
(a)
Interpretation:
The mass of NaCl required to make 1 L of 0.50 M solution needs to be determined.
Concept Introduction :
0.50 M solution means there is 0.50 M of solute in 1L solution.
(a)

Answer to Problem 3E
29.25 g of NaCl will be required to make 1 L of 0.50 M solution.
Explanation of Solution
Molar mass of NaCl is 55.8 g/mol.
The number of moles can be converted to mass as follows:
I L must contain0.50 mole NaCl=
So 29.25 g NaCl is required to make 1 L of 0.50 M solution.
(b)
Interpretation:
The mass of CaCl2 required to make 1 L of 2.0 M solution needs to be determined.
Concept Introduction :
2. 0 M solution means there is 2. 0 mol of solute in 1L solution.
(b)

Answer to Problem 3E
222 g of CaCl2will be required to make 1 L of 2M solution.
Explanation of Solution
Molecular weight of CaCl2is 111 g/mol.
The number of moles can be converted to mass as follows:
1L must contain 2. 0 mole CaCl2
So 222 g CaCl2 is required to make 1 L of 2.0 M solution.
(c)
Interpretation:
The mass of NaOH required to make 1 L of 1.5 M solution needs to be determined.
Concept Introduction :
1.5 M solution means there is 1.5 mol of solute in 1L solution.
(c)

Answer to Problem 3E
60 g of NaOH will be required to make 1 L of 1.5 M solution.
Explanation of Solution
Molecular weight of NaOH is 40 g/mol
The number of moles can be converted to mass as follows:
1L must contain 1.5 mole NaOH =
So, 60 g NaOH is required to make 1 L of 1.5 M solution.
Chapter U4 Solutions
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