Chapter F, Problem J.14E

(a)

Interpretation Introduction

Interpretation:

Acid and base has to be identified in the given reaction.

    ${\text{HBrO}}_{\text{3}}\text{(aq)}+{\text{NaHCO}}_{\text{3}}\text{(aq)}\to {\text{H}}_{\text{2}}{\text{CO}}_{\text{3}}\text{(aq)}+{\text{NaBrO}}_{\text{3}}\text{(aq)}$

Concept Introduction:

Bronsted acid is the one that can act as proton donors while Bronsted base are the ones that can act as acceptor of protons.  If an acid is dissolved in water, the donation of proton from acid takes place resulting in formation of hydronium ion.  Bronsted acid is the one that contains hydrogen atoms that are acidic.

(b)

Interpretation Introduction

Interpretation:

Acid and base has to be identified in the given reaction.

    ${{\text{(CH}}_{\text{3}}\text{)}}_{\text{3}}\text{N(aq)}+\text{HCl(aq)}\to {({\text{CH}}_{\text{3}}\text{)}}_{\text{3}}{\text{NH}}^{\text{+}}\text{(aq)}+{\text{Cl}}^{-}\text{(aq)}$

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

Acid and base has to be identified in the given reaction.

    ${\text{O}}^{\text{2-}}\text{(aq)}+{\text{H}}_{\text{2}}\text{O(l)}\to 2{\text{OH}}^{-}\text{(aq)}$

Concept Introduction:

Refer part (a).