Final volume of CO 2 gas if temperature is decreased from 21.0 ° C to − 5 ° C has to be determined. Concept Introduction: Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure. Mathematically relation for Charles’ law is as follows: V ∝ T Or, V 1 T 1 = V 2 T 2 Here, T 1 is initial temperature. T 2 is final temperature. V 1 is initial volume. V 2 is final volume.

Question

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Answer 1

Question

Chapter 12, Problem 13PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is decreased from 21.0 °C to −5 °C has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.114 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert −5 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−5 °C+273=268 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(268 K)294 K)(1 L103 mL)=0.114 L

Hence final volume of CO2 gas is 0.114 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.131 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 95 °F in equation (2).

T(°C)=59(95 °F−32)=35 °C

Conversion factor to convert 35 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=35 °C+273=308 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(308 K)294 K)(1 L103 mL)=0.131 L

Hence final volume of CO2 gas is 0.131 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.466 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Substitute 125 mL for V1, 294 K for T1, and 1095 K for T2 in equation (1).

V2=((125 mL)(1095 K)294 K)(1 L103 mL)=0.466 L

Hence final volume of CO2 gas is 0.466 L.

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Answer 2

Question

Chapter 12, Problem 13PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is decreased from 21.0 °C to −5 °C has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.114 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert −5 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−5 °C+273=268 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(268 K)294 K)(1 L103 mL)=0.114 L

Hence final volume of CO2 gas is 0.114 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.131 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 95 °F in equation (2).

T(°C)=59(95 °F−32)=35 °C

Conversion factor to convert 35 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=35 °C+273=308 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(308 K)294 K)(1 L103 mL)=0.131 L

Hence final volume of CO2 gas is 0.131 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.466 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Substitute 125 mL for V1, 294 K for T1, and 1095 K for T2 in equation (1).

V2=((125 mL)(1095 K)294 K)(1 L103 mL)=0.466 L

Hence final volume of CO2 gas is 0.466 L.

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Answer 3

Question

Chapter 12, Problem 13PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is decreased from 21.0 °C to −5 °C has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.114 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert −5 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−5 °C+273=268 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(268 K)294 K)(1 L103 mL)=0.114 L

Hence final volume of CO2 gas is 0.114 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.131 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 95 °F in equation (2).

T(°C)=59(95 °F−32)=35 °C

Conversion factor to convert 35 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=35 °C+273=308 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(308 K)294 K)(1 L103 mL)=0.131 L

Hence final volume of CO2 gas is 0.131 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.466 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Substitute 125 mL for V1, 294 K for T1, and 1095 K for T2 in equation (1).

V2=((125 mL)(1095 K)294 K)(1 L103 mL)=0.466 L

Hence final volume of CO2 gas is 0.466 L.

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Answer 4

Question

Chapter 12, Problem 13PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is decreased from 21.0 °C to −5 °C has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.114 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert −5 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−5 °C+273=268 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(268 K)294 K)(1 L103 mL)=0.114 L

Hence final volume of CO2 gas is 0.114 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.131 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 95 °F in equation (2).

T(°C)=59(95 °F−32)=35 °C

Conversion factor to convert 35 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=35 °C+273=308 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(308 K)294 K)(1 L103 mL)=0.131 L

Hence final volume of CO2 gas is 0.131 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.466 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Substitute 125 mL for V1, 294 K for T1, and 1095 K for T2 in equation (1).

V2=((125 mL)(1095 K)294 K)(1 L103 mL)=0.466 L

Hence final volume of CO2 gas is 0.466 L.

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Answer 5

Chapter 12, Problem 13PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is decreased from 21.0 °C to −5 °C has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.114 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert −5 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−5 °C+273=268 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(268 K)294 K)(1 L103 mL)=0.114 L

Hence final volume of CO2 gas is 0.114 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.131 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 95 °F in equation (2).

T(°C)=59(95 °F−32)=35 °C

Conversion factor to convert 35 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=35 °C+273=308 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(308 K)294 K)(1 L103 mL)=0.131 L

Hence final volume of CO2 gas is 0.131 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.466 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Substitute 125 mL for V1, 294 K for T1, and 1095 K for T2 in equation (1).

V2=((125 mL)(1095 K)294 K)(1 L103 mL)=0.466 L

Hence final volume of CO2 gas is 0.466 L.

Answer 6

Chapter 12, Problem 13PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is decreased from 21.0 °C to −5 °C has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.114 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert −5 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−5 °C+273=268 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(268 K)294 K)(1 L103 mL)=0.114 L

Hence final volume of CO2 gas is 0.114 L.

Answer 7

Chapter 12, Problem 13PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is decreased from 21.0 °C to −5 °C has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

Answer 8

(a)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.114 L.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert −5 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−5 °C+273=268 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(268 K)294 K)(1 L103 mL)=0.114 L

Hence final volume of CO2 gas is 0.114 L.

Answer 13

(b)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.131 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 95 °F in equation (2).

T(°C)=59(95 °F−32)=35 °C

Conversion factor to convert 35 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=35 °C+273=308 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(308 K)294 K)(1 L103 mL)=0.131 L

Hence final volume of CO2 gas is 0.131 L.

Answer 14

(b)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined.

Concept Introduction:

Refer to part (a).

Answer 15

(b)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.131 L.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 95 °F in equation (2).

T(°C)=59(95 °F−32)=35 °C

Conversion factor to convert 35 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=35 °C+273=308 K

Substitute 125 mL for V1, 294 K for T1, and 268 K for T2 in equation (1).

V2=((125 mL)(308 K)294 K)(1 L103 mL)=0.131 L

Hence final volume of CO2 gas is 0.131 L.

Answer 20

(c)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.466 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Substitute 125 mL for V1, 294 K for T1, and 1095 K for T2 in equation (1).

V2=((125 mL)(1095 K)294 K)(1 L103 mL)=0.466 L

Hence final volume of CO2 gas is 0.466 L.

Answer 21

(c)

Interpretation Introduction

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined.

Concept Introduction:

Refer to part (a).

Answer 22

(c)

Expert Solution

Answer to Problem 13PE

Final volume of CO2 gas is 0.466 L.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert 21.0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=21.0 °C+273=294 K

Substitute 125 mL for V1, 294 K for T1, and 1095 K for T2 in equation (1).

V2=((125 mL)(1095 K)294 K)(1 L103 mL)=0.466 L

Hence final volume of CO2 gas is 0.466 L.

Answer 27

Ch. 12.1 - Prob. 12.1P Ch. 12.2 - Prob. 12.2P Ch. 12.3 - Prob. 12.3P Ch. 12.5 - Prob. 12.4P Ch. 12.5 - Prob. 12.5P Ch. 12.5 - Prob. 12.6P Ch. 12.6 - Prob. 12.7P Ch. 12.6 - Prob. 12.8P Ch. 12.7 - Prob. 12.9P Ch. 12.8 - Prob. 12.10P

Concept explainers

Answer to Problem 13PE

Explanation of Solution

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 13PE

Explanation of Solution

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 13PE

Explanation of Solution

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Chapter 12 Solutions

Concept explainers

Answer to Problem 13PE

Explanation of Solution

Interpretation: Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 13PE

Explanation of Solution

Interpretation: Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 13PE

Explanation of Solution

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Chapter 12 Solutions

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 95 °F has to be determined.

Concept Introduction:

Refer to part (a).

Interpretation:

Final volume of CO2 gas if temperature is changed from 21.0 °C to 1095 K has to be determined.

Concept Introduction:

Refer to part (a).