Chapter U4.75, Problem 7E

Interpretation Introduction

Interpretation:

The mass of red jelly beans required to fill a 500 g bag with twice as many red jelly beans as yellow needs to be calculated.

Concept Introduction:

Mass is a fundamental property of an object which is representative of the amount of matter present in that object.

For small objects where the mass cannot be measured on an individual level, an average mass can be deduced by weighing the collection of similar objects and dividing by the total count.

Answer to Problem 7E

Mass of red jelly beans = 333 g

Explanation of Solution

Given:

Total mass of red + yellow jelly beans = 500 g

Mass of one jelly bean (yellow or red) = 0.64 g

Calculation:

Let the mass of all yellow jelly beans = 'x' g

Since twice as many red jelly beans are required, the corresponding mass would be = '2x' g

  $\begin{array}{l}\text{x + 2x = 500 g}\\ \text{3x = 500}\\ \text{x = 500/3=166}\text{.67g}\\ \text{Therefore, }\\ \text{Mass of red jelly beans = 2x }\\ \text{= 2(166}\text{.67) =333}\text{.34 g}\end{array}$

Conclusion

The mass of red jelly beans required to fill a 500 g bag with twice as many red jelly beans as yellowis 333 g.