Chapter 14, Problem 41PE

(a)

Interpretation Introduction

Interpretation:

Molality of solution prepared by $2.68\text{ g}$ of naphthalene in $38.4\text{ g}$ of benzene has to be determined.

Concept Introduction:

Molality is amount of solute present in one kilogram of solvent. Expression for molality of solution is as follows:

  $\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass }\left(\text{kg}\right)\text{of solvent}}$

(b)

Interpretation Introduction

Interpretation:

Freezing point of solution prepared by $2.68\text{ g}$ of naphthalene in $38.4\text{ g}$ of benzene has to be determined.

Concept Introduction:

Colligative properties are dependent on amount of solute and not on their natures. These are caused due to addition of nonvolatile solute in any solution. Below mentioned are colligative properties.

1. Freezing point depression

2. Boiling point elevation

3. Vapor pressure lowering

4. Osmotic pressure

(c)

Interpretation Introduction

Interpretation:

Boiling point of solution prepared by $2.68\text{ g}$ of naphthalene in $38.4\text{ g}$ of benzene has to be determined.

Concept Introduction:

Refer to part (b).