Chapter 13, Problem 1RQ

Interpretation Introduction

Interpretation:

State of ${\text{H}}_{\text{2}}\text{S}$, ${\text{H}}_{\text{2}}\text{Se}$ and ${\text{H}}_{\text{2}}\text{Te}$ at $\text{0 }°\text{C}$ has to be identified.

Concept Introduction:

A particle in the substance that occupies space and has mass is termed as matter. Atoms and molecules are composed of matter. There are three types of states of matter that are as follows:

1 Solid: In solid, particles are tightly packed and are highly dense.

2 Liquid: In liquid, particles are loosely packed and are less dense.

3 Gases:In gases, particles move freely with no force of attraction.

Explanation of Solution

Water being the first member of the group shows anomalous behavior and is liquid in nature at $\text{0 }°\text{C}$. Due to the intermolecular hydrogen bonding in water it has highest boiling point than ${\text{H}}_{\text{2}}\text{S}$, ${\text{H}}_{\text{2}}\text{Se}$ and ${\text{H}}_{\text{2}}\text{Te}$.  Whereas ${\text{H}}_{\text{2}}\text{S}$, ${\text{H}}_{\text{2}}\text{Se}$ and ${\text{H}}_{\text{2}}\text{Te}$ has dipole-dipole interaction that is weak in nature. Thus, at $\text{0 }°\text{C}$${\text{H}}_{\text{2}}\text{S}$, ${\text{H}}_{\text{2}}\text{Se}$ and ${\text{H}}_{\text{2}}\text{Te}$ are colorless gases.