
Concept explainers
(a)
Interpretation:
The theoretical yield of
(a)

Answer to Problem 31PE
The theoretical yield of
The theoretical yield of
Explanation of Solution
Given,
The mass of copper is
The mass of
The molecular weight of copper is
The molecular weight of
The molecular weight of
The balanced equation is,
In the reaction there is three mole of
The theoretical yield of
Grams of
Grams of
The theoretical yield of
The theoretical yield of
Grams of
Grams of
The theoretical yield of
(b)
Interpretation:
The grams of excess reactant remain have to be given.
(b)

Answer to Problem 31PE
The grams of excess reactant remain is
Explanation of Solution
The theoretical yield of
The theoretical yield of
The molecular weight of
The molecular weight of
Since Copper produces less
The balanced equation is,
The mole ratio is
The grams of excess reactant reacted can be calculated as,
The grams of excess reactant remain is
The grams of excess reactant remain is
(c)
Interpretation:
The Actual yield of
(c)

Answer to Problem 31PE
The actual yield of
The actual yield of
Explanation of Solution
Given,
The percentage yield of
The theoretical yield of
The theoretical yield of
The actual yield of
The percentage yield=
The actual yield of
The actual yield of
The actual yield of
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Chapter 9 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
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