Chapter 12, Problem 4PE

(a)

Interpretation Introduction

Interpretation:

Conversion of $649\text{ torr}$ pressure into $\text{kPa}$ has to be determined.

Concept Introduction:

Barometer is used for measurement of pressure of gas in atmospheric units $\left(\text{atm}\right)$. Pressure can also be represented in many units such as $\text{torr}$, $\text{mm Hg}$, and pascal $\left(\text{Pa}\right)$. These units can be related to one another as follows:

  $\begin{array}{c}1\text{ atm}=760\text{ torr}\\ =760\text{ mm Hg}\\ =\text{101325 Pa}\\ \text{=101}\text{.325 kPa}\end{array}$

Answer to Problem 4PE

Pressure $649\text{ torr}$ in $\text{kPa}$ units is $86.5\text{ kPa}$.

Explanation of Solution

Conversion factor to convert $\text{torr}$ to $\text{kPa}$ is as follows:

  $\left(\frac{101.325\text{ kPa}}{760\text{ torr}}\right)$

Pressure $649\text{ torr}$ can be converted to $\text{kPa}$ as follows:

  $\begin{array}{c}\text{Pressure}\left(\text{kPa}\right)=\left(649\text{ torr}\right)\left(\frac{101.325\text{ kPa}}{760\text{ torr}}\right)\\ =86.5\text{ kPa}\end{array}$

Hence $649\text{ torr}$ in $\text{kPa}$ units is $86.5\text{ kPa}$.

(b)

Interpretation Introduction

Interpretation:

Conversion of $5.07\text{ kPa}$ pressure into $\text{atm}$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 4PE

Pressure $5.07\text{ kPa}$ in $\text{atm}$ units is $0.0500\text{ atm}$.

Explanation of Solution

Conversion factor to convert $\text{kPa}$ to $\text{atm}$ is as follows:

  $\left(\frac{1\text{ atm}}{101.325\text{ kPa}}\right)$

Pressure $5.07\text{ kPa}$ can be converted to $\text{kPa}$ as follows:

  $\begin{array}{c}\text{Pressure}\left(\text{atm}\right)=\left(5.07\text{ kPa}\right)\left(\frac{1\text{ atm}}{101.325\text{ kPa}}\right)\\ =0.0500\text{ atm}\end{array}$

Hence $5.07\text{ kPa}$ in $\text{atm}$ units is $0.0500\text{ atm}$.

(c)

Interpretation Introduction

Interpretation:

Conversion of $3.64\text{ atm}$ pressure into $\text{mm Hg}$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 4PE

Pressure $3.64\text{ atm}$ in $\text{mm Hg}$ units is $2.77\times {10}^3\text{ mm Hg}$.

Explanation of Solution

Conversion factor to convert $\text{atm}$ to $\text{mm Hg}$ is as follows:

  $\left(\frac{760\text{ mm Hg}}{1\text{ atm}}\right)$

Pressure $3.64\text{ atm}$ can be converted to $\text{mm Hg}$ as follows:

  $\begin{array}{c}\text{Pressure}\left(\text{mm Hg}\right)=\left(3.64\text{ atm}\right)\left(\frac{760\text{ mm Hg}}{1\text{ atm}}\right)\\ =2.77\times {10}^3\text{ mm Hg}\end{array}$

Hence $3.64\text{ atm}$ in $\text{mm Hg}$ units is $2.77\times {10}^3\text{ mm Hg}$.

(d)

Interpretation Introduction

Interpretation:

Conversion of $803\text{ torr}$ pressure into $\text{atm}$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 4PE

Pressure $803\text{ torr}$ in $\text{atm}$ units is $1.06\text{ atm}$.

Explanation of Solution

Conversion factor to convert $\text{torr}$ to $\text{atm}$ is as follows:

  $\left(\frac{1\text{ atm}}{760\text{ torr}}\right)$

Pressure $803\text{ torr}$ can be converted to $\text{atm}$ as follows:

  $\begin{array}{c}\text{Pressure}\left(\text{atm}\right)=\left(803\text{ torr}\right)\left(\frac{1\text{ atm}}{760\text{ torr}}\right)\\ =1.06\text{ atm}\end{array}$

Hence $803\text{ torr}$ in $\text{atm}$ units is $1.06\text{ atm}$.

(e)

Interpretation Introduction

Interpretation:

Conversion of $1.08\text{ atm}$ pressure into $\text{cm Hg}$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 4PE

Pressure $1.08\text{ atm}$ in $\text{cm Hg}$ units is $82.1\text{ cm Hg}$.

Explanation of Solution

Conversion factor to convert $\text{atm}$ to $\text{mm Hg}$ is as follows:

  $\left(\frac{760\text{ mm Hg}}{1\text{ atm}}\right)$

Pressure $1.08\text{ atm}$ can be converted to $\text{cm Hg}$ as follows:

  $\begin{array}{c}\text{Pressure}\left(\text{cm Hg}\right)=\left(1.08\text{ atm}\right)\left(\frac{760\text{ mm Hg}}{1\text{ atm}}\right)\left(\frac{\text{1 cm Hg}}{10\text{ mm Hg}}\right)\\ =82.1\text{ cm Hg}\end{array}$

Hence $1.08\text{ atm}$ in $\text{cm Hg}$ units is $82.1\text{ cm Hg}$.