Interpretation:
The values of k should be calculated for the reaction.
Concept introduction:
Rate Law can be expressed as an integrated rate law and a differential rate law.
Differential Rate Law: This describes the change in the concentrations of reactant as a function of time.
Integrated Rate Law: This describes the initial concentrations and the measured concentration of one or more reactants as a function of time.
The proportionality coefficient which relates the
Answer to Problem 14STP
The value of rate constant is equal to
Explanation of Solution
Given information:
Data is given as:
Initial rate ( |
||
0.10 M | 0.10 M | |
0.30 M | 0.10 M | |
0.30 M | 0.20 M |
The general expression of rate law is expressed as:
Where, m and n are the experimentally determined values.
Experiment 1:
Rate law expression is written as:
Experiment 2:
Rate law expression is written as:
Experiment 3:
Rate law expression is written as:
Now, divide equation (2) by (1):
Now, divide equation (3) by (2):
Thus, rate law expression is written as:
Now,
For experiment 1:
Rate = 7.93
Put the values, in rate law expression:
Thus, value of rate constant is equal to
Chapter 21 Solutions
Chemistry: Matter and Change
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