Chapter F, Problem G.10E

(a)

Interpretation Introduction

Interpretation:

Mass of ${\text{K}}_{\text{2}}{\text{SO}}_{\text{4}}$ that is required to prepare a $\text{0}\text{.125}\text{M}$ solution of $\text{1}\text{.00}\text{L}$ has to be calculated.

Concept Introduction:

Molarity of the solution is defined as the number of moles of solute that is dissolved in the volume of solution in liters.  Unit of molarity is $\text{mol}\cdot {\text{L}}^{-1}$.  The equation for molarity is given as follows;

    $\text{Molarity (M)}=\frac{\text{Amount of solute in moles}}{\text{Volume of solution in liters}}$

Molar concentration of solute is used for calculating the amount of solute in solution as given below;

    $n=c\times V$

The equation to calculated the mass of solute dissolved in solution is given as follows;

    $m=cMV$

Where,

    $m$ is the mass of solute.

    $c$ is the concentration of solution.

    $M$ is the molar mass of solute.

    $V$ is the volume of solution.

(b)

Interpretation Introduction

Interpretation:

Mass of $\text{NaF}$ that is required to prepare a $\text{0}\text{.015}\text{M}$ solution of $\text{375}\text{mL}$ has to be calculated.

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

Mass of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ that is required to prepare a $\text{0}\text{.35}\text{M}$ solution of $\text{500}\text{mL}$ has to be calculated.

Concept Introduction:

Refer part (a).