Explanation The mixture that is given is said to contain KBr and K 2 S . The mass of mixture is 6 .14 g . Molar mass of the individual components is calculated as follows; Molar mass of KBr : Molar mass = 1 × ( 39.09 g ⋅ mol − 1 ) + 1 × ( 79.904 g ⋅ mol − 1 ) = 39.09 g ⋅ mol − 1 + 79.904 g ⋅ mol − 1 = 118.994 g ⋅ mol − 1 Molar mass of K 2 S : Molar mass = 2 × ( 39.09 g ⋅ mol − 1 ) + 1 × ( 32.06 g ⋅ mol − 1 ) = 78.18 g ⋅ mol − 1 + 32.06 g ⋅ mol − 1 = 110.24 g ⋅ mol − 1 Mass percentage of potassium in individual component in the mixture is calculated as shown below; Mass percentage of K in KBr : Mass percentage = Mass of K atom in 1 mol of KBr molar mass of KBr × 100 = 39.09 g ⋅ mol − 1 118.994 g ⋅ mol − 1 × 100 = 32.85 % Mass percentage of K in K 2 S : Mass percentage = Mass of K atom in 1 mol of K 2 S molar mass of K 2 S × 100 = 2 ( 39.09 g ⋅ mol − 1 ) 110.24 g ⋅ mol − 1 × 100 = 70.91 % The total mass of the mixture is given as 6 .14 g . Let the mass of KBr be considered as x g

Chemical Principles: The Quest for Insight

7th Edition

ISBN: 9781464183959

Author: Peter Atkins, Loretta Jones, Leroy Laverman

Publisher: W. H. Freeman

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Chapter F, Problem F.28E

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Percentage by mass of KBr in the mixture has to be calculated.

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Chapter F, Problem F.27E

Chapter F, Problem G.1AST

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Chemical Principles: The Quest for Insight

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Percentage by mass of KBr in the mixture has to be calculated.

Solution Summary: The author calculates the mass percentage of KBr in the mixture. The mass of the individual components is calculated as follows.

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Interpretation: Percentage by mass of KBr in the mixture has to be calculated.

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Chapter F Solutions

Interpretation:

Percentage by mass of KBr in the mixture has to be calculated.