Chapter 14.5, Problem 14.11P

Interpretation Introduction

Interpretation:

Molality of solution formed by dissolution of $150.0{\text{ g C}}_6{\text{H}}_{12}{\text{O}}_6$ in $60.0{\text{ g H}}_2\text{O}$ has to be determined.

Concept Introduction:

Molality is amount of solute present in one kilogram of solvent. Expression to calculate molality of solution is as follows:

  $\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass }\left(\text{kg}\right)\text{of solvent}}$