Chapter 3, Problem 26RE

To determine

Given quadratic function has a maximum value or minimum value.

Answer to Problem 26RE

Minimum value is $y=-3$ when $x=-2$ .

Explanation of Solution

Given information:

  $f\left(x\right)=2x^2+8x+5$

Calculation:

Given equation is,

  $f\left(x\right)=2x^2+8x+5$

Here,

  $\begin{array}{l}\frac{-b}{2a}=2x^2+8x+5\\ 2{\left(-2\right)}^2+8\left(-2\right)+5\\ 2.4-16+5\\ -8+5=-3\end{array}$

Thus, minimum value is $y=-3$ when $x=-2$ .