Chapter 14, Problem 24PE

(a)

Interpretation Introduction

Interpretation:

Milliliteres of $0.250M{\text{ NH}}_{\text{4}}\text{Cl}$ that are present in $0.85\text{ mol}$ of ${\text{NH}}_{\text{4}}\text{Cl}$ have to be determined.

Concept Introduction:

Molarity of solution is concentration term in terms of moles of solute per liter of solution. Formula to calculate molarity of solution is as follows:

  $\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume }\left(\text{L}\right)\text{ of solution}}$

(b)

Interpretation Introduction

Interpretation:

Milliliteres of $0.250M{\text{ NH}}_{\text{4}}\text{Cl}$ that are present in $25.2\text{ g}$ of ${\text{NH}}_{\text{4}}\text{Cl}$ have to be determined.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Milliliteres of $0.250M{\text{ NH}}_{\text{4}}\text{Cl}$ that are present in $2.06\times {\text{10}}^{20}\text{ formula units}$ of ${\text{NH}}_{\text{4}}\text{Cl}$ have to be determined.

Concept Introduction:

Refer to part (a).