Chapter 14, Problem 23PE

(a)

Interpretation Introduction

Interpretation:

Milliliteres of $0.750M{\text{ H}}_3{\text{PO}}_4$ that are present in $0.15{\text{ mol H}}_3{\text{PO}}_4$ have to be determined.

Concept Introduction:

Molarity of solution is concentration term in terms of moles of solute per liter of solution. Formula to calculate molarity of solution is as follows:

  $\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume }\left(\text{L}\right)\text{ of solution}}$

(b)

Interpretation Introduction

Interpretation:

Milliliteres of $0.750M{\text{ H}}_3{\text{PO}}_4$ that are present in $\text{35}{\text{.5 g H}}_3{\text{PO}}_4$ have to be determined.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Milliliteres of $0.750M{\text{ H}}_3{\text{PO}}_4$ that are present in $\text{7}\text{.34}\times {\text{10}}^{22}\text{ molecules}$ of ${\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}$ have to be determined.

Concept Introduction:

Refer to part (a).