Chapter 21.4, Problem 25SSC

Interpretation Introduction

Interpretation:

The structural isomers of the alkane ${\text{C}}_{\text{6}}{\text{H}}_{\text{14}}$ should be drawn.

Concept introduction:

The molecules having same molecular formula but structural arrangement of atoms in the molecule is different are said to be isomers of each other.

Answer to Problem 25SSC

Isomer I:

Isomer II:

Isomer III:

Isomer IV:

Isomer V:

Explanation of Solution

1. All six-carbon atoms are written in a straight chain.

Isomer I:



2. Making a five-carbon atoms straight chain and bonding the sixth carbon-atom to the C atom of straight chain:

For isomer II the sixth carbon atom is bonded to second carbon of the chain.

Isomer II:



For isomer III the sixth carbon atom is bonded to third carbon of the chain.

Isomer III:



3. Making a four-carbon atoms straight chain and bonding the fifth and sixth carbon-atom to the C atom of straight chain:

For isomer IV the fifth and sixth carbon atoms are attached to second and third carbon atom of the chain.

Isomer IV:

For isomer V the fifth and sixth carbon atoms are attached to second carbon atom of the chain.

Isomer V: