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- Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…1. Provide stepwise synthesis including reagents and intermediates for the following syntheses. OH COOH4. A CHEM 245 student wants to synthesize some ethylene glycol to use as antifreeze in his radiator this winter. He proposes the following reaction to his instructor, who quickly explains that this reaction won't work as proposed due to the student's choice of reagent. 1) NaH 2) H20 OH Но a) Why can't sodium hydride (NaH) be used as the nucleophile in the reaction above? b) Propose an alternate reagent that COULD be used with the ethylene oxide to successfully give the desired ethylene glycol product.
- orgo chem questions5.Synthesis. Make the following products from a suitable cyclic alkene starting material. Look at the functional group PATTERN present in the molecule, including stereochemistry. Br Br1. Show all steps in the synthesis of 4-methylaniline from toluene. Clearly show all reagents, reactants and products for each step. Toluene -------> --------> 4-methylaniline