 125 mL for volume of solution in equation (1). Molarity...Formula for molarity of K2CrO4 solution is as follows: Molarity of K2CrO4 solution=Moles of...Formula for molarity of H2SO4 solution is as follows: Molarity of H2SO4 solution=Moles of...Given reaction occurs as follows: 3Ca(NO3)2(aq)+2Na3PO4(aq)→Ca3(PO4)2(aq)+6NaNO3 According to...Given reaction occurs as follows: 2NaOH(aq)+H2SO4(aq)→Na2SO4(aq)+2H2O(l) According to balanced...Given reaction occurs as follows: 2KMnO4(aq)+16HCl(aq)→2MnCl2(aq)+5Cl2(g)+8H2O(l)+2KCl(aq)...Given reaction occurs as follows: K2CO3(aq)+2HC2H3O2(aq)→2KC2H3O2(aq)+H2O(l)+CO2(g) Expression for...Expression for molality of CaCl2 is as follows: Molality of CaCl2=Moles of CaCl2Mass(kg) of H2O (1)...Concentration of C12H22O11 solution is 15 %. This indicates that 15 g of C12H22O11 is present in 100...Expression to calculate molarity of Li2CO3 is as follows: Molarity of Li2CO3=Moles of Li2CO3Volume...In accordance with Bronsted definition, the most usual type of acid-base reaction involves lone pair...The formula equation is given as follows: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) Since H2 is gas and Zn is...The formula equation is given as follows: Mg(s)+2HClO4(aq)→Mg(ClO4)2(aq)+H2(g) Since H2 is gas and...1.25 M CuBr2 indicates that in 1 L they moles of CuBr2 is 1.25 mol. CuBr2 can be broken into 1 mol...2.25 M FeCl3 indicates that in 1 L they moles of FeCl3 is 1.25 mol. FeCl3 can be broken into 1 mol...CuBr2 can be broken into 1 mol Cu2+ and 2 mol Br− as follows: CuBr2⇌Cu2++2Br− Since 1 M Cu2+ is...FeCl3 can be broken into 1 mol Fe3+ and 2 mol Cl− as follows: FeCl3⇌Fe3++3Cl− Since 1 M Fe3+ is...Since in 1000 mL the moles of HCl present is 0.50 mol so, moles of HCl in 55.5 mL is calculated as...Since in 1000 mL the moles of NaCl present is 0.10 mol so, moles of NaCl in 45.5 mL is calculated as...The unbalanced equation is written as follows: K3PO4(aq)+Ca(NO3)2(aq)→Ca3(PO4)2(s)+KNO3(aq) (1)...Since in 1000 mL moles of HCl present is 0.2000 mol so, moles of HCl in 50.0 mL is calculated as...For reversible reaction, rate of forward and reverse reaction become equal at some point in time....The equilibrium reaction for Mn(OH)2 is as follows: Mn(OH)2(s)⇌Mn2+(aq)+2OH−(aq) In expression for...The ionization of H2CO3 is as follows: H2CO3(aq)⇌2H+(aq)+CO32−(aq) The expression for Ka for given...The ionization of lactic acid is as follows: HC3H5O2(aq)⇌H+(aq)+C3H5O2−(aq) The expression for Ka...The ionization of phenol, HC6H5O is as follows: HC6H5O(aq)⇌H+(aq)+C6H5O−(aq) The expression for Ka...The ionization of benzoic acid, HC7H5O2 is as follows: HC7H5O2(aq)⇌H+(aq)+C7H5O2−(aq) The expression...The complete ionization of HBr is as follows: HBr(aq)⇌H+(aq)+Br−(aq) The 0.250 M HBr completely...pH is defined as negative logarithm of concentration of H+. It is calculated as follows: pH=−log[H+]...pH is defined as negative logarithm of concentration of H+. It is calculated as follows: pH=−log[H+]...The equilibrium reaction for BaSO4 is as follows: BaSO4(s)⇌Ba+2(aq)+SO42−(aq) In expression for Ksp...The equilibrium reaction for ZnS is as follows: ZnS(s)⇌Zn+2(aq)+S2−(aq) In expression for Ksp molar...The equation of mixture of Na2SO4 and Pb(NO3)2 is as follows: Na2SO4+Pb(NO3)2→PbSO4+NaNO3 The...Given chemical equation is as follows: I2+5Cl2+6H2O→2HIO3+10HCl Oxidation of element in their...Since CuCO3 is not peroxide compound, oxidation state of O is −2. Since copper belongs to d-block...Since fluorine is member of halogen group, its oxidation number is −1. Since CHF3 is not hydride...Oxidation number of H is +1. Expression to calculate the oxidation number of C in CH4 is as follows:...Given reaction is as follows: Cu+O2→CuO (1) Oxidation number of each element in equation (1) can be...Given reaction is as follows: Cu+AgNO3→Ag+Cu(NO3)2 (1) Oxidation number of each element in equation...The oxidation number of each element is assigned as follows:...Given reaction (1) is as follows: C3H8+O2→CO2+H2O Oxidation number of each atom in reaction (1) is...Antoine Henri Becquerel (1852-1908) found radioactivity by experiments with uranium and many other...In the 1st step, T90232h emits α24 particle and reaction is as follows: T90232h→X88228+24He Here, X...Skeleton equation for transition from 88226Ra to 86222Rn is as follows: 88226Ra→86222Rn+ZAX Loss of...Skeleton equation for transition from 82210Pb to 82210Pb is as follows: 82210Pb→82210Pb+ZAX Since...Skeleton equation for transition is as follows: 2966Cu→3066Zn+ _ Since this transition causes atomic...Skeleton equation for transition is as follows: 1327Al+24He→1530P+ _ Since this transition is...Atomic number of chromium-51 is 24 and mass number of chromium-51 is 51. So, number of protons in...In the 1st step, T90232h emits α24 particle and reaction is as follows: T90232h→α24X88228 Here, X is...The nuclear reaction alpha emission is as follows: 511B→Z−2AX+24He (1) The nuclei that should come...Vital force theory: In old days, chemists are believed the organic compounds are not able to...The structural formula of 2,5-dimethyl-3-hexene is, From the given name parent compound is 3-hexene,...The structural formula of 1,2-diphenylethene is, From the given name parent compound is ethene, its...IUPAC name of given compound is, Parent chain name of given compound is 2-hexene, From the structure...IUPAC name of given compound is, Parent chain name of given compound is 1-pentene, From the...The structure for the given condensed structural formula is redrawn by indicating the carbon numbers...The structure for the given condensed structural formula is redrawn by indicating the carbon numbers...The given molecular formula for pentyne is C5H8. The given compound is unsaturated hydrocarbon...The given information in the problem is recored as follows: V =140.3 mLT =100 oCP =740 mm Hgm =0.442...The given common name for the alcohol compound is ethyl alcohol which contains two parts. The first...All the living things require food as a source of energy. Animals consume other plants and animals...
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