Chapter 3.5, Problem 10AYU

$x^2\text{ + 8}x\text{ > 0}$

To determine

To find: The solution of the inequality $x^2+8x>0$.

Answer to Problem 10AYU

Solution:

$x>0$ or $x<-8$

Explanation of Solution

Given:

The inequality is

$x^2+8x>0$

Calculation:

$x^2+8x>0$

$x\left(x+8\right)>0$

$x>0$ or $x<-8$

Therefore the solution to the given inequality is $x>0$ or $x<-8$.