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(a)
To find: the horizontal distance from the face of the cliff
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 11AYU
Therefore, the height of the projectile will be the maximum at a horizontal distance of
Explanation of Solution
Given:
Calculation:
Simplify the function for the height of the projectile.
Compare
Since
Thus,
Therefore, the height of the projectile will be the maximum at a horizontal distance of
Conclusion:
Therefore, the height of the projectile will be the maximum at a horizontal distance of
(b)
To find: the maximum height of the projectile.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 11AYU
Therefore, the maximum height of the projectile is
Explanation of Solution
Calculation:
Substitute
Simplify by multiplying the numerator and the denominator by the least common multiple of the denominators, 32
Therefore, the maximum height of the projectile is
Conclusion:
Therefore, the maximum height of the projectile is
(c)
To find:horizontal distancethat the projectile will strike the water
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 11AYU
Therefore, the projectile will strike the water at a horizontal distance of
Explanation of Solution
Calculation:
When the projectile strikes the water, the height will be 0 .
Thus,
The equation is in the form of the standard quadratic equation.
Find
Find the value of
Since the distance cannot be negative, discard -91.8
Therefore, the projectile will strike the water at a horizontal distance of
Conclusion:
Therefore, the projectile will strike the water at a horizontal distance of
(d)
To graph: graph the function by using a graphing utility
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 11AYU
Explanation of Solution
Calculation:
Following is the graph of the function
Conclusion:
Thus, the required graph is drawn.
(e)
To verify: the solutions found in parts (b) and (c).
(e)
![Check Mark](/static/check-mark.png)
Answer to Problem 11AYU
From the graph also the maximum height of the projectile is
Explanation of Solution
Calculation:
Following is the graph of the function
From the graph also the maximum height of the projectile is
Conclusion:
From the graph also the maximum height of the projectile is
(f)
To find:the distance of the projectile from the cliff
(f)
![Check Mark](/static/check-mark.png)
Answer to Problem 11AYU
Therefore, when the height of the projectile is
Explanation of Solution
Calculation:
Substitute
Swap the sides of the equation.
Subtract 100 from both the sides.
Compare the equation with the standard form of the quadratic equation.
Find
Find the value of
or -57.57
Since the distance cannot be negative, discard -57.57
Therefore, when the height of the projectile is
Conclusion:
Therefore, when the height of the projectile is
Chapter 3 Solutions
Precalculus
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