Icohols are acidic in nature. Therefore, a strong base can bstract the acidic hydrogen atom of the alcohol in a process nown as deprotonation. The alcohol forms an alkoxide ion by sing the proton attached to the oxygen atom of the hydroxyl ( OH) group. The alkoxide formed can act as a base or a ucleophile depending on the substrate and reaction conditions. owever, not all bases can abstract the acidic proton of alcohols nd not all alcohols easily lose the proton. Deprotonation epends on the strength of the base and the acidity of the cohol. Strong bases, such as NaNH₂, can easily abstract a roton from almost all alcohols. Likewise, more acidic alcohols se a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ▸ View Available Hint(s) CH3CH₂OH + NH3 CH3CH₂O-NH- CH3 CH3 H3C-C-H+NH3 → H3C-C-H OH O-NH * CH3CH,OH + NaNH, → CH3CH,O-Na* + NH ✓ CHCL Cl₂ HC-CH-OH+NaOH → Cl₂ HC-CH-O-Na+ CHC12 CH3 CH3 H3C-C-OH + NaOH → H3C-C-O-Na+ + H₂O CH3 CH3

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Chapter1: Chemical Foundations
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Alcohols are acidic in nature. Therefore, a strong base can
abstract the acidic hydrogen atom of the alcohol in a process
known as deprotonation. The alcohol forms an alkoxide ion by
losing the proton attached to the oxygen atom of the hydroxyl (
-OH) group. The alkoxide formed can act as a base or a
nucleophile depending on the substrate and reaction conditions.
However, not all bases can abstract the acidic proton of alcohols
and not all alcohols easily lose the proton. Deprotonation
depends on the strength of the base and the acidity of the
alcohol. Strong bases, such as NaNH2, can easily abstract a
proton from almost all alcohols. Likewise, more acidic alcohols
lose a proton more easily.
Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol.
Check all that apply.
► View Available Hint(s)
CH3CH,OH + NH3 →CH,CH,O-NH
CH3
CH3
H3C-C-H+NH3 → H3 C-C-H
OH
O-NH
CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3
CHC12
Cl₂ HC-CH-OH+NaOH → Cl₂ HC-CH-O-Na+
CHC12
Submit
+
CH3
CH3
ⒸH3C-C-OH + NaOH → H₂C—C—O¯Na+ + H₂O
CH3
CH3
Previous Answers
Transcribed Image Text:Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂ HC-CH-OH+NaOH → Cl₂ HC-CH-O-Na+ CHC12 Submit + CH3 CH3 ⒸH3C-C-OH + NaOH → H₂C—C—O¯Na+ + H₂O CH3 CH3 Previous Answers
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