EBK FOUNDATIONS OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781118930144
Author: Willard
Publisher: JOHN WILEY+SONS INC.
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Chapter 13, Problem 16RQ
Interpretation Introduction
Interpretation:
Pressure cooker requires higher temperature than ordinary pot has to be explained.
Concept Introduction:
Temperature at which vapor pressure becomes equal to the external pressure is termed as boiling point. Pressure that is exerted by the atmosphere is called atmospheric pressure. The standard atmospheric pressure is
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22) Evaporation of sweat requires energy and thus take excess heat away from the body. Some of the water that you
drink may eventually be converted into sweat and evaporate. If you drink a 20-ounce bottle of water (590g) that
had been in the refrigerator at 3.8 °C, how much heat is needed to convert all of that water into sweat and then to
vapor? (Note: Your body temperature is 36.6 °C. For the purpose of solving this problem, assume that the therm
properties of sweat are the same as for water.
Us, liquid water =
4.184 J/g °C
Cs, steam= 1.84 J/g °C
C3, ice = 2.09 /g °C
AHvap = 40.67 kJ/mol at 36.6 °C.
%3D
A Hus = 6.01 kJ/mol
A) 1420 kJ
B) 81 kJ
C) 1150 kJ
23) Based on the graph shown below, choose the correct statement about sublimation?
Gas
Liquid
sublimation
Solid
A) Sublimation is a phase transition from solid to gas
B) According to Hess Law, AHsub can be calculated as sum of AHvap and AHUS
C) Both A and B are correct
Water can absorb or release large amounts of heat with little change in actual temperature. Why?
Which method would you use to determine water content in packaging material, pharmaceuticals and cosmetics? Mention few advantages of this method.
Chapter 13 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
Ch. 13.2 - Prob. 13.1PCh. 13.2 - Prob. 13.2PCh. 13.3 - Prob. 13.3PCh. 13.3 - Prob. 13.4PCh. 13.4 - Prob. 13.5PCh. 13.5 - Prob. 13.6PCh. 13.5 - Prob. 13.7PCh. 13.5 - Prob. 13.8PCh. 13.6 - Prob. 13.9PCh. 13.6 - Prob. 13.10P
Ch. 13 - Prob. 1RQCh. 13 - Prob. 2RQCh. 13 - Prob. 3RQCh. 13 - Prob. 4RQCh. 13 - Prob. 5RQCh. 13 - Prob. 6RQCh. 13 - Prob. 7RQCh. 13 - Prob. 8RQCh. 13 - Prob. 9RQCh. 13 - Prob. 10RQCh. 13 - Prob. 11RQCh. 13 - Prob. 12RQCh. 13 - Prob. 13RQCh. 13 - Prob. 14RQCh. 13 - Prob. 15RQCh. 13 - Prob. 16RQCh. 13 - Prob. 17RQCh. 13 - Prob. 19RQCh. 13 - Prob. 20RQCh. 13 - Prob. 21RQCh. 13 - Prob. 22RQCh. 13 - Prob. 23RQCh. 13 - Prob. 24RQCh. 13 - Prob. 25RQCh. 13 - Prob. 26RQCh. 13 - Prob. 27RQCh. 13 - Prob. 28RQCh. 13 - Prob. 29RQCh. 13 - Prob. 30RQCh. 13 - Prob. 31RQCh. 13 - Prob. 32RQCh. 13 - Prob. 33RQCh. 13 - Prob. 34RQCh. 13 - Prob. 35RQCh. 13 - Prob. 36RQCh. 13 - Prob. 37RQCh. 13 - Prob. 38RQCh. 13 - Prob. 39RQCh. 13 - Prob. 40RQCh. 13 - Prob. 41RQCh. 13 - Prob. 42RQCh. 13 - Prob. 43RQCh. 13 - Prob. 1PECh. 13 - Prob. 2PECh. 13 - Prob. 3PECh. 13 - Prob. 4PECh. 13 - Prob. 5PECh. 13 - Prob. 6PECh. 13 - Prob. 7PECh. 13 - Prob. 8PECh. 13 - Prob. 9PECh. 13 - Prob. 10PECh. 13 - Prob. 11PECh. 13 - Prob. 12PECh. 13 - Prob. 13PECh. 13 - Prob. 14PECh. 13 - Prob. 15PECh. 13 - Prob. 16PECh. 13 - Prob. 17PECh. 13 - Prob. 18PECh. 13 - Prob. 19PECh. 13 - Prob. 20PECh. 13 - Prob. 21PECh. 13 - Prob. 22PECh. 13 - Prob. 23PECh. 13 - Prob. 24PECh. 13 - Prob. 25PECh. 13 - Prob. 26PECh. 13 - Prob. 27PECh. 13 - Prob. 28PECh. 13 - Prob. 29PECh. 13 - Prob. 30PECh. 13 - Prob. 31PECh. 13 - Prob. 32PECh. 13 - Prob. 33AECh. 13 - Prob. 34AECh. 13 - Prob. 35AECh. 13 - Prob. 36AECh. 13 - Prob. 38AECh. 13 - Prob. 39AECh. 13 - Prob. 40AECh. 13 - Prob. 41AECh. 13 - Prob. 42AECh. 13 - Prob. 43AECh. 13 - Prob. 44AECh. 13 - Prob. 45AECh. 13 - Prob. 46AECh. 13 - Prob. 47AECh. 13 - Prob. 48AECh. 13 - Prob. 49AECh. 13 - Prob. 50AECh. 13 - Prob. 51AECh. 13 - Prob. 52AECh. 13 - Prob. 53AECh. 13 - Prob. 54AECh. 13 - Prob. 55AECh. 13 - Prob. 56AECh. 13 - Prob. 57AECh. 13 - Prob. 58AECh. 13 - Prob. 59AECh. 13 - Prob. 60AECh. 13 - Prob. 61AECh. 13 - Prob. 62AECh. 13 - Prob. 63AECh. 13 - Prob. 64AECh. 13 - Prob. 65AECh. 13 - Prob. 66AECh. 13 - Prob. 67AECh. 13 - Prob. 69CECh. 13 - Prob. 70CECh. 13 - Prob. 71CECh. 13 - Prob. 72CE
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