EBK FOUNDATIONS OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781118930144
Author: Willard
Publisher: JOHN WILEY+SONS INC.
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Question
Chapter 5.2, Problem 5.2P
Interpretation Introduction
Interpretation:
The cations and anions have to be identified from the given set of ions.
Concept Introduction:
Cation: An atom (or) molecule that has more number of protons than electrons with a positive charge is called as a cation. Cations are positively charged species and are formed from metals.
Anions: An atom (or) molecule that has more number of electrons than protons with a negative charge is called as an anion. Anions are negatively charged species and are formed from nonmetals.
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Here is a list of five compounds: MX, M,X, MX, M,X, and MX3.
M represents a metal ion, but not necessarily the same. Depending on the salt, M could stand for Na, K
X represents an anion, but not necessarily the same. Depending on the salt, X could stand for cI, Br, so,
2+
....
...
In other words, the nature of the cation and the anion in each salt is rather unimportant, only the cation to anion ratio
matters.
All five compounds have the same K,
sp'
Select all compounds that have the lowest solubility (in mol/L).
Select one or more:
a. MX,
b. M,X
C. Because all five substances have the same K
they also have the same solubility in mol/L.
d. MX
e. Because all five substances have the same K they also have the same solubility in g/100g water.
sp'
Of.MX,
g. Cannot be answered without knowing the numerical value for K
h. M,X
As seen in the table, compounds containing an integer ratio of elements depend on how many cations combine with how many anions to form a stable compound. For example, in table 1, to form a NaCl compound, first Na ionizes from the Na+ cation which is having +1 positive charge, which will lose 1 electron, it is having +1 charge, this electron then goes to Cl and it will change to Cl- anion by gaining the electron, so here 1:1 ratio charge which means 1 Na+ combines with 1 Cl-1 to form NaCl. So here integer ratio is 1:1 for this sodium chloride compound. As listed in table 2, Mg(OH)2, the integer ratio is 1:2 which means, Mg is a neutral atom that loses 2 electrons and forms an Mg+2 cation, which combines with OH which gains 1 electron to form OH- anion, So here Mg2+ can combine with 2 OH- anion, so they both combine to form Mg(OH)2 which has integer ratio as 1:2 . Thus, atom forms as ions by losing or gaining electrons and combines together in whole number ratio to form stable…
Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
4+
3+
Pb++,
+, CIO3, Fe³+, CH₂ CO₂
3'
CH,CO,
0
0,0,..
×
Ś
000
Chapter 5 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
Ch. 5.1 - Prob. 5.1PCh. 5.2 - Prob. 5.2PCh. 5.3 - Prob. 5.3PCh. 5.4 - Prob. 5.4PCh. 5.5 - Prob. 5.5PCh. 5.5 - Prob. 5.6PCh. 5.6 - Prob. 5.7PCh. 5 - Prob. 1RQCh. 5 - Prob. 2RQCh. 5 - Prob. 3RQ
Ch. 5 - Prob. 4RQCh. 5 - Prob. 5RQCh. 5 - Prob. 6RQCh. 5 - Prob. 7RQCh. 5 - Prob. 8RQCh. 5 - Prob. 9RQCh. 5 - Prob. 10RQCh. 5 - Prob. 11RQCh. 5 - Prob. 12RQCh. 5 - Prob. 1PECh. 5 - Prob. 2PECh. 5 - Prob. 3PECh. 5 - Prob. 4PECh. 5 - Prob. 5PECh. 5 - Prob. 6PECh. 5 - Prob. 7PECh. 5 - Prob. 8PECh. 5 - Prob. 9PECh. 5 - Prob. 10PECh. 5 - Prob. 11PECh. 5 - Prob. 12PECh. 5 - Prob. 13PECh. 5 - Prob. 14PECh. 5 - Prob. 15PECh. 5 - Prob. 16PECh. 5 - Prob. 17PECh. 5 - Prob. 18PECh. 5 - Prob. 19PECh. 5 - Prob. 20PECh. 5 - Prob. 21PECh. 5 - Prob. 22PECh. 5 - Prob. 23PECh. 5 - Prob. 24PECh. 5 - Prob. 25PECh. 5 - Prob. 26PECh. 5 - Prob. 27PECh. 5 - Prob. 28PECh. 5 - Prob. 29PECh. 5 - Prob. 30PECh. 5 - Prob. 31PECh. 5 - Prob. 32PECh. 5 - Prob. 33PECh. 5 - Prob. 34PECh. 5 - Prob. 35AECh. 5 - Prob. 36AECh. 5 - Prob. 37AECh. 5 - Prob. 38AECh. 5 - Prob. 39AECh. 5 - Prob. 42AECh. 5 - Prob. 43AECh. 5 - Prob. 45AECh. 5 - Prob. 46AECh. 5 - Prob. 47AECh. 5 - Prob. 48AECh. 5 - Prob. 49AECh. 5 - Prob. 50AECh. 5 - Prob. 51AECh. 5 - Prob. 53AECh. 5 - Prob. 54AECh. 5 - Prob. 55AECh. 5 - Prob. 56AECh. 5 - Prob. 60CE
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