(a)
Interpretation:
Balanced equation for reaction below by change-in-oxidation-number method in basic solution has to be determined.
Concept Introduction:
Change in oxidation number method to
1. Oxidation number of each element has to be assigned and change in oxidation number has to be identified. Then add electrons to balance charge.
2. Two half-reactions with only elements that have changed oxidation numbers have to be formed.
3. Both reactions multiplied by smallest whole number that can make electrons lost equal to electron gained.
4. Coefficient should transferred to original equation.
5. Remaining oxygen atoms are balanced through water molecules.
6. For acidic medium, charge is balanced by addition of
(b)
Interpretation:
Balanced equation for reaction below by change-in-oxidation-number method in acidic solution has to be determined.
Concept Introduction:
Refer to part (a).
(c)
Interpretation:
Balanced equation for reaction below by change-in-oxidation-number method in basic solution has to be determined.
Concept Introduction:
Refer to part (a).
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EBK FOUNDATIONS OF COLLEGE CHEMISTRY
- The blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with an acidic potassium di-chromate solution, resulting in the production of Cr3+ (aq) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2O72) is orange in solution, and the Cr3+ ion is green. The balanced equations is 16H+(aq) + 2Cr2O72(aq) + C2H5OH(aq) 4Cr4+(aq) + 2CO2(g) + 11H2O(l) This reaction is an oxidationreduction reaction. What species is reduced, and what species is oxidized? How many electrons are transferred in the balanced equation above?arrow_forwardFour metals, A, B, C, and D, exhibit the following properties: (a) Only A and C react with 1.0 M hydrochloric acid to give H2(g). (b) When C is added to solutions of the ions of the other metals, metallic B, D, and A are formed. (c) Metal D reduces Bn+ to give metallic B and Dn+. Based on this information, arrange the four metals in order of increasing ability to act as reducing agents.arrow_forwardThe Toliens test for the presence of reducing sugars (say, in a urine sample) involves treating the sample with silver ions in aqueous ammonia. The result is the formation of a silver mirror within the reaction vessel if a reducing sugar is present. Using glucose, C6H12O6, to illustrate this test, the oxidation-reduction reaction occurring is C6H12O6 (aq) + 2 Ag+(aq) + 2OH(aq) C6H12O7(aq) + 2 Ag(s) + H2O() What has been oxidized, and what has been reduced? What is the oxidizing agent, and what is the reducing agent? Tolien's test. The reaction of silver ions with a sugar such as glucose produces metallic silver. (a) The set-up for the reaction. (b) The silvered test tubearrow_forward
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- Chromium has been investigated as a coating for steel cans. The thickness of the chromium film is determined by dissolving a sample of a can in acid and oxidizing the resulting Cr3+ to Cr2O72 with the peroxydisulfate ion: S2O82(aq) + Cr3+(aq) + H2O(l) Cr2O72(aq) + SO42(aq) + H+(aq) (Unbalanced) After removal of unreacted S2O82 an excess of ferrous ammonium sulfate [Fe(NH4)2(SO4)26H2O] is added, reacting with Cr2O72 produced from the first reaction. The unreacted Fe2+ from the excess ferrous ammonium sulfate is titrated with a separate K2Cr2O7 solution. The reaction is: H+(aq) + Fe2+(aq) + Cr2O72(aq) Fe3+(aq) + Cr3+(aq) + H2O(l) (Unbalanced) a. Write balanced chemical equations for the two reactions. b. In one analysis, a 40.0-cm2 sample of a chromium-plated can was treated according to this procedure. After dissolution and removal of excess S2O82, 3.000 g of Fe(NH4)2(SO4)26H2O was added. It took 8.58 mL of 0.0520 M K2Cr2O7 solution to completely react with the excess Fe2+. Calculate the thickness of the chromium film on the can. (The density of chromium is 7.19 g/cm3)arrow_forwardWhich two of the following reactions are oxidation-reduction reactions? Explain your answer briefly. Classify the remaining reaction. (a) CdC12(aq) + Na2S(aq) CdS(s) + 2 NaCl(aq) (b) 2 Ca(s) + O2(g) 2 CaO(s) (c) 4 Fe(OH)2(s) + 2 H2O() + O2(g) 4 Fe(OH)3(s)arrow_forwardBalance each of the following oxidationreduction reactions by nsing the oxidation states method. a. Cl2(g) + Al(s) Al3+(aq) + Cl(aq) b. O2(g) + H2O(l) + Ph(s) Ph(OH)2(s) c. H+(aq) + MnO4(aq) + Fe2+(aq) Mn2+(aq) + Fe3+(aq) + H2O(l)arrow_forward
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