
(a)
Interpretation:
The below equation through change in oxidation number method has to be balanced.
Concept Introduction:
Steps for change in oxidation number method to
1 Oxidation number of each element has to be assigned and change in oxidation number has to be identified. Then add electrons to balance charge.
2 Two half-reactions with only elements that have changed oxidation numbers have to be formed.
3 Both reactions multiplied by smallest whole number that can make electrons lost equal to electron gained.
4 Coefficient should transfer to original equation.
5 Remaining oxygen atoms are balanced through water molecules.
6 For acidic medium, charge is balanced by addition of
(a)

Explanation of Solution
Given reaction is as follows:
Oxidation number of each element in equation (1) can be assigned as follows:
Change in oxidation number occurred in copper and silver thus two half-reactions can be formed as follows:
Oxidation half-reaction for copper is as follows:
Reduction half-reaction for silver is as follows:
Multiply equation (3) by 2 to make same number of electron gained and loses.
Coefficient of atoms in equation (2) and equation (4) of half reactions are transferred to equation (1). Left atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:
(b)
Interpretation:
The below equation through change in oxidation number method has to be balanced.
Concept Introduction:
Refer to part (a).
(b)

Explanation of Solution
Given reaction is as follows:
Oxidation number of each element in equation (5) can be assigned as follows:
Change in oxidation number occurred in manganese and chlorine thus two half-reactions can be formed as follows:
Oxidation half-reaction for chlorine is as follows:
Reduction half-reaction for manganese is as follows:
Coefficient of atoms in both half reactions is transferred to equation (5). Left atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:
(c)
Interpretation:
The below equation through change in oxidation number method has to be balanced.
Concept Introduction:
Refer to part (a).
(c)

Explanation of Solution
Given reaction is as follows:
Oxidation number of each element in equation (9) can be assigned as follows:
Change in oxidation number occured in chlorine and oxygen thus two balanced half-reactions can be formed as follows:
Balanced oxidation half-reaction is as follows:
Balanced reduction half-reaction is as follows:
Multiply equation (10) by 2 so that number of electrons gained and lost becomes same and cancels each other. Thus, equation (10) is as follows:
Coefficient of atoms in equation (11) and equation (12) of half reactions are transferred to equation (9). Remaining atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:
(d)
Interpretation:
The below equation through change in oxidation number method has to be balanced.
Concept Introduction:
Refer to part (a).
(d)

Explanation of Solution
Given reaction is as follows:
Oxidation number of each element in equation can be assigned as follows:
Change in oxidation number occurred in silver and oxygen thus two balanced half-reactions can be formed as follows:
Balanced oxidation half-reaction is as follows:
Balanced reduction half-reaction is as follows:
Multiply equation (14) by 2 so that number of electrons gained and lost becomes same and cancels each other. Thus, equation (14) becomes as follows:
Coefficient of atoms in equation (15) and equation (16) of half reactions are transferred to equation (13). Remaining atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:
(e)
Interpretation:
The below equation through change in oxidation number method has to be balanced.
Concept Introduction:
Refer to part (a).
(e)

Explanation of Solution
Given reaction is as follows:
Oxidation number of each element in equation can be assigned as follows:
Change in oxidation number occurred in manganese and carbon thus two balanced half-reactions can be formed as follows:
Balanced oxidation half-reaction for carbon is as follows:
Balanced reduction half-reaction for manganese is as follows:
Multiply equation (18) by 5 and equation (19) by 2 so that number of electrons gained and lost becomes same and cancels each other. Thus, equation (18) becomes as follows:
Equation (19) becomes as follows:
Coefficient of atoms in equation (20) and equation (21) of half reactions are transferred to equation (17). Remaining atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:
Want to see more full solutions like this?
Chapter 17 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
- Please sirrr soollveee these parts pleaseeee and thank youuuuuarrow_forward4. Read paragraph 4.15 from your textbook, use your calculated lattice energy values for CuO, CuCO3 and Cu(OH)2 an explain thermal decomposition reaction of malachite: Cu2CO3(OH)2 →2CuO + H2O + CO2 (3 points)arrow_forwardPlease sirrr soollveee these parts pleaseeee and thank youuuuuarrow_forward
- III O Organic Chemistry Using wedges and dashes in skeletal structures Draw a skeletal ("line") structure for each of the molecules below. Be sure your structures show the important difference between the molecules. key O O O O O CHON Cl jiii iiiiiiii You can drag the slider to rotate the molecules. Explanation Check Click and drag to start drawing a structure. Q Search X G ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use F 3 W C 3/5arrow_forward3. Use Kapustinskii's equation and data from Table 4.10 in your textbook to calculate lattice energies of Cu(OH)2 and CuCO3 (4 points)arrow_forward2. Copper (II) oxide crystalizes in monoclinic unit cell (included below; blue spheres 2+ represent Cu²+, red - O²-). Use Kapustinski's equation (4.5) to calculate lattice energy for CuO. You will need some data from Resource section of your textbook (p.901). (4 points) CuOarrow_forward
- What is the IUPAC name of the following compound? OH (2S, 4R)-4-chloropentan-2-ol O (2R, 4R)-4-chloropentan-2-ol O (2R, 4S)-4-chloropentan-2-ol O(2S, 4S)-4-chloropentan-2-olarrow_forwardIn the answer box, type the number of maximum stereoisomers possible for the following compound. A H H COH OH = H C Br H.C OH CHarrow_forwardSelect the major product of the following reaction. Br Br₂, light D Br Br Br Brarrow_forward
- Select all molecules which are chiral. Brarrow_forwardUse the reaction coordinate diagram to answer the below questions. Type your answers into the answer box for each question. (Watch your spelling) Energy A B C D Reaction coordinate E A) Is the reaction step going from D to F endothermic or exothermic? A F G B) Does point D represent a reactant, product, intermediate or transition state? A/ C) Which step (step 1 or step 2) is the rate determining step? Aarrow_forward1. Using radii from Resource section 1 (p.901) and Born-Lande equation, calculate the lattice energy for PbS, which crystallizes in the NaCl structure. Then, use the Born-Haber cycle to obtain the value of lattice energy for PbS. You will need the following data following data: AH Pb(g) = 196 kJ/mol; AHƒ PbS = −98 kJ/mol; electron affinities for S(g)→S¯(g) is -201 kJ/mol; S¯(g) (g) is 640kJ/mol. Ionization energies for Pb are listed in Resource section 2, p.903. Remember that enthalpies of formation are calculated beginning with the elements in their standard states (S8 for sulfur). The formation of S2, AHF: S2 (g) = 535 kJ/mol. Compare the two values, and explain the difference. (8 points)arrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning





