The fate of the labeled carbon (at second position) of glucose in the pentose phosphate pathway. Introduction: Glucose is the primary source of energy in a cell, which undergoes glycolysis to produce energy in the form of ATP (adenosine triphosphate) in all the living organisms. However, it can also produce a precursor of nucleic acid or nucleotides by entering an alternate pathway celled pentose phosphate pathway (PPP). There is no ATP production in this pathway, instead reduced nicotinamide adenine dinucleotide phosphate(NADPH) and ribose-5-phosphate areproduced.

Question

Want to see the full answer?

Answer 1

Question

Chapter 8, Problem 72TQ

Summary Introduction

To review:

The fate of the labeled carbon (at second position) of glucose in the pentose phosphate pathway.

Introduction:

Glucose is the primary source of energy in a cell, which undergoes glycolysis to produce energy in the form of ATP (adenosine triphosphate) in all the living organisms. However, it can also produce a precursor of nucleic acid or nucleotides by entering an alternate pathway celled pentose phosphate pathway (PPP). There is no ATP production in this pathway, instead reduced nicotinamide adenine dinucleotide phosphate(NADPH) and ribose-5-phosphate areproduced.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

2. For the flow of fluid over a flat membrane of length 10cm, determine the length-average mass transfer coefficient. The relevant properties of the system are u=0.01cm²/s, D=5 x 106 cm²/s, and v = 5.0 cm/s.

Background Freezing isn't the only challenge in cryopreservation - thawing can be just as difficult. A microwave oven seems like a nice solution, since it deposits energy quickly and microwaves are non-ionizing radiation (they do not cause DNA mutation). However, water absorbs microwaves more effectively than ice does, meaning that the portion of an organ that has already melted will get warmer at a higher rate than the remaining ice – the opposite of what we want! - The transmission of radiation through a weakly absorbing material such as ice or water can be modeled by Beer's law, which assumes that the rate of absorption at a depth x is proportional to the local radiation intensity I(x) times an absorption coefficient, which is often written as μ or a or just µ). Noting that absorption decreases the intensity, we can write a differential equation a Solving the differential equation with the boundary condition on the surface being gives the relationship For a standard microwave oven…

3. Dry air is inhaled at a rate of 10 liter/min through a trachea with a diameter of 20 mm and a length of 125 mm. The inner surface of the trachea is at a normal body temperature of 37°C and may be assumed to be saturated with water. a. Assuming steady, fully developed flow in the trachea, estimate the mass transfer convection coefficient. b. Estimate the daily water loss (liter/day) associated with evaporation in the trachea.