
(a)
Interpretation:
Structural formula of 1,2-diphenylethene has to be drawn.
Concept introduction:
IUAC gives rules for the naming of chemical compounds. These rules are,
For
In the nomenclature, Find the parent chin first then number the carbon atoms in the parent chain by giving lest number to the unsaturated double/triple bonded carbon followed by designate the substituent in its position in parent chain.
If more than one same substituent were occurs, add a prefix (di-, tri-, tetra-, ect..) in front of parent chain name.
If compound contains double bond means, name end with suffix of ene or if compound contains triple bond means name end with suffix of yne.
Finally the systematic name was written as, the substituent position number with prefix (di-, tri-, tetra-, ect..) of number of substituents followed by name of the substituent then write the parent chain name (which contains large number of carbon atoms in the chain) with suffix of suffix ene/yne.
The parent chain names based on the carbon atoms are,
The substituent names based on the carbon atoms are,
(a)

Explanation of Solution
The structural formula of 1,2-diphenylethene is,
From the given name parent compound is ethene, its structure is,
Two phenyl groups are present at 1 and 2 positions so substitute phenyl groups at 2 and 5 positions to get the complete structural formula of 1,2-diphenylethene.
Hence, the complete structural formula of 1,2-diphenylethene is,
(b)
Interpretation:
Structural formula of 3-pentene-1-yne has to be drawn.
Concept introduction:
Refer part (a).
(b)

Explanation of Solution
The structural formula of 3-pentene-1-yne is,
From the given name parent compound is Pentane, its structure is,
From the given name, double bond at third position and triple bond at first position. Therefore draw the double bond at third position and triple bond at first position of the pentane.
Hence, the complete structural formula of 3-pentene-1-yne is,
(c)
Interpretation:
Structural formula of 3-phenyl-1-butyne has to be drawn.
Concept introduction:
Refer part (a).
(c)

Explanation of Solution
The structural formula of 3-phenyl-1-butyne is,
From the given name parent compound is 1-butyne, its structure is,
Phenyl group is present at third carbon so substitute phenyl group at 3 carbon atom to get structural formula of 3-phenyl-1-butyne.
Hence, the complete structural formula of 3-phenyl-1-butyne is,
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Chapter 19 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. :0: :0 H. 0:0 :0: :6: S: :0: Select to Edit Arrows ::0 Select to Edit Arrows H :0: H :CI: Rotation Select to Edit Arrows H. < :0: :0: :0: S:arrow_forward3:48 PM Fri Apr 4 K Problem 4 of 10 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Mg. :0: Select to Add Arrows :0: :Br: Mg :0: :0: Select to Add Arrows Mg. Br: :0: 0:0- Br -190 H 0:0 Select to Add Arrows Select to Add Arrows neutralizing workup H CH3arrow_forwardIarrow_forward
- Draw the Markovnikov product of the hydrobromination of this alkene. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for this problem. + Explanation Check 1 X E 4 1 1 1 1 1 HBr Click and drag to start drawing a structure. 80 LE #3 @ 2 $4 0 I அ2 % 85 F * K M ? BH 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center & 6 27 FG F10 8 9 R T Y U D F G H P J K L Z X C V B N M Q W A S H option command H command optiarrow_forwardBe sure to use wedge and dash bonds to show the stereochemistry of the products when it's important, for example to distinguish between two different major products. Predict the major products of the following reaction. Explanation Q F1 A Check F2 @ 2 # 3 + X 80 F3 W E S D $ 4 I O H. H₂ 2 R Pt % 05 LL ee F6 F5 T <6 G Click and drag to start drawing a structure. 27 & A 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Acce Y U H DII 8 9 F10 4 J K L Z X C V B N M T H option command F11 P H commandarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the intermediate and product in this reaction or mechanistic step(s). Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore inorganic byproducts. H :0: CH3 O: OH Q CH3OH2+ Draw Intermediate protonation CH3OH CH3OH nucleophilic addition H Draw Intermediate deprotonation :0: H3C CH3OH2* protonation H 0: H CH3 H.arrow_forward
- Predicting the reactants or products of hemiacetal and acetal formation uentify the missing organic reactants in the following reaction: H+ X+Y OH H+ за Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H2O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Explanation Check Click and drag to start drawing a structure. ? olo 18 Ar © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardcan someone please answer thisarrow_forwardPlease, please help me figure out the the moles, molarity and Ksp column. Step by step details because I've came up with about three different number and have no idea what I'm doing wrong.arrow_forward
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