EBK FOUNDATIONS OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781118930144
Author: Willard
Publisher: JOHN WILEY+SONS INC.
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Chapter 9, Problem 57AE
Interpretation Introduction
Interpretation:
The picture showing the reaction between two molecules of methane and three molecules of oxygen has to be drawn and any reactants, which limit the amount of the products has to be given.
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B 1 of 2
Additional problems in preparation to Midterm #1:
1.) How can the following compounds be prepared using Diels-Alder reaction:
CH3 O
CN
(a)
(b)
CN
CH3
2.) What is the missing reagent in the shown reaction?
H3C
+ ?
H3C
H3C
CN
H3C
''CN
(၁)
H
3.) Write the products 1,2-addition and 1,4-addition of DBr to 1,3-cyclohexadiene.
Remember, D is deuterium, a heavy isotope of hydrogen. It reacts exactly like hydrogen.
4.) In the shown reaction, which will be the kinetic product and which will be the
thermodynamic product?
H3C
CI
H3C
HCI
H3C
+
5.) Which of the following molecules is aromatic?
(a)
(b)
(c)
H
6.) Which of the following molecules is aromatic?
(a)
(b)
(c)
7.) Write the mechanism for the shown reaction.
+
Ха
AICI 3
CI
8.) Suggest reagents that would convert benzene into the shown compounds.
CI
NO2
-8-6-6-8-a
(a)
(b)
(c)
(d)
(e)
(a)
SO3H
Br
The number of 2sp^2 hybridized atoms in is: A. 8; B. 6; C.4; D.2; E.0;
Chapter 9 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
Ch. 9.1 - Prob. 9.1PCh. 9.2 - Prob. 9.2PCh. 9.2 - Prob. 9.3PCh. 9.3 - Prob. 9.4PCh. 9.3 - Prob. 9.5PCh. 9.4 - Prob. 9.6PCh. 9.4 - Prob. 9.7PCh. 9.5 - Prob. 9.8PCh. 9.5 - Prob. 9.9PCh. 9.5 - Prob. 9.10P
Ch. 9 - Prob. 1RQCh. 9 - Prob. 2RQCh. 9 - Prob. 3RQCh. 9 - Prob. 4RQCh. 9 - Prob. 5RQCh. 9 - Prob. 6RQCh. 9 - Prob. 7RQCh. 9 - Prob. 8RQCh. 9 - Prob. 1PECh. 9 - Prob. 2PECh. 9 - Prob. 3PECh. 9 - Prob. 4PECh. 9 - Prob. 5PECh. 9 - Prob. 6PECh. 9 - Prob. 7PECh. 9 - Prob. 8PECh. 9 - Prob. 9PECh. 9 - Prob. 10PECh. 9 - Prob. 11PECh. 9 - Prob. 12PECh. 9 - Prob. 13PECh. 9 - Prob. 14PECh. 9 - Prob. 15PECh. 9 - Prob. 16PECh. 9 - Prob. 17PECh. 9 - Prob. 18PECh. 9 - Prob. 19PECh. 9 - Prob. 20PECh. 9 - Prob. 21PECh. 9 - Prob. 22PECh. 9 - Prob. 23PECh. 9 - Prob. 24PECh. 9 - Prob. 25PECh. 9 - Prob. 26PECh. 9 - Prob. 27PECh. 9 - Prob. 28PECh. 9 - Prob. 29PECh. 9 - Prob. 30PECh. 9 - Prob. 31PECh. 9 - Prob. 33AECh. 9 - Prob. 34AECh. 9 - Prob. 35AECh. 9 - Prob. 36AECh. 9 - Prob. 37AECh. 9 - Prob. 39AECh. 9 - Prob. 42AECh. 9 - Prob. 43AECh. 9 - Prob. 44AECh. 9 - Prob. 45AECh. 9 - Prob. 46AECh. 9 - Prob. 47AECh. 9 - Prob. 48AECh. 9 - Prob. 49AECh. 9 - Prob. 50AECh. 9 - Prob. 51AECh. 9 - Prob. 52AECh. 9 - Prob. 53AECh. 9 - Prob. 54AECh. 9 - Prob. 55AECh. 9 - Prob. 56AECh. 9 - Prob. 57AECh. 9 - Prob. 59CECh. 9 - Prob. 60CECh. 9 - Prob. 61CECh. 9 - Prob. 62CECh. 9 - Prob. 63CE
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