Conversion of 953 torr pressure into kPa has to be determined. Concept Introduction: Barometer is used for measurement of pressure of gas in atmospheric units ( atm ) . Pressure can also be represented in many units such as torr , mm Hg , and pascal ( Pa ) . These units can be related to one another as follows: 1 atm = 760 torr = 760 mm Hg = 101325 Pa =101 .325 kPa

Question

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Answer 1

Question

Chapter 12, Problem 3PE

(a)

Interpretation Introduction

Interpretation:

Conversion of $953 torr$ pressure into $kPa$ has to be determined.

Concept Introduction:

Barometer is used for measurement of pressure of gas in atmospheric units $(atm)$ . Pressure can also be represented in many units such as $torr$ , $mm Hg$ , and pascal $(Pa)$ . These units can be related to one another as follows:

$1 atm=760 torr=760 mm Hg=101325 Pa=101.325 kPa$

(a)

Expert Solution

Answer to Problem 3PE

Pressure $953 torr$ in $kPa$ units is $127 kPa$ .

Explanation of Solution

Conversion factor to convert $torr$ to $kPa$ is as follows:

$(101.325 kPa760 torr)$

Pressure $953 torr$ can be converted to $kPa$ as follows:

$Pressure(kPa)=(953 torr)(101.325 kPa760 torr)=127 kPa$

Hence $953 torr$ in $kPa$ units is $127 kPa$ .

(b)

Interpretation Introduction

Interpretation:

Conversion of $2.98 kPa$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3PE

Pressure $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

Explanation of Solution

Conversion factor to convert $kPa$ to $atm$ is as follows:

$(1 atm101.325 kPa)$

Pressure $1.12 atm$ can be converted to $kPa$ as follows:

$Pressure(atm)=(2.98 kPa)(1 atm101.325 kPa)=0.0294 atm$

Hence $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

(c)

Interpretation Introduction

Interpretation:

Conversion of $2.77 atm$ pressure into $mm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3PE

Pressure $2.77 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.77 atm$ can be converted to $mm Hg$ as follows:

$Pressure(mm Hg)=(2.77 atm)(760 mm Hg1 atm)=2.11×103 mm Hg$

Hence $1.12 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

(d)

Interpretation Introduction

Interpretation:

Conversion of $372 torr$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(d)

Expert Solution

Answer to Problem 3PE

Pressure $372 torr$ in $atm$ units is $0.489 atm$ .

Explanation of Solution

Conversion factor to convert $torr$ to $atm$ is as follows:

$(1 atm760 torr)$

Pressure $372 torr$ can be converted to $atm$ as follows:

$Pressure(atm)=(372 torr)(1 atm760 torr)=0.489 atm$

Hence $372 torr$ in $atm$ units is $0.489 atm$ .

(e)

Interpretation Introduction

Interpretation:

Conversion of $2.81 atm$ pressure into $cm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(e)

Expert Solution

Answer to Problem 3PE

Pressure $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.81 atm$ can be converted to $cm Hg$ as follows:

$Pressure(cm Hg)=(2.81 atm)(760 mm Hg1 atm)(1 cm Hg10 mm Hg)=214 cm Hg$

Hence $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

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Answer 2

Question

Chapter 12, Problem 3PE

(a)

Interpretation Introduction

Interpretation:

Conversion of $953 torr$ pressure into $kPa$ has to be determined.

Concept Introduction:

Barometer is used for measurement of pressure of gas in atmospheric units $(atm)$ . Pressure can also be represented in many units such as $torr$ , $mm Hg$ , and pascal $(Pa)$ . These units can be related to one another as follows:

$1 atm=760 torr=760 mm Hg=101325 Pa=101.325 kPa$

(a)

Expert Solution

Answer to Problem 3PE

Pressure $953 torr$ in $kPa$ units is $127 kPa$ .

Explanation of Solution

Conversion factor to convert $torr$ to $kPa$ is as follows:

$(101.325 kPa760 torr)$

Pressure $953 torr$ can be converted to $kPa$ as follows:

$Pressure(kPa)=(953 torr)(101.325 kPa760 torr)=127 kPa$

Hence $953 torr$ in $kPa$ units is $127 kPa$ .

(b)

Interpretation Introduction

Interpretation:

Conversion of $2.98 kPa$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3PE

Pressure $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

Explanation of Solution

Conversion factor to convert $kPa$ to $atm$ is as follows:

$(1 atm101.325 kPa)$

Pressure $1.12 atm$ can be converted to $kPa$ as follows:

$Pressure(atm)=(2.98 kPa)(1 atm101.325 kPa)=0.0294 atm$

Hence $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

(c)

Interpretation Introduction

Interpretation:

Conversion of $2.77 atm$ pressure into $mm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3PE

Pressure $2.77 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.77 atm$ can be converted to $mm Hg$ as follows:

$Pressure(mm Hg)=(2.77 atm)(760 mm Hg1 atm)=2.11×103 mm Hg$

Hence $1.12 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

(d)

Interpretation Introduction

Interpretation:

Conversion of $372 torr$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(d)

Expert Solution

Answer to Problem 3PE

Pressure $372 torr$ in $atm$ units is $0.489 atm$ .

Explanation of Solution

Conversion factor to convert $torr$ to $atm$ is as follows:

$(1 atm760 torr)$

Pressure $372 torr$ can be converted to $atm$ as follows:

$Pressure(atm)=(372 torr)(1 atm760 torr)=0.489 atm$

Hence $372 torr$ in $atm$ units is $0.489 atm$ .

(e)

Interpretation Introduction

Interpretation:

Conversion of $2.81 atm$ pressure into $cm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(e)

Expert Solution

Answer to Problem 3PE

Pressure $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.81 atm$ can be converted to $cm Hg$ as follows:

$Pressure(cm Hg)=(2.81 atm)(760 mm Hg1 atm)(1 cm Hg10 mm Hg)=214 cm Hg$

Hence $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

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Answer 3

Question

Chapter 12, Problem 3PE

(a)

Interpretation Introduction

Interpretation:

Conversion of $953 torr$ pressure into $kPa$ has to be determined.

Concept Introduction:

Barometer is used for measurement of pressure of gas in atmospheric units $(atm)$ . Pressure can also be represented in many units such as $torr$ , $mm Hg$ , and pascal $(Pa)$ . These units can be related to one another as follows:

$1 atm=760 torr=760 mm Hg=101325 Pa=101.325 kPa$

(a)

Expert Solution

Answer to Problem 3PE

Pressure $953 torr$ in $kPa$ units is $127 kPa$ .

Explanation of Solution

Conversion factor to convert $torr$ to $kPa$ is as follows:

$(101.325 kPa760 torr)$

Pressure $953 torr$ can be converted to $kPa$ as follows:

$Pressure(kPa)=(953 torr)(101.325 kPa760 torr)=127 kPa$

Hence $953 torr$ in $kPa$ units is $127 kPa$ .

(b)

Interpretation Introduction

Interpretation:

Conversion of $2.98 kPa$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3PE

Pressure $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

Explanation of Solution

Conversion factor to convert $kPa$ to $atm$ is as follows:

$(1 atm101.325 kPa)$

Pressure $1.12 atm$ can be converted to $kPa$ as follows:

$Pressure(atm)=(2.98 kPa)(1 atm101.325 kPa)=0.0294 atm$

Hence $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

(c)

Interpretation Introduction

Interpretation:

Conversion of $2.77 atm$ pressure into $mm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3PE

Pressure $2.77 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.77 atm$ can be converted to $mm Hg$ as follows:

$Pressure(mm Hg)=(2.77 atm)(760 mm Hg1 atm)=2.11×103 mm Hg$

Hence $1.12 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

(d)

Interpretation Introduction

Interpretation:

Conversion of $372 torr$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(d)

Expert Solution

Answer to Problem 3PE

Pressure $372 torr$ in $atm$ units is $0.489 atm$ .

Explanation of Solution

Conversion factor to convert $torr$ to $atm$ is as follows:

$(1 atm760 torr)$

Pressure $372 torr$ can be converted to $atm$ as follows:

$Pressure(atm)=(372 torr)(1 atm760 torr)=0.489 atm$

Hence $372 torr$ in $atm$ units is $0.489 atm$ .

(e)

Interpretation Introduction

Interpretation:

Conversion of $2.81 atm$ pressure into $cm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(e)

Expert Solution

Answer to Problem 3PE

Pressure $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.81 atm$ can be converted to $cm Hg$ as follows:

$Pressure(cm Hg)=(2.81 atm)(760 mm Hg1 atm)(1 cm Hg10 mm Hg)=214 cm Hg$

Hence $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

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Answer 4

Question

Chapter 12, Problem 3PE

(a)

Interpretation Introduction

Interpretation:

Conversion of $953 torr$ pressure into $kPa$ has to be determined.

Concept Introduction:

Barometer is used for measurement of pressure of gas in atmospheric units $(atm)$ . Pressure can also be represented in many units such as $torr$ , $mm Hg$ , and pascal $(Pa)$ . These units can be related to one another as follows:

$1 atm=760 torr=760 mm Hg=101325 Pa=101.325 kPa$

(a)

Expert Solution

Answer to Problem 3PE

Pressure $953 torr$ in $kPa$ units is $127 kPa$ .

Explanation of Solution

Conversion factor to convert $torr$ to $kPa$ is as follows:

$(101.325 kPa760 torr)$

Pressure $953 torr$ can be converted to $kPa$ as follows:

$Pressure(kPa)=(953 torr)(101.325 kPa760 torr)=127 kPa$

Hence $953 torr$ in $kPa$ units is $127 kPa$ .

(b)

Interpretation Introduction

Interpretation:

Conversion of $2.98 kPa$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3PE

Pressure $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

Explanation of Solution

Conversion factor to convert $kPa$ to $atm$ is as follows:

$(1 atm101.325 kPa)$

Pressure $1.12 atm$ can be converted to $kPa$ as follows:

$Pressure(atm)=(2.98 kPa)(1 atm101.325 kPa)=0.0294 atm$

Hence $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

(c)

Interpretation Introduction

Interpretation:

Conversion of $2.77 atm$ pressure into $mm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3PE

Pressure $2.77 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.77 atm$ can be converted to $mm Hg$ as follows:

$Pressure(mm Hg)=(2.77 atm)(760 mm Hg1 atm)=2.11×103 mm Hg$

Hence $1.12 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

(d)

Interpretation Introduction

Interpretation:

Conversion of $372 torr$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(d)

Expert Solution

Answer to Problem 3PE

Pressure $372 torr$ in $atm$ units is $0.489 atm$ .

Explanation of Solution

Conversion factor to convert $torr$ to $atm$ is as follows:

$(1 atm760 torr)$

Pressure $372 torr$ can be converted to $atm$ as follows:

$Pressure(atm)=(372 torr)(1 atm760 torr)=0.489 atm$

Hence $372 torr$ in $atm$ units is $0.489 atm$ .

(e)

Interpretation Introduction

Interpretation:

Conversion of $2.81 atm$ pressure into $cm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(e)

Expert Solution

Answer to Problem 3PE

Pressure $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.81 atm$ can be converted to $cm Hg$ as follows:

$Pressure(cm Hg)=(2.81 atm)(760 mm Hg1 atm)(1 cm Hg10 mm Hg)=214 cm Hg$

Hence $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

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Answer 5

Chapter 12, Problem 3PE

(a)

Interpretation Introduction

Interpretation:

Conversion of $953 torr$ pressure into $kPa$ has to be determined.

Concept Introduction:

Barometer is used for measurement of pressure of gas in atmospheric units $(atm)$ . Pressure can also be represented in many units such as $torr$ , $mm Hg$ , and pascal $(Pa)$ . These units can be related to one another as follows:

$1 atm=760 torr=760 mm Hg=101325 Pa=101.325 kPa$

(a)

Expert Solution

Answer to Problem 3PE

Pressure $953 torr$ in $kPa$ units is $127 kPa$ .

Explanation of Solution

Conversion factor to convert $torr$ to $kPa$ is as follows:

$(101.325 kPa760 torr)$

Pressure $953 torr$ can be converted to $kPa$ as follows:

$Pressure(kPa)=(953 torr)(101.325 kPa760 torr)=127 kPa$

Hence $953 torr$ in $kPa$ units is $127 kPa$ .

(b)

Interpretation Introduction

Interpretation:

Conversion of $2.98 kPa$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3PE

Pressure $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

Explanation of Solution

Conversion factor to convert $kPa$ to $atm$ is as follows:

$(1 atm101.325 kPa)$

Pressure $1.12 atm$ can be converted to $kPa$ as follows:

$Pressure(atm)=(2.98 kPa)(1 atm101.325 kPa)=0.0294 atm$

Hence $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

(c)

Interpretation Introduction

Interpretation:

Conversion of $2.77 atm$ pressure into $mm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3PE

Pressure $2.77 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.77 atm$ can be converted to $mm Hg$ as follows:

$Pressure(mm Hg)=(2.77 atm)(760 mm Hg1 atm)=2.11×103 mm Hg$

Hence $1.12 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

(d)

Interpretation Introduction

Interpretation:

Conversion of $372 torr$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(d)

Expert Solution

Answer to Problem 3PE

Pressure $372 torr$ in $atm$ units is $0.489 atm$ .

Explanation of Solution

Conversion factor to convert $torr$ to $atm$ is as follows:

$(1 atm760 torr)$

Pressure $372 torr$ can be converted to $atm$ as follows:

$Pressure(atm)=(372 torr)(1 atm760 torr)=0.489 atm$

Hence $372 torr$ in $atm$ units is $0.489 atm$ .

(e)

Interpretation Introduction

Interpretation:

Conversion of $2.81 atm$ pressure into $cm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(e)

Expert Solution

Answer to Problem 3PE

Pressure $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.81 atm$ can be converted to $cm Hg$ as follows:

$Pressure(cm Hg)=(2.81 atm)(760 mm Hg1 atm)(1 cm Hg10 mm Hg)=214 cm Hg$

Hence $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Answer 6

Chapter 12, Problem 3PE

(a)

Interpretation Introduction

Interpretation:

Conversion of $953 torr$ pressure into $kPa$ has to be determined.

Concept Introduction:

Barometer is used for measurement of pressure of gas in atmospheric units $(atm)$ . Pressure can also be represented in many units such as $torr$ , $mm Hg$ , and pascal $(Pa)$ . These units can be related to one another as follows:

$1 atm=760 torr=760 mm Hg=101325 Pa=101.325 kPa$

(a)

Expert Solution

Answer to Problem 3PE

Pressure $953 torr$ in $kPa$ units is $127 kPa$ .

Explanation of Solution

Conversion factor to convert $torr$ to $kPa$ is as follows:

$(101.325 kPa760 torr)$

Pressure $953 torr$ can be converted to $kPa$ as follows:

$Pressure(kPa)=(953 torr)(101.325 kPa760 torr)=127 kPa$

Hence $953 torr$ in $kPa$ units is $127 kPa$ .

Answer 7

Chapter 12, Problem 3PE

(a)

Interpretation Introduction

Interpretation:

Conversion of $953 torr$ pressure into $kPa$ has to be determined.

Concept Introduction:

Barometer is used for measurement of pressure of gas in atmospheric units $(atm)$ . Pressure can also be represented in many units such as $torr$ , $mm Hg$ , and pascal $(Pa)$ . These units can be related to one another as follows:

$1 atm=760 torr=760 mm Hg=101325 Pa=101.325 kPa$

Answer 8

(a)

Expert Solution

Answer to Problem 3PE

Pressure $953 torr$ in $kPa$ units is $127 kPa$ .

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Conversion factor to convert $torr$ to $kPa$ is as follows:

$(101.325 kPa760 torr)$

Pressure $953 torr$ can be converted to $kPa$ as follows:

$Pressure(kPa)=(953 torr)(101.325 kPa760 torr)=127 kPa$

Hence $953 torr$ in $kPa$ units is $127 kPa$ .

Answer 13

(b)

Interpretation Introduction

Interpretation:

Conversion of $2.98 kPa$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3PE

Pressure $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

Explanation of Solution

Conversion factor to convert $kPa$ to $atm$ is as follows:

$(1 atm101.325 kPa)$

Pressure $1.12 atm$ can be converted to $kPa$ as follows:

$Pressure(atm)=(2.98 kPa)(1 atm101.325 kPa)=0.0294 atm$

Hence $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

Answer 14

(b)

Interpretation Introduction

Interpretation:

Conversion of $2.98 kPa$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer 15

(b)

Expert Solution

Answer to Problem 3PE

Pressure $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Conversion factor to convert $kPa$ to $atm$ is as follows:

$(1 atm101.325 kPa)$

Pressure $1.12 atm$ can be converted to $kPa$ as follows:

$Pressure(atm)=(2.98 kPa)(1 atm101.325 kPa)=0.0294 atm$

Hence $2.98 kPa$ in $atm$ units is $0.0294 atm$ .

Answer 20

(c)

Interpretation Introduction

Interpretation:

Conversion of $2.77 atm$ pressure into $mm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3PE

Pressure $2.77 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.77 atm$ can be converted to $mm Hg$ as follows:

$Pressure(mm Hg)=(2.77 atm)(760 mm Hg1 atm)=2.11×103 mm Hg$

Hence $1.12 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

Answer 21

(c)

Interpretation Introduction

Interpretation:

Conversion of $2.77 atm$ pressure into $mm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer 22

(c)

Expert Solution

Answer to Problem 3PE

Pressure $2.77 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.77 atm$ can be converted to $mm Hg$ as follows:

$Pressure(mm Hg)=(2.77 atm)(760 mm Hg1 atm)=2.11×103 mm Hg$

Hence $1.12 atm$ in $mm Hg$ units is $2.11×103 mm Hg$ .

Answer 27

(d)

Interpretation Introduction

Interpretation:

Conversion of $372 torr$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

(d)

Expert Solution

Answer to Problem 3PE

Pressure $372 torr$ in $atm$ units is $0.489 atm$ .

Explanation of Solution

Conversion factor to convert $torr$ to $atm$ is as follows:

$(1 atm760 torr)$

Pressure $372 torr$ can be converted to $atm$ as follows:

$Pressure(atm)=(372 torr)(1 atm760 torr)=0.489 atm$

Hence $372 torr$ in $atm$ units is $0.489 atm$ .

Answer 28

(d)

Interpretation Introduction

Interpretation:

Conversion of $372 torr$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer 29

(d)

Expert Solution

Answer to Problem 3PE

Pressure $372 torr$ in $atm$ units is $0.489 atm$ .

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Conversion factor to convert $torr$ to $atm$ is as follows:

$(1 atm760 torr)$

Pressure $372 torr$ can be converted to $atm$ as follows:

$Pressure(atm)=(372 torr)(1 atm760 torr)=0.489 atm$

Hence $372 torr$ in $atm$ units is $0.489 atm$ .

Answer 34

(e)

Interpretation Introduction

Interpretation:

Conversion of $2.81 atm$ pressure into $cm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

(e)

Expert Solution

Answer to Problem 3PE

Pressure $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.81 atm$ can be converted to $cm Hg$ as follows:

$Pressure(cm Hg)=(2.81 atm)(760 mm Hg1 atm)(1 cm Hg10 mm Hg)=214 cm Hg$

Hence $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Answer 35

(e)

Interpretation Introduction

Interpretation:

Conversion of $2.81 atm$ pressure into $cm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer 36

(e)

Expert Solution

Answer to Problem 3PE

Pressure $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Conversion factor to convert $atm$ to $mm Hg$ is as follows:

$(760 mm Hg1 atm)$

Pressure $2.81 atm$ can be converted to $cm Hg$ as follows:

$Pressure(cm Hg)=(2.81 atm)(760 mm Hg1 atm)(1 cm Hg10 mm Hg)=214 cm Hg$

Hence $2.81 atm$ in $cm Hg$ units is $214 cm Hg$ .

Answer 41

Ch. 12.1 - Prob. 12.1P Ch. 12.2 - Prob. 12.2P Ch. 12.3 - Prob. 12.3P Ch. 12.5 - Prob. 12.4P Ch. 12.5 - Prob. 12.5P Ch. 12.5 - Prob. 12.6P Ch. 12.6 - Prob. 12.7P Ch. 12.6 - Prob. 12.8P Ch. 12.7 - Prob. 12.9P Ch. 12.8 - Prob. 12.10P

Concept explainers

Videos

Answer to Problem 3PE

Explanation of Solution

Interpretation:

Conversion of $2.98 kPa$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 3PE

Explanation of Solution

Interpretation:

Conversion of $2.77 atm$ pressure into $mm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 3PE

Explanation of Solution

Interpretation:

Conversion of $372 torr$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 3PE

Explanation of Solution

Interpretation:

Conversion of $2.81 atm$ pressure into $cm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 3PE

Explanation of Solution

Want to see more full solutions like this?

Chapter 12 Solutions

Concept explainers

Videos

Answer to Problem 3PE

Explanation of Solution

Interpretation: Conversion of 2.98 kPa<m:math><m:mrow><m:mn>2.98</m:mn><m:mtext> kPa</m:mtext></m:mrow></m:math> pressure into atm<m:math><m:mrow><m:mtext>atm</m:mtext></m:mrow></m:math> has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 3PE

Explanation of Solution

Interpretation: Conversion of 2.77 atm<m:math><m:mrow><m:mn>2.77</m:mn><m:mtext> atm</m:mtext></m:mrow></m:math> pressure into mm Hg<m:math><m:mrow><m:mtext>mm Hg</m:mtext></m:mrow></m:math> has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 3PE

Explanation of Solution

Interpretation: Conversion of 372 torr<m:math><m:mrow><m:mn>372</m:mn><m:mtext> torr</m:mtext></m:mrow></m:math> pressure into atm<m:math><m:mrow><m:mtext>atm</m:mtext></m:mrow></m:math> has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 3PE

Explanation of Solution

Interpretation: Conversion of 2.81 atm<m:math><m:mrow><m:mn>2.81</m:mn><m:mtext> atm</m:mtext></m:mrow></m:math> pressure into cm Hg<m:math><m:mrow><m:mtext>cm Hg</m:mtext></m:mrow></m:math> has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 3PE

Explanation of Solution

Want to see more full solutions like this?

Chapter 12 Solutions

Interpretation:

Conversion of $2.98 kPa$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

Interpretation:

Conversion of $2.77 atm$ pressure into $mm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).

Interpretation:

Conversion of $372 torr$ pressure into $atm$ has to be determined.

Concept Introduction:

Refer to part (a).

Interpretation:

Conversion of $2.81 atm$ pressure into $cm Hg$ has to be determined.

Concept Introduction:

Refer to part (a).