
Concept explainers
Interpretation:
The molarity of 45.0 g C12H22O11 dissolved in 250 mL of water needs to be determined.
Concept introduction:
The molar concentration of a solute in a solution can be expressed in terms of molarity as moles of solute present in per liter of solution. Mathematically,
Molarity = number of moles of soluteVolume of solution (L) - (1)

Answer to Problem 10STP
The molarity of 45.0 g C12H22O11 dissolved in 250 mL of water is 0.53 M.
Explanation of Solution
The formula to calculate number of moles is:
number of moles = mass of the substanceMolar mass of the substance
Now, equation (1) an be rewritten as:
Molarity = mass of the soluteMolar mass of the soluteVolume of solution (L) - (2)
The molar mass of sugar, C12H22O11 is 342.3 g/mol.
Converting the given volume of sample from mL to L as:
250 mL×1 L1000 mL= 0.25 L
Substituting the given values in equation (2) to determine the molarity of the solution as:
Molarity = 45 g342.3 g/mol0.25 LMolarity = 0.1315 mol0.25 LMolarity = 0.526 mol/L ≃ 0.53 M
Since, the molarity of 45.0 g C12H22O11 dissolved in 250 mL of water is 0.53 M so, the correct option is (a).
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