(a)
Interpretation: The steps to make 0.5 M solution of sodium hydroxide needs to be explained.
Concept Introduction: Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The relation between these values can be shown as:
(a)
Answer to Problem C15.5RE
- Take 19.9 g of solid NaOH solution.
- Measure 1 L of water with the help of measuring cylinder
- Add water in beaker containing 19.9 g of solid NaOH
- Stir the solution till complete NaOH dissolved in it.
Explanation of Solution
To make 0.5 M solution of NaOH; 0.5 M stands for 0.5 moles of NaOH dissolves in 1 L of water.
Molar mass of NaOH = 39.9 g/mol
Calculate the mass of NaOH required:
Thus to make 0.5 M solution of 1 L of NaOH:
- Take 19.9 g of solid NaOH.
- Measure 1 L of water with the help of measuring cylinder
- Add water in beaker containing 19.9 g of solid NaOH
- Stir the solution till complete NaOH dissolves in it.
(b)
Interpretation: The use of 1 L of water while making 0.5 M solution of sodium hydroxide needs to be explained.
Concept Introduction: The molecular mass of compound is the sum of
(b)
Answer to Problem C15.5RE
The volume of water depends on the volume of solution required. If less than 1 L volume of solution required, less volume of water and corresponding mass of NaOH can be used.
Explanation of Solution
To make 0.5 M solution of NaOH; 0.5 M stands for 0.5 moles of NaOH dissolves in 1 L of water. Thus to make 0.5 M solution of 1 L of NaOH take 19.9 g of solid NaOH and dissolve it in 1 L of water.
Thus the volume of water depends on the volume of solution required. If less than 1 L volume of solution required, less volume of water and mass of NaOH can be used.
Chapter U4 Solutions
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