(a)
Interpretation:
The type of bond form between H and S to be predicted.
Concept introduction:
Power of an atom to attract electrons in a bond is electro negativity. Electro negativity is directly proportional to ionic character of the bond.

Answer to Problem 74SSC
Bond is non polar covalent.
Explanation of Solution
Electro negativity of H atom is 2 and electro negativity of S atom is 2.58. Thus electro negativity difference is as follows:
(b)
Interpretation:
The type of bond form between C and H to be predicted.
Concept introduction:
Power of an atom to attract electrons in a bond is electro negativity. Electro negativity is directly proportional to ionic character of the bond.

Answer to Problem 74SSC
Bond is non polar covalent.
Explanation of Solution
Electro negativity of H atom is 2 and electro negativity of C atom is 2.55. Thus electro negativity difference is as follows:
(c)
Interpretation:
The type of bond form between Na and S to be predicted.
Concept introduction:
Power of an atom to attract electrons in a bond is electro negativity. Electro negativity is directly proportional to ionic character of the bond.

Answer to Problem 74SSC
Bond is polar covalent.
Explanation of Solution
Electro negativity of Na atom is 0.93 and electro negativity of S atom is 2.58. Thus electro negativity difference is as follows:
Chapter 8 Solutions
Chemistry: Matter and Change
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