Chapter F, Problem G.2AST

Interpretation Introduction

Interpretation:

Mass of glucose that is required to prepare a $\text{0}\text{.442}\text{M}$ solution of $\text{150}\text{mL}$ has to be calculated.

Concept Introduction:

Molarity of the solution is defined as the number of moles of solute that is dissolved in the volume of solution in liters.  Unit of molarity is $\text{mol}\cdot {\text{L}}^{-1}$.  The equation for molarity is given as follows;

    $\text{Molarity (M)}=\frac{\text{Amount of solute in moles}}{\text{Volume of solution in liters}}$

Molar concentration of solute is used for calculating the amount of solute in solution as given below;

    $n=c\times V$

The equation to calculated the mass of solute dissolved in solution is given as follows;

    $m=cMV$

Where,

    $m$ is the mass of solute.

    $c$ is the concentration of solution.

    $M$ is the molar mass of solute.

    $V$ is the volume of solution.