Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 21, Problem 94A

(a)

Interpretation Introduction

Interpretation:

The structure of 3, 5-dimethylnonane needs to be drawn and the number of possible stereoisomers should be determined.

Concept introduction:

The molecules having same molecular formula and connectivity but differ in spatial arrangements of atoms in the molecule are said to be stereoisomers of each other.

(a)

Expert Solution
Check Mark

Answer to Problem 94A

The structure of the compound is:

Chemistry: Matter and Change, Chapter 21, Problem 94A , additional homework tip  1

The compound 3, 5-dimethylnonane has 22 = 4 stereoisomers.

Explanation of Solution

A molecule is said to be chiral molecule when all the attached groups to central carbon atom are different and lacks in plane of symmetry in the molecule. The molecules having chiral centres show optical isomerism (one form of stereoisomer) as there are two mirror image representations possible for a molecule having chiral center in its structure and if the mirror images are non-superimposable to each other then, they are said to be optical isomers.

The given name of the compound is 3, 5-dimethylnonane which represents a parent chain of 9 carbon atoms having two methyl substituents at position 3 and 5 so, the structure of the compound will be:

Chemistry: Matter and Change, Chapter 21, Problem 94A , additional homework tip  2

The number of chiral carbons in the compound is shown “*” as they are attached by 4 different atoms/groups:

Chemistry: Matter and Change, Chapter 21, Problem 94A , additional homework tip  3

The square represents 4 different atoms and groups for first chiral carbon and oval represents 4 different atoms and groups for second chiral carbon. Hence, the total number of chiral carbons is 2.

Now, for each chiral carbon in a compound, the total number possible isomer for the compound is 2n where n represents number of chiral carbons so, the compound 3, 5-dimethylnonane has 22 = 4 stereoisomers.

(b)

Interpretation Introduction

Interpretation:

The structure of 3, 7-dimethyl-5-ethyldecane needs to be drawn and the number of possible stereoisomers should be determined.

Concept introduction:

The molecules having same molecular formula and connectivity but differ in spatial arrangements of atoms in the molecule are said to be stereoisomers of each other.

(b)

Expert Solution
Check Mark

Answer to Problem 94A

The structure of the compound is:

Chemistry: Matter and Change, Chapter 21, Problem 94A , additional homework tip  4

The compound 3, 7-dimethyl-5-ethyldecane has 23 = 8 stereoisomers.

Explanation of Solution

The given name of the compound is 3, 7-dimethyl-5-ethyldecane which represents a parent chain of 10 carbon atoms having two methyl and one ethyl substituents at position 3, 7 and 5 respectively so, the structure of the compound will be:

Chemistry: Matter and Change, Chapter 21, Problem 94A , additional homework tip  5

The number of chiral carbons in the compound is shown “*” as they are attached by 4 different atoms/groups:

Chemistry: Matter and Change, Chapter 21, Problem 94A , additional homework tip  6

The square represents 4 different atoms and groups for first chiral carbon and oval in red and black color represents 4 different atoms and groups for second and third chiral carbon respectively. Hence, the total number of chiral carbons is 3.

Now, for each chiral carbon in a compound, the total number possible isomer for the compound is 2n where n represents number of chiral carbons so, the compound 3, 7-dimethyl-5-ethyldecane has 23 = 8 stereoisomers.

Chapter 21 Solutions

Chemistry: Matter and Change

Ch. 21.2 - Prob. 11PPCh. 21.2 - Prob. 12SSCCh. 21.2 - Prob. 13SSCCh. 21.2 - Prob. 14SSCCh. 21.2 - Prob. 15SSCCh. 21.2 - Prob. 16SSCCh. 21.3 - Prob. 17PPCh. 21.3 - Prob. 18PPCh. 21.3 - Prob. 19SSCCh. 21.3 - Prob. 20SSCCh. 21.3 - Prob. 21SSCCh. 21.3 - Prob. 22SSCCh. 21.3 - Prob. 23SSCCh. 21.3 - Prob. 24SSCCh. 21.4 - Prob. 25SSCCh. 21.4 - Prob. 26SSCCh. 21.4 - Prob. 27SSCCh. 21.4 - Prob. 28SSCCh. 21.4 - Prob. 29SSCCh. 21.4 - Prob. 30SSCCh. 21.5 - Prob. 31PPCh. 21.5 - Prob. 32PPCh. 21.5 - Prob. 33SSCCh. 21.5 - Prob. 34SSCCh. 21.5 - Prob. 35SSCCh. 21.5 - Prob. 36SSCCh. 21.5 - Prob. 37SSCCh. 21 - Prob. 38ACh. 21 - Prob. 39ACh. 21 - Prob. 40ACh. 21 - Prob. 41ACh. 21 - Prob. 42ACh. 21 - Prob. 43ACh. 21 - Prob. 44ACh. 21 - Prob. 45ACh. 21 - Prob. 46ACh. 21 - Prob. 47ACh. 21 - Prob. 48ACh. 21 - Prob. 49ACh. 21 - Prob. 50ACh. 21 - Prob. 51ACh. 21 - Prob. 52ACh. 21 - How does the structure of a cycloalkane differ...Ch. 21 - Prob. 54ACh. 21 - Prob. 55ACh. 21 - Prob. 56ACh. 21 - Prob. 57ACh. 21 - Prob. 58ACh. 21 - Prob. 59ACh. 21 - Prob. 60ACh. 21 - Prob. 61ACh. 21 - Prob. 62ACh. 21 - Prob. 63ACh. 21 - Prob. 64ACh. 21 - Prob. 65ACh. 21 - Prob. 66ACh. 21 - Prob. 67ACh. 21 - Prob. 68ACh. 21 - Prob. 69ACh. 21 - Prob. 70ACh. 21 - Prob. 71ACh. 21 - Prob. 72ACh. 21 - Prob. 73ACh. 21 - Prob. 74ACh. 21 - Prob. 75ACh. 21 - Prob. 76ACh. 21 - Prob. 77ACh. 21 - Prob. 78ACh. 21 - Prob. 79ACh. 21 - Prob. 80ACh. 21 - Prob. 81ACh. 21 - Prob. 82ACh. 21 - Prob. 83ACh. 21 - Prob. 84ACh. 21 - Prob. 85ACh. 21 - Prob. 86ACh. 21 - Prob. 87ACh. 21 - Prob. 88ACh. 21 - Prob. 89ACh. 21 - Prob. 90ACh. 21 - Prob. 91ACh. 21 - Prob. 92ACh. 21 - Prob. 93ACh. 21 - Prob. 94ACh. 21 - Prob. 95ACh. 21 - Prob. 96ACh. 21 - Prob. 97ACh. 21 - Prob. 98ACh. 21 - Prob. 99ACh. 21 - Prob. 100ACh. 21 - Prob. 101ACh. 21 - Prob. 1STPCh. 21 - Prob. 2STPCh. 21 - Prob. 3STPCh. 21 - Prob. 4STPCh. 21 - Prob. 5STPCh. 21 - Prob. 6STPCh. 21 - Prob. 7STPCh. 21 - Prob. 8STPCh. 21 - Prob. 9STPCh. 21 - Prob. 10STPCh. 21 - Prob. 11STPCh. 21 - Prob. 12STPCh. 21 - Prob. 13STPCh. 21 - Prob. 14STPCh. 21 - Prob. 15STPCh. 21 - Prob. 16STPCh. 21 - Prob. 17STP
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