(a)
Interpretation: The molarity of the solution that is prepared by dissolving 7.30 g of NaCl to make 500 mL of the solution needs to be determined.
Concept Introduction: Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The relation between these values can be shown as:
The relation between concentration and moles is as given below;
(a)
Answer to Problem C15.7RE
Explanation of Solution
Mass of NaCl = 7.30 g
Volume of solution = 500 mL = 0.500 L
Molar mass of NaCl = 58.5 g/mol
Substitute the values to calculate the molarity:
(b)
Interpretation: The molarity of the solution that is prepared by dissolving 43.84 g of NaCl to make 1 L of the solution needs to be determined.
Concept Introduction: Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The relation between these values can be shown as:
The relation between concentration and moles is as given below;
(b)
Answer to Problem C15.7RE
Explanation of Solution
Mass of NaCl = 43.84 g
Volume of solution = 1.0 L
Molar mass of NaCl = 58.5 g/mol
Substitute the values to calculate the molarity:
(c)
Interpretation: The molarity of the solution that is prepared by dissolving 25.00 g of NaCl to make 1 L of the solution needs to be determined.
Concept Introduction: Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The relation between these values can be shown as:
The relation between concentration and moles is as given below;
(c)
Answer to Problem C15.7RE
Explanation of Solution
Mass of NaCl = 25.00 g
Volume of solution = 1.0 L
Molar mass of NaCl = 58.5 g/mol
Substitute the values to calculate the molarity:
(d)
Interpretation: The molarity of the solution that is prepared by dissolving 25.00 g of NaCl to make 2 L of the solution needs to be determined.
Concept Introduction: Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The relation between these values can be shown as:
The relation between concentration and moles is as given below;
(d)
Answer to Problem C15.7RE
Explanation of Solution
Mass of NaCl = 25.00 g
Volume of solution = 2.0 L
Molar mass of NaCl = 58.5 g/mol
Substitute the values to calculate the molarity:
Chapter U4 Solutions
Living by Chemistry
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