Explanation Given molecule is Testosterone. The molecular formula of Testosterone is C 19 H 28 O 2 . One mole of Testosterone molecule contains nineteen moles of carbon, twenty eight moles of hydrogen, and two moles of oxygen atom. Molar mass of Testosterone is calculated as follows; Molar mass of testosterone = 19 × M(C) + 28 × M(H) + 2 × M(O) = ( 19 × 12.01 g ⋅ mol − 1 ) + ( 28 × 1.008 g ⋅ mol − 1 ) + ( 2 × 16.00 g ⋅ mol − 1 ) = 228.19 g ⋅ mol − 1 + 28.224 g ⋅ mol − 1 + 32.00 g ⋅ mol − 1 = 288.414 g ⋅ mol − 1 Mass of carbon, hydrogen, and oxygen present in Testosterone is calculated as shown below; Mass percentage of carbon: Mass percentage of carbon = mass of carbon atoms in Testosterone mass of Testosterone molecule × 100 % = 19 mol × 12.01 g ⋅ mol − 1 1 mol × 288

Chemical Principles: The Quest for Insight

7th Edition

ISBN: 9781464183959

Author: Peter Atkins, Loretta Jones, Leroy Laverman

Publisher: W. H. Freeman

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Chapter F, Problem F.6E

Interpretation Introduction

Interpretation:

Mass percentage of composition of Testosterone has to be calculated.

Concept Introduction:

Mass percentage composition of the individual elements can be calculated if the formula of the compound containing the elements is known. Mass percentage of an element is calculated using the formula given below;

Mass percentage of element=mass of element in sampletotal mass of sample×100%

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Chapter F, Problem F.5E

Chapter F, Problem F.7E

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Chemical Principles: The Quest for Insight

Ch. F - Prob. A.1AST Ch. F - Prob. A.1BST Ch. F - Prob. A.2AST Ch. F - Prob. A.2BST Ch. F - Prob. A.3AST Ch. F - Prob. A.3BST Ch. F - Prob. A.4AST Ch. F - Prob. A.4BST Ch. F - Prob. A.5AST Ch. F - Prob. A.5BST

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