Interpretation: The given table needs to be completed for glucose.
Concept Introduction: The molarity of solution is defined as number of moles of solute in 1 L of the solution.
Here, n is number of moles and V is volume of solution in L.
The number of moles is calculated from mass and molar mass as follows:
Here, m is mass and M is molar mass.
Explanation of Solution
The given table is as follows:
According to the given table:
(1)
In
Thus, in
Molar mass of glucose is 180 g.
The number of moles can be calculated as follows:
Thus,
Therefore, molarity is 0.50 M
(2)
Now,
Thus,
Also,
Mass of
(3)
Thus,
Mass of
(4)
Thus,
Or,
Thus,
And,
1L solution contains
Thus, molarity of glucose is 0.01 M.
Therefore, the complete table will be as follows:
Molarity(moles/liter) | Volume(liters) | Number(moles of solute) | Molar mass of solute(grams/mole) | Mass of solute(grams) |
0.50 M | 2.0 L | 1 mol | 180 g/mol | 180 g |
0.40 M | 0.25 L | 0.10 mol | 180 g/mol | 18 g |
0.10 M | 0.3 L | 0.03 mol | 180 g/mol | 5.4 g |
0.01 | 100 mL=0.1 L | 0.001 mol | 180 g/mol | 0.180 g |
Chapter U4 Solutions
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