Chapter 2, Problem 22PE

(a)

Interpretation Introduction

Interpretation:

The quantity $\text{35}\text{.6}\text{m}$ has to be converted into foot.

Answer to Problem 22PE

The quantity $\text{35}\text{.6}\text{m}$ in foot is $\text{117}\text{ft}\text{.}$

Explanation of Solution

The given quantity is $\text{35}\text{.6}\text{m}\text{.}$

Meters is converted into foot using the conversion factor,

  $\left(\frac{\text{100}\text{cm}}{\text{1}\text{m}}\right)\left(\frac{\text{1}\text{in}\text{.}}{\text{2}\text{.54}\text{cm}}\right)\left(\frac{\text{1}\text{ft}}{\text{12}\text{in}\text{.}}\right)$

The quantity $\text{35}\text{.6}\text{m}$ is converted as,

  $\begin{array}{l}\text{ft=}\left(\text{35}\text{.6}\text{m}\right)\left(\frac{\text{100}\text{cm}}{\text{1}\text{m}}\right)\left(\frac{\text{1}\text{in}\text{.}}{\text{2}\text{.54}\text{cm}}\right)\left(\frac{\text{1}\text{ft}}{\text{12}\text{in}\text{.}}\right)\\ \text{ft=117}\text{ft}\end{array}$

The quantity $\text{35}\text{.6}\text{m}$ in foot is $\text{117}\text{ft}\text{.}$

(b)

Interpretation Introduction

Interpretation:

The quantity $\text{16}\text{.5}\text{km}$ has to be converted into miles.

Answer to Problem 22PE

The quantity $\text{16}\text{.5}\text{km}$ in miles is $\text{10}\text{.3 mi}\text{.}$

Explanation of Solution

The given quantity is $\text{16}\text{.5}\text{km}\text{.}$

Kilometers is converted into miles using the conversion factor,

  $\left(\frac{\text{1}\text{mi}}{\text{1}\text{.609}\text{km}}\right)$

The quantity $\text{16}\text{.5}\text{km}$ is converted as,

  $\begin{array}{l}\text{km=}\left(\text{16}\text{.5}\text{km}\right)\left(\frac{\text{1}\text{mi}}{\text{1}\text{.609}\text{km}}\right)\\ \text{km=10}\text{.3}\text{km}\end{array}$

The quantity $\text{16}\text{.5}\text{km}$ in miles is $\text{10}\text{.3 mi}\text{.}$

(c)

Interpretation Introduction

Interpretation:

The quantity $\text{4}\text{.5}\text{in}{\text{.}}^{\text{3}}$ has to be converted into millimeter cube $\left({\text{mm}}^{\text{3}}\right)\text{.}$

Answer to Problem 22PE

The quantity $\text{4}\text{.5}\text{in}{\text{.}}^{\text{3}}$ in millimeter cube is $\text{7}{\text{.4×10}}^{\text{4}}{\text{mm}}^{\text{3}}\text{.}$

Explanation of Solution

The given quantity is $\text{4}\text{.5}\text{in}{\text{.}}^{\text{3}}.$

Cubic inches is converted into millimeter cube using the conversion factor,

  ${\left(\frac{\text{2}\text{.54}\text{cm}}{\text{1}\text{in}\text{.}}\right)}^{\text{3}}{\left(\frac{\text{10}\text{mm}}{\text{1}\text{cm}}\right)}^{\text{3}}$

The quantity $\text{4}\text{.5}\text{in}{\text{.}}^{\text{3}}$ is converted as,

  $\begin{array}{l}{\text{mm}}^{\text{3}}\text{=}\left(\text{4}\text{.5}\text{in}{\text{.}}^{\text{3}}\right){\left(\frac{\text{2}\text{.54}\text{cm}}{\text{1}\text{in}\text{.}}\right)}^{\text{3}}{\left(\frac{\text{10}\text{mm}}{\text{1}\text{cm}}\right)}^{\text{3}}\\ {\text{mm}}^{\text{3}}\text{=7}{\text{.4×10}}^{\text{4}}{\text{mm}}^{\text{3}}\end{array}$

The quantity $\text{4}\text{.5}\text{in}{\text{.}}^{\text{3}}$ in millimeter cube is $\text{7}{\text{.4×10}}^{\text{4}}{\text{mm}}^{\text{3}}\text{.}$

(d)

Interpretation Introduction

Interpretation:

The quantity $\text{95}\text{lb}$ has to be converted into grams.

Answer to Problem 22PE

The quantity $\text{95}\text{lb}$ in grams is $\text{4}{\text{.3×10}}^{\text{4}}\text{g}\text{.}$

Explanation of Solution

The given quantity is $\text{95}\text{lb}\text{.}$

Pounds is converted into grams using the conversion factor,

  $\left(\frac{\text{453}\text{.6 g}}{\text{1}\text{lb}}\right)$

The quantity $\text{95}\text{lb}$ is converted as,

  $\begin{array}{l}\text{g=}\left(\text{95}\text{lb}\right)\left(\frac{\text{453}\text{.6 g}}{\text{1}\text{lb}}\right)\\ \text{g=4}{\text{.3×10}}^{\text{4}}\text{g}\end{array}$

The quantity $\text{95}\text{lb}$ in grams is $\text{4}{\text{.3×10}}^{\text{4}}\text{g}\text{.}$

(e)

Interpretation Introduction

Interpretation:

The quantity $\text{20}\text{.0 gal}$ has to be converted into liters.

Answer to Problem 22PE

The quantity $\text{20}\text{.0 gal}$ in liters is $\text{75}\text{.7}\text{L}\text{.}$

Explanation of Solution

The given quantity is $\text{20}\text{.0 gal}\text{.}$

Gallons is converted into liters using the conversion factor,

  $\left(\frac{\text{4}\text{qt}}{\text{1}\text{gal}}\right)\left(\frac{\text{0}\text{.946}\text{mL}}{\text{1qt}}\right)$

The quantity $\text{20}\text{.0 gal}$ is converted as,

  $\begin{array}{l}\text{L=}\left(\text{20}\text{.0}\text{gal}\right)\left(\frac{\text{4}\text{qt}}{\text{1}\text{gal}}\right)\left(\frac{\text{0}\text{.946}\text{mL}}{\text{1qt}}\right)\\ \text{L=75}\text{.7 L}\end{array}$

The quantity $\text{20}\text{.0 gal}$ in liters is $\text{75}\text{.7}\text{L}\text{.}$

(f)

Interpretation Introduction

Interpretation:

The quantity $\text{4}{\text{.5×10}}^{\text{4}}{\text{ft}}^{\text{3}}$ has to be converted into cubic meter.

Answer to Problem 22PE

The quantity $\text{4}{\text{.5×10}}^{\text{4}}{\text{ft}}^{\text{3}}$ in cubic meter is $\text{1}{\text{.3×10}}^{\text{3}}{\text{m}}^{\text{3}}\text{.}$

Explanation of Solution

The given quantity is $\text{4}{\text{.5×10}}^{\text{4}}{\text{ft}}^{\text{3}}\text{.}$

Cubic feet is converted into meter cube using the conversion factor,

  ${\left(\frac{\text{12}\text{in}\text{.}}{\text{1}\text{ft}}\right)}^{\text{3}}{\left(\frac{\text{2}\text{.54}\text{cm}}{\text{1}\text{in}\text{.}}\right)}^{\text{3}}{\left(\frac{\text{1}\text{m}}{\text{100}\text{cm}}\right)}^{\text{3}}$

The quantity $\text{4}{\text{.5×10}}^{\text{4}}{\text{ft}}^{\text{3}}$ is converted as,

  $\begin{array}{l}{\text{m}}^{\text{3}}\text{=}\left(\text{4}{\text{.5×10}}^{\text{4}}{\text{ft}}^{\text{3}}\right){\left(\frac{\text{12}\text{in}\text{.}}{\text{1}\text{ft}}\right)}^{\text{3}}{\left(\frac{\text{2}\text{.54}\text{cm}}{\text{1}\text{in}\text{.}}\right)}^{\text{3}}{\left(\frac{\text{1}\text{m}}{\text{100}\text{cm}}\right)}^{\text{3}}\\ {\text{m}}^{\text{3}}\text{=1}{\text{.3×10}}^{\text{3}}{\text{m}}^{\text{3}}\end{array}$

The quantity $\text{4}{\text{.5×10}}^{\text{4}}{\text{ft}}^{\text{3}}$ in cubic meter is $\text{1}{\text{.3×10}}^{\text{3}}{\text{m}}^{\text{3}}\text{.}$